如何在React.js中执行debounce ?

我想撤消handleOnChange。

我尝试debounce(这。handleOnChange, 200)但它不起作用。

function debounce(fn, delay) {
  var timer = null;
  return function() {
    var context = this,
      args = arguments;
    clearTimeout(timer);
    timer = setTimeout(function() {
      fn.apply(context, args);
    }, delay);
  };
}

var SearchBox = React.createClass({
  render: function() {
    return <input type="search" name="p" onChange={this.handleOnChange} />;
  },

  handleOnChange: function(event) {
    // make ajax call
  }
});

当前回答

如果你不喜欢添加lodash或任何其他包:

import React, { useState, useRef } from "react";

function DebouncedInput() {
  const [isRefetching, setIsRefetching] = useState(false);
  const [searchTerm, setSearchTerm] = useState("");
  const previousSearchTermRef = useRef("");

  function setDebouncedSearchTerm(value) {
    setIsRefetching(true);
    setSearchTerm(value);
    previousSearchTermRef.current = value;
    setTimeout(async () => {
      if (previousSearchTermRef.current === value) {
        try {
          // await refetch();
        } finally {
          setIsRefetching(false);
        }
      }
    }, 500);
  }

  return (
    <input
      value={searchTerm}
      onChange={(event) => setDebouncedSearchTerm(event.target.value)}
    />
  );
}

其他回答

2022 -使用useEffect钩子

此时最好的选择是使用useEffect钩子。useEffect允许您设置一个函数,该函数可以修改状态以响应某些异步事件。debounging是异步的,因此useEffect可以很好地用于此目的。

如果从钩子返回一个函数,返回的函数将在钩子再次被调用之前被调用。这让您可以取消之前的超时,有效地解除函数。

例子

这里我们有两个状态,value和tempValue。设置tempValue将触发useEffect钩子,该钩子将启动一个1000ms超时,该超时将调用一个函数将tempValue复制为value。

钩子返回一个取消定时器设置的函数。当钩子再次被调用时(即按下另一个键),超时被取消并重置。

const DebounceDemo = () => {
  const [value, setValue] = useState();
  const [tempValue, setTempValue] = useState();

  // This hook will set a 1000 ms timer to copy tempValue into value
  // If the hook is called again, the timer will be cancelled
  // This creates a debounce
  useEffect(
    () => {
      // Wait 1000ms before copying the value of tempValue into value;
      const timeout = setTimeout(() => {
        setValue(tempValue);
      }, 1000);

      // If the hook is called again, cancel the previous timeout
      // This creates a debounce instead of a delay
      return () => clearTimeout(timeout);
    },
    // Run the hook every time the user makes a keystroke
    [tempValue]
  )

  // Here we create an input to set tempValue. 
  // value will be updated 1000 ms after the hook is last called, 
  // i.e after the last user keystroke.
  return (
    <>
      <input 
        onChange={
          ({ target }) => setTempValue(target.value)
        }
      />
      <p>{ value }</p>
    </>
  )
}

有点晚了,但应该有帮助。 创建这个类(它是用typescript写的,但是很容易转换成javascript)

export class debouncedMethod<T>{
  constructor(method:T, debounceTime:number){
    this._method = method;
    this._debounceTime = debounceTime;
  }
  private _method:T;
  private _timeout:number;
  private _debounceTime:number;
  public invoke:T = ((...args:any[])=>{
    this._timeout && window.clearTimeout(this._timeout);
    this._timeout = window.setTimeout(()=>{
      (this._method as any)(...args);
    },this._debounceTime);
  }) as any;
}

要使用

var foo = new debouncedMethod((name,age)=>{
 console.log(name,age);
},500);
foo.invoke("john",31);

I was searching for a solution to the same problem and came across this thread as well as some others but they had the same problem: if you are trying to do a handleOnChange function and you need the value from an event target, you will get cannot read property value of null or some such error. In my case, I also needed to preserve the context of this inside the debounced function since I'm executing a fluxible action. Here's my solution, it works well for my use case so I'm leaving it here in case anyone comes across this thread:

// at top of file:
var myAction = require('../actions/someAction');

// inside React.createClass({...});

handleOnChange: function (event) {
    var value = event.target.value;
    var doAction = _.curry(this.context.executeAction, 2);

    // only one parameter gets passed into the curried function,
    // so the function passed as the first parameter to _.curry()
    // will not be executed until the second parameter is passed
    // which happens in the next function that is wrapped in _.debounce()
    debouncedOnChange(doAction(myAction), value);
},

debouncedOnChange: _.debounce(function(action, value) {
    action(value);
}, 300)

如果我们有兴趣在react.js中使用epic.js,我们可以在epic.js库中使用debounceTime rxjs/操作符。因此,我们可以在epic.js的帮助下,在react.js中使用可观察对象,而不是使用回调。

不受控制的组件

你可以使用event.persist()方法。

下面是一个使用下划线_.debounce()的例子:

var SearchBox = React.createClass({

  componentWillMount: function () {
     this.delayedCallback = _.debounce(function (event) {
       // `event.target` is accessible now
     }, 1000);
  },

  onChange: function (event) {
    event.persist();
    this.delayedCallback(event);
  },

  render: function () {
    return (
      <input type="search" onChange={this.onChange} />
    );
  }

});

编辑:请看这个JSFiddle


控制组件

更新:上面的例子显示了一个不受控制的组件。我一直在使用受控元素,这里是上面的另一个例子,但没有使用event.persist()“欺骗”。

JSFiddle也是可用的。不带下划线的示例

var SearchBox = React.createClass({
    getInitialState: function () {
        return {
            query: this.props.query
        };
    },

    componentWillMount: function () {
       this.handleSearchDebounced = _.debounce(function () {
           this.props.handleSearch.apply(this, [this.state.query]);
       }, 500);
    },

    onChange: function (event) {
      this.setState({query: event.target.value});
      this.handleSearchDebounced();
    },

    render: function () {
      return (
        <input type="search"
               value={this.state.query}
               onChange={this.onChange} />
      );
    }
});


var Search = React.createClass({
    getInitialState: function () {
        return {
            result: this.props.query
        };
    },

    handleSearch: function (query) {
        this.setState({result: query});
    },

    render: function () {
      return (
        <div id="search">
          <SearchBox query={this.state.result}
                     handleSearch={this.handleSearch} />
          <p>You searched for: <strong>{this.state.result}</strong></p>
        </div>
      );
    }
});

React.render(<Search query="Initial query" />, document.body);

编辑:更新示例和JSFiddles到React 0.12

编辑:更新的例子,以解决Sebastien Lorber提出的问题

编辑:更新的jsfiddle不使用下划线和使用纯javascript debounce。