我在看Pluralsight关于React的课程,老师说道具不应该被改变。我现在正在读一篇关于道具vs.国家的文章(uberVU/react-guide),它说

道具和状态更改都会触发呈现更新。

文章后面说:

Props(属性的缩写)是组件的配置,如果可以的话,是它的选项。它们是从上面接收的,是不可变的。

所以道具可以改变,但它们应该是不可变的? 什么时候应该使用道具,什么时候应该使用状态? 如果你有一个React组件需要的数据,它应该通过道具或设置在React组件通过getInitialState?


当前回答

State是你的数据,是可变的,你可以对它做任何你需要的事情,props是只读数据,通常当你传递props时,你已经使用了你的数据,你需要子组件来渲染它,或者如果你的props是一个函数,你调用它来执行任务

其他回答

一般来说,一个组件(父组件)的状态是子组件的prop。

State resides within a component where as props are passed from parent to child. Props are generally immutable. class Parent extends React.Component { constructor() { super(); this.state = { name : "John", } } render() { return ( <Child name={this.state.name}> ) } } class Child extends React.Component { constructor() { super(); } render() { return( {this.props.name} ) } }

在上面的代码中,我们有一个父类(parent),它的状态是name,它被传递给子组件(子类)作为道具,子组件使用{this.props.name}渲染它。

Basically, props and state are two ways the component can know what and how to render. Which part of the application state belongs to state and which to some top-level store, is more related to your app design, than to how React works. The simplest way to decide, IMO, is to think, whether this particular piece of data is useful for application as a whole, or it's some local information. Also, it's important to not duplicate state, so if some piece of data can be calculated from props - it should calculated from props.

For example, let's say you have some dropdown control (which wraps standart HTML select for custom styling), which can a) select some value from list, and b) be opened or closed (i.e., the options list displayed or hidden). Now, let's say your app displays a list of items of some sort and your dropdown controls filter for list entries. Then, it would be best to pass active filter value as a prop, and keep opened/closed state local. Also, to make it functional, you would pass an onChange handler from parent component, which would be called inside dropdown element and send updated information (new selected filter) to the store immediately. On the other hand, opened/closed state can be kept inside dropdown component, because the rest of the application doesn't really care if the control is opened, until user actually changes it value.

下面的代码是不完全工作,它需要css和处理下拉单击/模糊/改变事件,但我想保持示例最小。希望这有助于理解其中的区别。

const _store = {
    items: [
    { id: 1, label: 'One' },
    { id: 2, label: 'Two' },
    { id: 3, label: 'Three', new: true },
    { id: 4, label: 'Four', new: true },
    { id: 5, label: 'Five', important: true },
    { id: 6, label: 'Six' },
    { id: 7, label: 'Seven', important: true },
    ],
  activeFilter: 'important',
  possibleFilters: [
    { key: 'all', label: 'All' },
    { key: 'new', label: 'New' },
    { key: 'important', label: 'Important' }
  ]
}

function getFilteredItems(items, filter) {
    switch (filter) {
    case 'all':
        return items;

    case 'new':
        return items.filter(function(item) { return Boolean(item.new); });

    case 'important':
        return items.filter(function(item) { return Boolean(item.important); });

    default:
        return items;
  }
}

const App = React.createClass({
  render: function() {
    return (
            <div>
            My list:

            <ItemList   items={this.props.listItems} />
          <div>
            <Dropdown 
              onFilterChange={function(e) {
                _store.activeFilter = e.currentTarget.value;
                console.log(_store); // in real life, some action would be dispatched here
              }}
              filterOptions={this.props.filterOptions}
              value={this.props.activeFilter}
              />
          </div>
        </div>
      );
  }
});

const ItemList = React.createClass({
  render: function() {
    return (
      <div>
        {this.props.items.map(function(item) {
          return <div key={item.id}>{item.id}: {item.label}</div>;
        })}
      </div>
    );
  }
});

const Dropdown = React.createClass({
    getInitialState: function() {
    return {
        isOpen: false
    };
  },

  render: function() {
    return (
        <div>
            <select 
            className="hidden-select" 
          onChange={this.props.onFilterChange}
          value={this.props.value}>
            {this.props.filterOptions.map(function(option) {
            return <option value={option.key} key={option.key}>{option.label}</option>
          })}
        </select>

        <div className={'custom-select' + (this.state.isOpen ? ' open' : '')} onClick={this.onClick}>
            <div className="selected-value">{this.props.activeFilter}</div>
          {this.props.filterOptions.map(function(option) {
            return <div data-value={option.key} key={option.key}>{option.label}</div>
          })}
        </div>
      </div>
    );
  },

  onClick: function(e) {
    this.setState({
        isOpen: !this.state.isOpen
    });
  }
});

ReactDOM.render(
  <App 
    listItems={getFilteredItems(_store.items, _store.activeFilter)} 
    filterOptions={_store.possibleFilters}
    activeFilter={_store.activeFilter}
    />,
  document.getElementById('root')
);

道具和状态之间的关键区别在于,状态是内部的,由组件本身控制,而道具是外部的,由呈现组件的任何东西控制。

状态是真相的起源,是您的数据存在的地方。 你可以说这种状态是通过道具表现出来的。

为组件提供支持可以使UI与数据保持同步。 组件实际上只是一个返回标记的函数。

给定相同的道具(用于显示的数据),它将始终生成相同的标记。

所以这些道具就像是将数据从原点传递到功能组件的管道。

react中的state和props都用于将数据控制到组件中,通常props由父组件设置并传递给子组件,并且它们在整个组件中都是固定的。对于将要改变的数据,我们必须使用状态。道具是不可变的,而状态是可变的,如果你想改变道具,你可以从父组件做,然后传递给子组件。