我试着:
somearray = ["some", "thing"]
anotherarray = ["another", "thing"]
somearray.push(anotherarray.flatten!)
我预期的
["some", "thing", "another", "thing"]
但有
["some", "thing", nil]
当前回答
(array1 + array2).uniq
这样你就可以先得到array1元素。你不会得到副本。
其他回答
你可以使用+运算符!
irb(main):001:0> a = [1,2]
=> [1, 2]
irb(main):002:0> b = [3,4]
=> [3, 4]
irb(main):003:0> a + b
=> [1, 2, 3, 4]
你可以在这里阅读关于数组类的所有内容: http://ruby-doc.org/core/classes/Array.html
这里有两种方法，注意在这个例子中，第一种方法分配一个新数组(转换为somearray = somearray + anotherarray)
somearray = ["some", "thing"]
anotherarray = ["another", "thing"]
somearray += anotherarray # => ["some", "thing", "another", "thing"]
somearray = ["some", "thing"]
somearray.concat anotherarray # => ["some", "thing", "another", "thing"]
适用于Ruby版本>= 2.0但不适用于旧版本的简单方法:
irb(main):001:0> a=[1,2]
=> [1, 2]
irb(main):003:0> b=[3,4]
=> [3, 4]
irb(main):002:0> c=[5,6]
=> [5, 6]
irb(main):004:0> [*a,*b,*c]
=> [1, 2, 3, 4, 5, 6]
a = ['a', 'b']
b = ['c', 'd']
arr = [a, b].flatten
这不会去除dups，但是
a|b
删除重复。
["some", "thing"] + ["another", "thing"]
