是否有一种方法可以确定一个方法需要执行多少时间(以毫秒为单位)?


当前回答

这里有另一种方法,在Swift中,使用defer关键字来做到这一点

func methodName() {
  let methodStart = Date()
  defer {
    let executionTime = Date().timeIntervalSince(methodStart)
    print("Execution time: \(executionTime)")
  }
  // do your stuff here
}

来自苹果的文档:defer语句用于在将程序控制权转移到该defer语句出现的范围之外之前执行代码。

这类似于try/finally块,优点是将相关代码分组。

其他回答

我在我的utils库中使用这个(Swift 4.2):

public class PrintTimer {
    let start = Date()
    let name: String

    public init(file: String=#file, line: Int=#line, function: String=#function, name: String?=nil) {
        let file = file.split(separator: "/").last!
        self.name = name ?? "\(file):\(line) - \(function)"
    }

    public func done() {
        let end = Date()
        print("\(self.name) took \((end.timeIntervalSinceReferenceDate - self.start.timeIntervalSinceReferenceDate).roundToSigFigs(5)) s.")
    }
}

…然后调用如下方法:

func myFunctionCall() {
    let timer = PrintTimer()
    // ...
    timer.done()
}

…运行后在控制台中看起来是这样的:

MyFile.swift:225 - myFunctionCall() took 1.8623 s.

虽然不像上面的TICK/TOCK那样简洁,但它足以清楚地看到它在做什么,并自动包括正在计时的内容(通过文件、方法开头的行和函数名)。显然,如果我想要更多的细节(例如,如果我不只是计时一个方法调用,因为是通常的情况下,而是在该方法内计时块),我可以在PrintTimer init上添加“name="Foo""参数来命名它除了默认值之外的东西。

下面是我使用的两个单行宏:

#define TICK   NSDate *startTime = [NSDate date]
#define TOCK   NSLog(@"Time: %f", -[startTime timeIntervalSinceNow])

像这样使用它:

TICK;

/* ... Do Some Work Here ... */

TOCK;
struct TIME {

    static var ti = mach_timebase_info()
    static var k: Double = 1
    static var mach_stamp: Double {

        if ti.denom == 0 {
            mach_timebase_info(&ti)
            k = Double(ti.numer) / Double(ti.denom) * 1e-6
        }
        return Double(mach_absolute_time()) * k
    }
    static var stamp: Double { return NSDate.timeIntervalSinceReferenceDate() * 1000 }
}

do {
    let mach_start = TIME.mach_stamp
    usleep(200000)
    let mach_diff = TIME.mach_stamp - mach_start

    let start = TIME.stamp
    usleep(200000)
    let diff = TIME.stamp - start

    print(mach_diff, diff)
}

我用这个:

clock_t start, end;
double elapsed;
start = clock();

//Start code to time

//End code to time

end = clock();
elapsed = ((double) (end - start)) / CLOCKS_PER_SEC;
NSLog(@"Time: %f",elapsed);

但我不确定iPhone上的CLOCKS_PER_SEC。你还是别打了吧。

这里有一个Swift 3的解决方案,可以在任何地方对代码进行等分,以找到长时间运行的进程。

var increment: Int = 0

var incrementTime = NSDate()

struct Instrumentation {
    var title: String
    var point: Int
    var elapsedTime: Double

    init(_ title: String, _ point: Int, _ elapsedTime: Double) {
        self.title = title
        self.point = point
        self.elapsedTime = elapsedTime
    }
}

var elapsedTimes = [Instrumentation]()

func instrument(_ title: String) {
    increment += 1
    let incrementedTime = -incrementTime.timeIntervalSinceNow
    let newPoint = Instrumentation(title, increment, incrementedTime)
    elapsedTimes.append(newPoint)
    incrementTime = NSDate()
}

用法:-

instrument("View Did Appear")

print("ELAPSED TIMES \(elapsedTimes)")

样例输出:

[MyApp.SomeViewController.]仪器仪表(标题:“开始视图 Did Load", point: 1, elapsedTime: 0.040504038333892822), MyApp.SomeViewController。检测(标题:“完成添加 SubViews", point: 2, elapsedTime: 0.010585010051727295), MyApp.SomeViewController。仪器仪表(标题:“视图已出现”, 点:3,elapsedTime: 0.56564098596572876)]