public Deck(IEnumerable<Card> initialCards) 
    {
    cards = new List<Card>(initialCards);
    public void Shuffle() 
     }
    {
        List<Card> NewCards = new List<Card>();
        while (cards.Count > 0) 
        {
            int CardToMove = random.Next(cards.Count);
            NewCards.Add(cards[CardToMove]);
            cards.RemoveAt(CardToMove);
        }
        cards = NewCards;
    }

public IEnumerable<string> GetCardNames() 

{
    string[] CardNames = new string[cards.Count];
    for (int i = 0; i < cards.Count; i++)
    CardNames[i] = cards[i].Name;
    return CardNames;
}

Deck deck1;
Deck deck2;
Random random = new Random();

public Form1() 
{

InitializeComponent();
ResetDeck(1);
ResetDeck(2);
RedrawDeck(1);
 RedrawDeck(2);

}



 private void ResetDeck(int deckNumber) 
    {
    if (deckNumber == 1) 
{
      int numberOfCards = random.Next(1, 11);
      deck1 = new Deck(new Card[] { });
      for (int i = 0; i < numberOfCards; i++)
           deck1.Add(new Card((Suits)random.Next(4),(Values)random.Next(1, 14)));
       deck1.Sort();
}


   else
    deck2 = new Deck();
 }

private void reset1_Click(object sender, EventArgs e) {
ResetDeck(1);
RedrawDeck(1);

}

private void shuffle1_Click(object sender, EventArgs e) 
{
    deck1.Shuffle();
    RedrawDeck(1);

}

private void moveToDeck1_Click(object sender, EventArgs e) 
{

    if (listBox2.SelectedIndex >= 0)
    if (deck2.Count > 0) {
    deck1.Add(deck2.Deal(listBox2.SelectedIndex));

}

    RedrawDeck(1);
    RedrawDeck(2);

}

可以使用morelinq包中的Shuffle扩展方法，它适用于IEnumerables

安装包morelinq

using MoreLinq;
...    
var randomized = list.Shuffle();

如果您有一个固定的数字(75)，您可以创建一个包含75个元素的数组，然后枚举您的列表，将元素移动到数组中的随机位置。您可以使用Fisher-Yates shuffle生成列表号到数组索引的映射。

private List<GameObject> ShuffleList(List<GameObject> ActualList) {


    List<GameObject> newList = ActualList;
    List<GameObject> outList = new List<GameObject>();

    int count = newList.Count;

    while (newList.Count > 0) {

        int rando = Random.Range(0, newList.Count);

        outList.Add(newList[rando]);

        newList.RemoveAt(rando);

     

    }

    return (outList);

}

用法:

List<GameObject> GetShuffle = ShuffleList(ActualList);

解决这类问题的一个非常简单的方法是在列表中使用一些随机的元素交换。

在伪代码中是这样的:

do 
    r1 = randomPositionInList()
    r2 = randomPositionInList()
    swap elements at index r1 and index r2 
for a certain number of times

只是想建议使用IComparer<T>和List.Sort()的变体:

public class RandomIntComparer : IComparer<int>
{
    private readonly Random _random = new Random();
    
    public int Compare(int x, int y)
    {
        return _random.Next(-1, 2);
    }
}

用法:

list.Sort(new RandomIntComparer());