有几种方法，所以我将把它们都总结一下

Best way is: function foo(v) {if (v instanceof Function) {/* do something */} }; Most performant (no string comparison) and elegant solution - the instanceof operator has been supported in browsers for a very long time, so don't worry - it will work in IE 6. Next best way is: function foo(v) {if (typeof v === "function") {/* do something */} }; disadvantage of typeof is that it is susceptible to silent failure, bad, so if you have a typo (e.g. "finction") - in this case the if will just return false and you won't know you have an error until later in your code The next best way is: function isFunction(functionToCheck) { var getType = {}; return functionToCheck && getType.toString.call(functionToCheck) === '[object Function]'; } This has no advantage over solution #1 or #2 but is a lot less readable. An improved version of this is function isFunction(x) { return Object.prototype.toString.call(x) == '[object Function]'; } but still lot less semantic than solution #1

当然，下划线的方式更有效率，但当效率不是问题时，最好的检查方法是在@Paul Rosania的下划线页面上写的。

受下划线的启发，最后的isFunction函数如下:

function isFunction(functionToCheck) {
 return functionToCheck && {}.toString.call(functionToCheck) === '[object Function]';
}

注意:此解决方案不适用于异步函数、生成器或代理函数。请参阅其他答案，以了解更多最新的解决方案。

尝试instanceof操作符:似乎所有函数都继承自Function类:

// Test data
var f1 = function () { alert("test"); }
var o1 = { Name: "Object_1" };
F_est = function () { };
var o2 = new F_est();

// Results
alert(f1 instanceof Function); // true
alert(o1 instanceof Function); // false
alert(o2 instanceof Function); // false

下面的代码似乎也适用于我(从node.js测试):

var isFunction = function(o) {
     return Function.prototype.isPrototypeOf(o);
};

console.log(isFunction(function(){})); // true
console.log(isFunction({})); // false

注意这一点:

typeof Object === "function" // true.
typeof Array  === "function" // true

if (typeof v === 'function') {
    // do something
}