假设有任意变量,定义如下:
var a = function() {/* Statements */};
我想要一个函数来检查变量的类型是否为类函数。例如:
function foo(v) {if (v is function type?) {/* do something */}};
foo(a);
我怎样才能检查变量a是否为上述定义的函数类型?
假设有任意变量,定义如下:
var a = function() {/* Statements */};
我想要一个函数来检查变量的类型是否为类函数。例如:
function foo(v) {if (v is function type?) {/* do something */}};
foo(a);
我怎样才能检查变量a是否为上述定义的函数类型?
当前回答
当然,下划线的方式更有效率,但当效率不是问题时,最好的检查方法是在@Paul Rosania的下划线页面上写的。
受下划线的启发,最后的isFunction函数如下:
function isFunction(functionToCheck) {
return functionToCheck && {}.toString.call(functionToCheck) === '[object Function]';
}
注意:此解决方案不适用于异步函数、生成器或代理函数。请参阅其他答案,以了解更多最新的解决方案。
其他回答
你应该在js中使用typeOf操作符。
var a=function(){
alert("fun a");
}
alert(typeof a);// alerts "function"
如果你正在寻找一个简单的解决方案:
function isFunction(value) {
return value instanceof Function
}
另一种简单的方法:
var fn = function () {}
if (fn.constructor === Function) {
// true
} else {
// false
}
有几种方法,所以我将把它们都总结一下
Best way is: function foo(v) {if (v instanceof Function) {/* do something */} }; Most performant (no string comparison) and elegant solution - the instanceof operator has been supported in browsers for a very long time, so don't worry - it will work in IE 6. Next best way is: function foo(v) {if (typeof v === "function") {/* do something */} }; disadvantage of typeof is that it is susceptible to silent failure, bad, so if you have a typo (e.g. "finction") - in this case the if will just return false and you won't know you have an error until later in your code The next best way is: function isFunction(functionToCheck) { var getType = {}; return functionToCheck && getType.toString.call(functionToCheck) === '[object Function]'; } This has no advantage over solution #1 or #2 but is a lot less readable. An improved version of this is function isFunction(x) { return Object.prototype.toString.call(x) == '[object Function]'; } but still lot less semantic than solution #1
对于那些对函数式风格感兴趣,或者在元编程中寻找更有表现力的方法(如类型检查)的人来说,看到Ramda库来完成这样的任务可能会很有趣。
下面的代码只包含纯函数和无点函数:
const R = require('ramda');
const isPrototypeEquals = R.pipe(Object.getPrototypeOf, R.equals);
const equalsSyncFunction = isPrototypeEquals(() => {});
const isSyncFunction = R.pipe(Object.getPrototypeOf, equalsSyncFunction);
从ES2017开始,异步函数是可用的,所以我们也可以检查它们:
const equalsAsyncFunction = isPrototypeEquals(async () => {});
const isAsyncFunction = R.pipe(Object.getPrototypeOf, equalsAsyncFunction);
然后把它们组合在一起:
const isFunction = R.either(isSyncFunction, isAsyncFunction);
当然,函数应该被保护不受空值和未定义值的影响,所以为了使它“安全”:
const safeIsFunction = R.unless(R.isNil, isFunction);
并且,完整的片段进行总结:
const R = require('ramda');
const isPrototypeEquals = R.pipe(Object.getPrototypeOf, R.equals);
const equalsSyncFunction = isPrototypeEquals(() => {});
const equalsAsyncFunction = isPrototypeEquals(async () => {});
const isSyncFunction = R.pipe(Object.getPrototypeOf, equalsSyncFunction);
const isAsyncFunction = R.pipe(Object.getPrototypeOf, equalsAsyncFunction);
const isFunction = R.either(isSyncFunction, isAsyncFunction);
const safeIsFunction = R.unless(R.isNil, isFunction);
// ---
console.log(safeIsFunction( function () {} ));
console.log(safeIsFunction( () => {} ));
console.log(safeIsFunction( (async () => {}) ));
console.log(safeIsFunction( new class {} ));
console.log(safeIsFunction( {} ));
console.log(safeIsFunction( [] ));
console.log(safeIsFunction( 'a' ));
console.log(safeIsFunction( 1 ));
console.log(safeIsFunction( null ));
console.log(safeIsFunction( undefined ));
但是,请注意,由于大量使用高阶函数,此解决方案的性能可能低于其他可用选项。