如果你有enum

enum Diet {
  KETO = "Ketogenic",
  ATKINS = "Atkins",
  PALEO = "Paleo",
  DGAF = "Whatever"
}

然后你可以得到如下的键和值:

Object.keys(Diet).forEach((d: Diet) => {
  console.log(d); // KETO
  console.log(Diet[d]) // Ketogenic
});

我卑微的2美分基于阅读一个了不起的评论从github TS讨论

const EnvironmentVariants = ['development', 'production', 'test'] as const 
type EPredefinedEnvironment = typeof EnvironmentVariants[number]

然后在编译时:

// TS2322: Type '"qaEnv"' is not assignable to type '"development" | "production" | "test"'.
const qaEnv: EPredefinedEnvironment = 'qa' 

在运行时:

function isPredefinedEnvironemt(env: string) {
  for (const predefined of EnvironmentVariants) {
    if (predefined === env) {
      return true
    }
  }
  return false
}

assert(isPredefinedEnvironemet('test'), true)
assert(isPredefinedEnvironemet('qa'), false)

注意，for(const index in environmentvariables){…}将遍历"0"，"1"，"2"集合

可以是简短的:

enum AnimalEnum {
  DOG = "dog", 
  CAT = "cat", 
  MOUSE = "mouse"
}

Object.keys(AnimalEnum).filter(v => typeof v == 'string' && isNaN(v))

在当前的TypeScript版本1.8.9中，我使用类型化enum:

export enum Option {
    OPTION1 = <any>'this is option 1',
    OPTION2 = <any>'this is option 2'
}

与结果在这个Javascript对象:

Option = {
    "OPTION1": "this is option 1",
    "OPTION2": "this is option 2",
    "this is option 1": "OPTION1",
    "this is option 2": "OPTION2"
}

所以我必须通过键和值查询，只返回值:

let optionNames: Array<any> = [];    
for (let enumValue in Option) {
    let optionNameLength = optionNames.length;

    if (optionNameLength === 0) {
        this.optionNames.push([enumValue, Option[enumValue]]);
    } else {
        if (this.optionNames[optionNameLength - 1][1] !== enumValue) {
            this.optionNames.push([enumValue, Option[enumValue]]);
        }
    }
}

我在数组中收到选项键:

optionNames = [ "OPTION1", "OPTION2" ];

我希望这个问题仍然有意义。我使用这样的函数:

function enumKeys(target: Record<string, number|string>): string[] {
  const allKeys: string[] = Object.keys(target);
  const parsedKeys: string[] = [];

  for (const key of allKeys) {
    const needToIgnore: boolean
      = target[target[key]]?.toString() === key && !isNaN(parseInt(key));

    if (!needToIgnore) {
      parsedKeys.push(key);
    }
  }

  return parsedKeys;
}

function enumValues(target: Record<string, number|string>): Array<string|number> {
  const keys: string[] = enumKeys(target);
  const values: Array<string|number> = [];

  for (const key of keys) {
    values.push(target[key]);
  }

  return values;
}

例子:

enum HttpStatus {
  OK,
  INTERNAL_ERROR,
  FORBIDDEN = 'FORBIDDEN',
  NOT_FOUND = 404,
  BAD_GATEWAY = 'bad-gateway'
}


console.log(enumKeys(HttpStatus));
// > ["OK", "INTERNAL_ERROR", "FORBIDDEN", "NOT_FOUND", "BAD_GATEWAY"] 

console.log(enumValues(HttpStatus));
// > [0, 1, "FORBIDDEN", 404, "bad-gateway"]

你可以这样做，我认为这是最短、最干净、最快的:

Object.entries(test).filter(([key]) => (!~~key && key !== "0"))

给定以下混合类型枚举定义:

enum testEnum {
  Critical = "critical",
  Major = 3,
  Normal = "2",
  Minor = "minor",
  Info = "info",
  Debug = 0
};

它将会变成以下内容:

var testEnum = { 关键:“至关重要的”, 主要:3, 正常:“2”, 小:“小”, 信息:“信息”, 调试:0, [0]:“关键”, [1]: 3, [2]:“2”, [3]:“小”, [4]:“信息”, [5]: 0 ｝ 函数safeEnumEntries(test) { return Object.entries(test).filter(([key]) => (!~~key && key !== "0"); }; console.log (safeEnumEntries (testEnum));

执行函数后，你只会得到好的条目:

[
  ["Critical", "critical"],
  ["Major", 3],
  ["Normal", "2"],
  ["Minor", "minor"],
  ["Info", "info"],
  ["Debug", 0]
]