我想迭代一个TypeScript枚举对象,并获得每个枚举符号名称,例如: enum myEnum {entry1, entry2}

for (var entry in myEnum) { 
    // use entry's name here, e.g., "entry1"
}

当前回答

虽然答案已经提供了,但几乎没有人指向文档

下面是一个片段

enum Enum {
    A
}
let nameOfA = Enum[Enum.A]; // "A"

请记住,string enum成员根本不会生成反向映射。

其他回答

在当前的TypeScript版本1.8.9中,我使用类型化enum:

export enum Option {
    OPTION1 = <any>'this is option 1',
    OPTION2 = <any>'this is option 2'
}

与结果在这个Javascript对象:

Option = {
    "OPTION1": "this is option 1",
    "OPTION2": "this is option 2",
    "this is option 1": "OPTION1",
    "this is option 2": "OPTION2"
}

所以我必须通过键和值查询,只返回值:

let optionNames: Array<any> = [];    
for (let enumValue in Option) {
    let optionNameLength = optionNames.length;

    if (optionNameLength === 0) {
        this.optionNames.push([enumValue, Option[enumValue]]);
    } else {
        if (this.optionNames[optionNameLength - 1][1] !== enumValue) {
            this.optionNames.push([enumValue, Option[enumValue]]);
        }
    }
}

我在数组中收到选项键:

optionNames = [ "OPTION1", "OPTION2" ];

使用当前版本的TypeScript,你可以使用这些函数将Enum映射到你选择的记录。注意,不能用这些函数定义字符串值,因为它们查找值为数字的键。

enum STATES {
  LOGIN,
  LOGOUT,
}

export const enumToRecordWithKeys = <E extends any>(enumeration: E): E => (
  Object.keys(enumeration)
    .filter(key => typeof enumeration[key] === 'number')
    .reduce((record, key) => ({...record, [key]: key }), {}) as E
);

export const enumToRecordWithValues = <E extends any>(enumeration: E): E => (
  Object.keys(enumeration)
    .filter(key => typeof enumeration[key] === 'number')
    .reduce((record, key) => ({...record, [key]: enumeration[key] }), {}) as E
);

const states = enumToRecordWithKeys(STATES)
const statesWithIndex = enumToRecordWithValues(STATES)

console.log(JSON.stringify({
  STATES,
  states,
  statesWithIndex,
}, null ,2));

// Console output:
{
  "STATES": {
    "0": "LOGIN",
    "1": "LOGOUT",
    "LOGIN": 0,
    "LOGOUT": 1
  },
  "states": {
    "LOGIN": "LOGIN",
    "LOGOUT": "LOGOUT"
  },
  "statesWithIndex": {
    "LOGIN": 0,
    "LOGOUT": 1
  }
}

如果你有enum

enum Diet {
  KETO = "Ketogenic",
  ATKINS = "Atkins",
  PALEO = "Paleo",
  DGAF = "Whatever"
}

然后你可以得到如下的键和值:

Object.keys(Diet).forEach((d: Diet) => {
  console.log(d); // KETO
  console.log(Diet[d]) // Ketogenic
});

唯一的解决方案,适用于我在所有情况下(即使值是字符串)是以下:

var enumToString = function(enumType, enumValue) {
    for (var enumMember in enumType) {
        if (enumType[enumMember]==enumValue) return enumMember
    }
}

我卑微的2美分基于阅读一个了不起的评论从github TS讨论

const EnvironmentVariants = ['development', 'production', 'test'] as const 
type EPredefinedEnvironment = typeof EnvironmentVariants[number]

然后在编译时:

// TS2322: Type '"qaEnv"' is not assignable to type '"development" | "production" | "test"'.
const qaEnv: EPredefinedEnvironment = 'qa' 

在运行时:

function isPredefinedEnvironemt(env: string) {
  for (const predefined of EnvironmentVariants) {
    if (predefined === env) {
      return true
    }
  }
  return false
}

assert(isPredefinedEnvironemet('test'), true)
assert(isPredefinedEnvironemet('qa'), false)

注意,for(const index in environmentvariables){…}将遍历"0","1","2"集合