When I look at this description, I have a feeling, that this xdr integer is just a big-endian "standard" integer, but it's expressed in the most obfuscated way. Two's complement notation is better know as U2, and it's what we are using on today's processors. The byte order indicates that it's a big-endian notation. So, answering your question, you should inverse elements in your array (0 <--> 3, 1 <-->2), as they are encoded in little-endian. Just to make sure, you should first check BitConverter.IsLittleEndian to see on what machine you are running.

这里有另一种方法:我们都知道1x字节= 8x位，而且，一个“常规”整数(int32)包含32位(4个字节)。我们可以使用>>操作符向右移位位(>>操作符不改变值)。

int intValue = 566;

byte[] bytes = new byte[4];

bytes[0] = (byte)(intValue >> 24);
bytes[1] = (byte)(intValue >> 16);
bytes[2] = (byte)(intValue >> 8);
bytes[3] = (byte)intValue;

Console.WriteLine("{0} breaks down to : {1} {2} {3} {4}",
    intValue, bytes[0], bytes[1], bytes[2], bytes[3]);

如果你想了解更多关于表示数字的各种方法(包括Two's Complement)的一般信息，请查看:

维基百科上2的补数和有符号数表示

byte[] Take_Byte_Arr_From_Int(Int64 Source_Num)
{
   Int64 Int64_Num = Source_Num;
   byte Byte_Num;
   byte[] Byte_Arr = new byte[8];
   for (int i = 0; i < 8; i++)
   {
      if (Source_Num > 255)
      {
         Int64_Num = Source_Num / 256;
         Byte_Num = (byte)(Source_Num - Int64_Num * 256);
      }
      else
      {
         Byte_Num = (byte)Int64_Num;
         Int64_Num = 0;
      }
      Byte_Arr[i] = Byte_Num;
      Source_Num = Int64_Num;
   }
   return (Byte_Arr);
}

When I look at this description, I have a feeling, that this xdr integer is just a big-endian "standard" integer, but it's expressed in the most obfuscated way. Two's complement notation is better know as U2, and it's what we are using on today's processors. The byte order indicates that it's a big-endian notation. So, answering your question, you should inverse elements in your array (0 <--> 3, 1 <-->2), as they are encoded in little-endian. Just to make sure, you should first check BitConverter.IsLittleEndian to see on what machine you are running.

另一种方法是像这样使用BinaryPrimitives

byte[] intBytes = BitConverter.GetBytes(123); int actual = BinaryPrimitives.ReadInt32LittleEndian(intBytes);