TodoInTX的存储过程不太适合我。以下是我的尝试:

-- stored procedure rename_db: Rename a database my means of table copying.
-- Caveats: 
-- Will clobber any existing database with the same name as the 'new' database name.
-- ONLY copies tables; stored procedures and other database objects are not copied.
-- Tomer Altman (taltman@ai.sri.com)

delimiter //
DROP PROCEDURE IF EXISTS rename_db;
CREATE PROCEDURE rename_db(IN old_db VARCHAR(100), IN new_db VARCHAR(100))
BEGIN
    DECLARE current_table VARCHAR(100);
    DECLARE done INT DEFAULT 0;
    DECLARE old_tables CURSOR FOR select table_name from information_schema.tables where table_schema = old_db;
    DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = 1;

    SET @output = CONCAT('DROP SCHEMA IF EXISTS ', new_db, ';'); 
    PREPARE stmt FROM @output;
    EXECUTE stmt;

    SET @output = CONCAT('CREATE SCHEMA IF NOT EXISTS ', new_db, ';');
    PREPARE stmt FROM @output;
    EXECUTE stmt;

    OPEN old_tables;
    REPEAT
        FETCH old_tables INTO current_table;
        IF NOT done THEN
        SET @output = CONCAT('alter table ', old_db, '.', current_table, ' rename ', new_db, '.', current_table, ';');
        PREPARE stmt FROM @output;
        EXECUTE stmt;

        END IF;
    UNTIL done END REPEAT;

    CLOSE old_tables;

END//
delimiter ;

简单的方法

切换到数据库目录:

cd /var/lib/mysql/

关闭MySQL…这很重要!

/etc/init.d/mysql stop

好吧，这种方法不适用于InnoDB或BDB-Databases。

重命名数据库:

mv old-name new-name

.．.或者桌子……

cd database/

mv old-name.frm new-name.frm

mv old-name.MYD new-name.MYD

mv old-name.MYI new-name.MYI

重新启动MySQL

/etc/init.d/mysql start

做……

好吧，这种方法不适用于InnoDB或BDB数据库。在这种情况下，您必须转储数据库并重新导入它。

我能给出的最快和最简单的解决办法是……在MySql Workbench中右键单击您的模式->单击创建模式->输入该模式的名称。

删除旧名称的旧模式。

你已经准备好摇滚....

注意:仅用于本地目的。不要尝试生产数据库表。创建了模式，但其中没有数据。所以要小心。

当您在PHPMyAdmin中重命名数据库时，它会创建一个转储，然后删除并使用新名称重新创建数据库。

这里的大多数答案都是错误的，原因有两个:

不能只使用RENAME TABLE，因为可能存在视图和触发器。如果有触发器，RENAME TABLE将失败 如果你想“快速”(如问题中要求的)重命名一个大数据库，你不能使用mysqldump

Percona有一篇关于如何做到这一点的博客文章: https://www.percona.com/blog/2013/12/24/renaming-database-schema-mysql/

以及由西蒙·R·琼斯(Simon R Jones)发布的脚本(制作的?)我修复了在脚本中发现的一个错误。你可以在这里看到:

https://gist.github.com/ryantm/76944318b0473ff25993ef2a7186213d

以下是它的副本:

#!/bin/bash
# Copyright 2013 Percona LLC and/or its affiliates
# @see https://www.percona.com/blog/2013/12/24/renaming-database-schema-mysql/
set -e
if [ -z "$3" ]; then
    echo "rename_db <server> <database> <new_database>"
    exit 1
fi
db_exists=`mysql -h $1 -e "show databases like '$3'" -sss`
if [ -n "$db_exists" ]; then
    echo "ERROR: New database already exists $3"
    exit 1
fi
TIMESTAMP=`date +%s`
character_set=`mysql -h $1 -e "SELECT default_character_set_name FROM information_schema.SCHEMATA WHERE schema_name = '$2'" -sss`
TABLES=`mysql -h $1 -e "select TABLE_NAME from information_schema.tables where table_schema='$2' and TABLE_TYPE='BASE TABLE'" -sss`
STATUS=$?
if [ "$STATUS" != 0 ] || [ -z "$TABLES" ]; then
    echo "Error retrieving tables from $2"
    exit 1
fi
echo "create database $3 DEFAULT CHARACTER SET $character_set"
mysql -h $1 -e "create database $3 DEFAULT CHARACTER SET $character_set"
TRIGGERS=`mysql -h $1 $2 -e "show triggers\G" | grep Trigger: | awk '{print $2}'`
VIEWS=`mysql -h $1 -e "select TABLE_NAME from information_schema.tables where table_schema='$2' and TABLE_TYPE='VIEW'" -sss`
if [ -n "$VIEWS" ]; then
    mysqldump -h $1 $2 $VIEWS > /tmp/${2}_views${TIMESTAMP}.dump
fi
mysqldump -h $1 $2 -d -t -R -E > /tmp/${2}_triggers${TIMESTAMP}.dump
for TRIGGER in $TRIGGERS; do
    echo "drop trigger $TRIGGER"
    mysql -h $1 $2 -e "drop trigger $TRIGGER"
done
for TABLE in $TABLES; do
    echo "rename table $2.$TABLE to $3.$TABLE"
    mysql -h $1 $2 -e "SET FOREIGN_KEY_CHECKS=0; rename table $2.$TABLE to $3.$TABLE"
done
if [ -n "$VIEWS" ]; then
    echo "loading views"
    mysql -h $1 $3 < /tmp/${2}_views${TIMESTAMP}.dump
fi
echo "loading triggers, routines and events"
mysql -h $1 $3 < /tmp/${2}_triggers${TIMESTAMP}.dump
TABLES=`mysql -h $1 -e "select TABLE_NAME from information_schema.tables where table_schema='$2' and TABLE_TYPE='BASE TABLE'" -sss`
if [ -z "$TABLES" ]; then
    echo "Dropping database $2"
    mysql -h $1 $2 -e "drop database $2"
fi
if [ `mysql -h $1 -e "select count(*) from mysql.columns_priv where db='$2'" -sss` -gt 0 ]; then
    COLUMNS_PRIV="    UPDATE mysql.columns_priv set db='$3' WHERE db='$2';"
fi
if [ `mysql -h $1 -e "select count(*) from mysql.procs_priv where db='$2'" -sss` -gt 0 ]; then
    PROCS_PRIV="    UPDATE mysql.procs_priv set db='$3' WHERE db='$2';"
fi
if [ `mysql -h $1 -e "select count(*) from mysql.tables_priv where db='$2'" -sss` -gt 0 ]; then
    TABLES_PRIV="    UPDATE mysql.tables_priv set db='$3' WHERE db='$2';"
fi
if [ `mysql -h $1 -e "select count(*) from mysql.db where db='$2'" -sss` -gt 0 ]; then
    DB_PRIV="    UPDATE mysql.db set db='$3' WHERE db='$2';"
fi
if [ -n "$COLUMNS_PRIV" ] || [ -n "$PROCS_PRIV" ] || [ -n "$TABLES_PRIV" ] || [ -n "$DB_PRIV" ]; then
    echo "IF YOU WANT TO RENAME the GRANTS YOU NEED TO RUN ALL OUTPUT BELOW:"
    if [ -n "$COLUMNS_PRIV" ]; then echo "$COLUMNS_PRIV"; fi
    if [ -n "$PROCS_PRIV" ]; then echo "$PROCS_PRIV"; fi
    if [ -n "$TABLES_PRIV" ]; then echo "$TABLES_PRIV"; fi
    if [ -n "$DB_PRIV" ]; then echo "$DB_PRIV"; fi
    echo "    flush privileges;"
fi

将它保存到一个名为rename_db的文件中，并使用chmod +x rename_db使脚本可执行，然后像。/rename_db localhost old_db new_db那样使用它

我认为这个解决方案更简单，是一些开发人员提出的。phpMyAdmin对此有一个操作。

从phpMyAdmin中选择要选择的数据库。在选项卡中有一个叫做Operations，转到rename部分。这是所有。

正如许多人建议的那样，它使用新名称创建一个新数据库，将旧数据库的所有表转储到新数据库中，并删除旧数据库。

更新2022-09-22:MySQL 8.0+增加了一个更简单的解决方案:

不知道从什么时候开始添加RENAME TO关键字，但肯定更简单。不过在尝试之前，我会先把桌子备份一下，尤其是如果你的桌子很大的话。无论如何，它可以实现如下:

ALTER TABLE `schema_name`.`table_name` 
RENAME TO  `schema_name`.`new_table_name` ;

为了便于阅读，我把它分成了两行，但也可以写成单行，如下:

ALTER TABLE `schema_name`.`table_name` RENAME TO `schema_name`.`new_table_name` ;