给定一个这样的字符串:

"The dog      has a long   tail, and it     is RED!"

什么样的jQuery或JavaScript魔法可以用来保持空间只有一个最大空间?

目标:

"The dog has a long tail, and it is RED!"

当前回答

尝试用一个空格替换多个空格。

<script type="text/javascript">
    var myStr = "The dog      has a long   tail, and it     is RED!";
    alert(myStr);  // Output 'The dog      has a long   tail, and it     is RED!'

    var newStr = myStr.replace(/  +/g, ' ');
    alert(newStr);  // Output 'The dog has a long tail, and it is RED!'
</script>

阅读更多@用单个空格替换多个空格

其他回答

如果你不想使用replace(替换字符串中的空格而不使用replace javascript),这里有一个替代解决方案。

var str=“狗有一条长尾巴,而且是红色的!”; var = / \ s规则{1,}/ g; STR = STR .split(规则)。加入(" "); document . write (str);

var string = "The dog      has a long   tail, and it     is RED!";
var replaced = string.replace(/ +/g, " ");

或者如果你也想替换制表符:

var replaced = string.replace(/\s+/g, " ");

以下是对我来说很有效的解决方案:

var text = “ Tes ddas dMd WAlkman 3Dsfd ” .toLowerCase() .replace(/\b\s+/g, “ ”) .replace(/\b\w/g, s => s.toUpperCase()) .trimStart() .trimEnd(); 控制台.log(文本); 结果: Tes Ddas Dmd 随身听 3dsfd

更健壮的:

function trim(word)
{
    word = word.replace(/[^\x21-\x7E]+/g, ' '); // change non-printing chars to spaces
    return word.replace(/^\s+|\s+$/g, '');      // remove leading/trailing spaces
}

我有一个方法,我叫它Derp方法因为没有更好的名字。

while (str.indexOf("  ") !== -1) {
    str = str.replace(/  /g, " ");
}

在JSPerf中运行它会得到一些令人惊讶的结果,它击败了一些更复杂的方法EDIT原始JSPerf链接http://jsperf.com/removing-multiple-spaces/3当时似乎已经死了