是否存在在一次操作中截断数据库中所有表的查询(命令)?我想知道我是否可以用一个查询做到这一点。
当前回答
由battousaix的Ans是完美的! 我只是使用了他的答案,并创建了截断数据库表的最终工作命令。
mysql -P 3306 -h YOUR_HOST_HERE -u YOUR_USERNAME_HERE -pYOUR_PASSWORD_HERE -Nse 'show tables' DATABASE_NAME |,同时读取表;-h YOUR_HOST_HERE -u your_username - here -pYOUR_PASSWORD_HERE -e "SET FOREIGN_KEY_CHECKS = 0;截断表$ DATABASE_NAME完成
上面的命令将完美地工作于MySQL服务器。
而且,它也包括在内。
设置foreign_key_checks = 0
其他回答
TB=$( mysql -Bse "show tables from DATABASE" );
for i in ${TB};
do echo "Truncating table ${i}";
mysql -e "set foreign_key_checks=0; set unique_checks=0;truncate table DATABASE.${i}; set foreign_key_checks=1; set unique_checks=1";
sleep 1;
done
--
大卫,
感谢您花时间格式化代码,但这是它应该如何应用。
库尔特
在UNIX或Linux机器上:
确保您处于bash shell中。从命令行运行这些命令,如下所示。
注意:
我将凭据存储在~/.my.cnf文件中,因此不需要在命令行上提供凭据。
注意:
CPM是数据库名称
我只展示了来自每个命令的结果的一小部分示例。
找到你的外键约束:
klarsen@Chaos:~$ mysql -Bse "select concat(table_name, ' depends on ', referenced_table_name)
from information_schema.referential_constraints
where constraint_schema = 'cpm'
order by referenced_table_name"
Approval_external_system依赖于approval_request 地址视客户而定 Customer_identification取决于客户 External_id取决于客户 凭证取决于客户 Email_address取决于客户 Approval_request取决于客户 Customer_status取决于客户 Customer_image取决于客户
列出表和行数:
klarsen@Chaos:~$ mysql -Bse "SELECT table_name, table_rows FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_SCHEMA = 'cpm'" | cat -n
1 address 297
2 approval_external_system 0
3 approval_request 0
4 country 189
5 credential 468
6 customer 6776
7 customer_identification 5631
8 customer_image 2
9 customer_status 13639
截断你的表:
klarsen@Chaos:~$ TB=$( mysql -Bse "show tables from cpm" ); for i in ${TB}; do echo "Truncating table ${i}"; mysql -e "set foreign_key_checks=0; set unique_checks=0;truncate table cpm.${i}; set foreign_key_checks=1; set unique_checks=1"; sleep 1; done
截断表地址 截断表approval_external_system 截断表approval_request 截断表国家 截断表凭据 截断表客户 截断表customer_identification 截断表customer_image 截断表customer_status
验证它是否有效:
klarsen@Chaos:~$ mysql -Bse "SELECT table_name, table_rows FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_SCHEMA = 'cpm'" | cat -n
1 address 0
2 approval_external_system 0
3 approval_request 0
4 country 0
5 credential 0
6 customer 0
7 customer_identification 0
8 customer_image 0
9 customer_status 0
10 email_address 0
在Windows机器上:
注意:
CPM是数据库名称
C:\>for /F "tokens=*" %a IN ('mysql -Bse "show tables" cpm') do mysql -e "set foreign_key_checks=0; set unique_checks=0; truncate table %a; foreign_key_checks=1; set unique_checks=1" cpm
这将输出截断所有表的命令:
SELECT GROUP_CONCAT(Concat('TRUNCATE TABLE ',table_schema,'.',TABLE_NAME) SEPARATOR ';') FROM INFORMATION_SCHEMA.TABLES where table_schema in ('my_db');
我发现最简单的方法是像下面这样做,只需用自己的表名替换表名。重要的是确保最后一行永远是 设置FOREIGN_KEY_CHECKS = 1;
SET FOREIGN_KEY_CHECKS=0;
TRUNCATE `table1`;
TRUNCATE `table2`;
TRUNCATE `table3`;
TRUNCATE `table4`;
TRUNCATE `table5`;
TRUNCATE `table6`;
TRUNCATE `table7`;
SET FOREIGN_KEY_CHECKS=1;
溶液(1)
mysql> select group_concat('truncate',' ',table_name,';') from information_schema.tables where table_schema="db_name" into outfile '/tmp/a.txt';
mysql> /tmp/a.txt;
溶液2)
- Export only structure of a db
- drop the database
- import the .sql of structure
——编辑----
earlier in solution 1, i had mentioned concat() instead of group_concat() which would have not returned the desired result
<?php
// connect to database
$conn=mysqli_connect("localhost","user","password","database");
// check connection
if (mysqli_connect_errno()) {
exit('Connect failed: '. mysqli_connect_error());
}
// sql query
$sql =mysqli_query($conn,"TRUNCATE " . TABLE_NAME);
// Print message
if ($sql === TRUE) {
echo 'data delete successfully';
}
else {
echo 'Error: '. $conn->error;
}
$conn->close();
?>
这是我用来清除一个表的代码片段。只需更改$conn info和TABLE_NAME。