是否有一个聪明的(即优化)方法重命名一个关键在javascript对象?
一种非优化的方式是:
o[ new_key ] = o[ old_key ];
delete o[ old_key ];
是否有一个聪明的(即优化)方法重命名一个关键在javascript对象?
一种非优化的方式是:
o[ new_key ] = o[ old_key ];
delete o[ old_key ];
当前回答
const data = res
const lista = []
let newElement: any
if (data && data.length > 0) {
data.forEach(element => {
newElement = element
Object.entries(newElement).map(([key, value]) =>
Object.assign(newElement, {
[key.toLowerCase()]: value
}, delete newElement[key], delete newElement['_id'])
)
lista.push(newElement)
})
}
return lista
其他回答
重命名键,但避免改变原始对象参数
oldJson=[{firstName:'s1',lastName:'v1'},
{firstName:'s2',lastName:'v2'},
{firstName:'s3',lastName:'v3'}]
newJson = oldJson.map(rec => {
return {
'Last Name': rec.lastName,
'First Name': rec.firstName,
}
})
output: [{Last Name:"v1",First Name:"s1"},
{Last Name:"v2",First Name:"s2"},
{Last Name:"v3",First Name:"s3"}]
最好有一个新的数组
尝试使用lodash transform。
var _ = require('lodash');
obj = {
"name": "abc",
"add": "xyz"
};
var newObject = _.transform(obj, function(result, val, key) {
if (key === "add") {
result["address"] = val
} else {
result[key] = val
}
});
console.log(obj);
console.log(newObject);
如果有人需要重命名object的键:
const renameKeyObject = (obj, oldKey, newKey) => { 如果 (旧键 === 新键) 返回 volj; Object.keys(obj).forEach((key) => { if (key === oldKey) { obj[newKey] = obj[key]; 删除 obj[键]; } else if (obj[key] !== null &&; typeof obj[key] === “object”) { obj[key] = renameKeyObject(obj[key], oldKey, newKey); } }); 返回卷; };
还有一种最强大的REDUCE方法。
数据= {\ key1:“value1”,key2:“value2”,key3:“value3”}; 键文件夹= {\ key1:“firstkey”,key2:“secondkey”,key3:“thirdkey” mappedData = Object.keys . .还原((obj,k) =>对象。assign(obj, {\ [keyMap]]:数据[k]},{\}; 控制台日志(mappedData); 第一个“value1”、“secondkey”、“value2”、“thirdkey”、“value3”……
const data = res
const lista = []
let newElement: any
if (data && data.length > 0) {
data.forEach(element => {
newElement = element
Object.entries(newElement).map(([key, value]) =>
Object.assign(newElement, {
[key.toLowerCase()]: value
}, delete newElement[key], delete newElement['_id'])
)
lista.push(newElement)
})
}
return lista