在我的模型中我有:

class Alias(MyBaseModel):
remote_image = models.URLField(
    max_length=500, null=True,
    help_text='''
        A URL that is downloaded and cached for the image.
        Only used when the alias is made
    '''
)
    image = models.ImageField(
        upload_to='alias', default='alias-default.png',
        help_text="An image representing the alias"
    )

    
    def save(self, *args, **kw):
        if (not self.image or self.image.name == 'alias-default.png') and self.remote_image :
            try :
                data = utils.fetch(self.remote_image)
                image = StringIO.StringIO(data)
                image = Image.open(image)
                buf = StringIO.StringIO()
                image.save(buf, format='PNG')
                self.image.save(
                    hashlib.md5(self.string_id).hexdigest() + ".png", ContentFile(buf.getvalue())
                )
            except IOError :
                pass

这在remote_image第一次改变的时候工作得很好。

当有人修改了别名上的remote_image时,我如何获取一个新的图像?其次,是否有更好的方法来缓存远程映像?


当前回答

我对@iperelivskiy的解决方案的看法是:在大规模的情况下,为每个__init__创建_initial字典是昂贵的,而且大多数时候是不必要的。我稍微改变了mixin,这样它只在你显式地告诉它这样做(通过调用instance.track_changes)时才记录更改:

from typing import KeysView, Optional
from django.forms import model_to_dict

class TrackChangesMixin:
    _snapshot: Optional[dict] = None

    def track_changes(self):
        self._snapshot = self.as_dict

    @property
    def diff(self) -> dict:
        if self._snapshot is None:
            raise ValueError("track_changes wasn't called, can't determine diff.")
        d1 = self._snapshot
        d2 = self.as_dict
        diffs = [(k, (v, d2[k])) for k, v in d1.items() if str(v) != str(d2[k])]
        return dict(diffs)

    @property
    def has_changed(self) -> bool:
        return bool(self.diff)

    @property
    def changed_fields(self) -> KeysView:
        return self.diff.keys()

    @property
    def as_dict(self) -> dict:
        return model_to_dict(self, fields=[field.name for field in self._meta.fields])

其他回答

我使用以下mixin:

from django.forms.models import model_to_dict


class ModelDiffMixin(object):
    """
    A model mixin that tracks model fields' values and provide some useful api
    to know what fields have been changed.
    """

    def __init__(self, *args, **kwargs):
        super(ModelDiffMixin, self).__init__(*args, **kwargs)
        self.__initial = self._dict

    @property
    def diff(self):
        d1 = self.__initial
        d2 = self._dict
        diffs = [(k, (v, d2[k])) for k, v in d1.items() if v != d2[k]]
        return dict(diffs)

    @property
    def has_changed(self):
        return bool(self.diff)

    @property
    def changed_fields(self):
        return self.diff.keys()

    def get_field_diff(self, field_name):
        """
        Returns a diff for field if it's changed and None otherwise.
        """
        return self.diff.get(field_name, None)

    def save(self, *args, **kwargs):
        """
        Saves model and set initial state.
        """
        super(ModelDiffMixin, self).save(*args, **kwargs)
        self.__initial = self._dict

    @property
    def _dict(self):
        return model_to_dict(self, fields=[field.name for field in
                             self._meta.fields])

用法:

>>> p = Place()
>>> p.has_changed
False
>>> p.changed_fields
[]
>>> p.rank = 42
>>> p.has_changed
True
>>> p.changed_fields
['rank']
>>> p.diff
{'rank': (0, 42)}
>>> p.categories = [1, 3, 5]
>>> p.diff
{'categories': (None, [1, 3, 5]), 'rank': (0, 42)}
>>> p.get_field_diff('categories')
(None, [1, 3, 5])
>>> p.get_field_diff('rank')
(0, 42)
>>>

Note

请注意,此解决方案仅在当前请求的上下文中工作良好。因此,它主要适用于简单的情况。在并发环境中,多个请求可以同时操作同一个模型实例,您肯定需要一种不同的方法。

用David Cramer的解决方案怎么样:

http://cramer.io/2010/12/06/tracking-changes-to-fields-in-django/

我曾经这样成功地使用过:

@track_data('name')
class Mode(models.Model):
    name = models.CharField(max_length=5)
    mode = models.CharField(max_length=5)

    def save(self, *args, **kwargs):
        if self.has_changed('name'):
            print 'name changed'

    # OR #

    @classmethod
    def post_save(cls, sender, instance, created, **kwargs):
        if instance.has_changed('name'):
            print "Hooray!"

自从Django 1.8发布以来,你可以使用from_db类方法来缓存remote_image的旧值。然后在保存方法中,您可以比较字段的旧值和新值,以检查该值是否已更改。

@classmethod
def from_db(cls, db, field_names, values):
    new = super(Alias, cls).from_db(db, field_names, values)
    # cache value went from the base
    new._loaded_remote_image = values[field_names.index('remote_image')]
    return new

def save(self, force_insert=False, force_update=False, using=None,
         update_fields=None):
    if (self._state.adding and self.remote_image) or \
        (not self._state.adding and self._loaded_remote_image != self.remote_image):
        # If it is first save and there is no cached remote_image but there is new one, 
        # or the value of remote_image has changed - do your stuff!

虽然这实际上并没有回答你的问题,但我会以不同的方式来讨论这个问题。

成功保存本地副本后,只需清除remote_image字段。然后在保存方法中,只要remote_image不为空,就可以随时更新图像。

如果您想保留对url的引用,您可以使用一个不可编辑的布尔字段来处理缓存标志,而不是使用remote_image字段本身。

你可以使用django-model-changes来做到这一点,而不需要额外的数据库查询:

from django.dispatch import receiver
from django_model_changes import ChangesMixin

class Alias(ChangesMixin, MyBaseModel):
   # your model

@receiver(pre_save, sender=Alias)
def do_something_if_changed(sender, instance, **kwargs):
    if 'remote_image' in instance.changes():
        # do something