我有下面的数组
cities = ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"]
我想从数组中删除空白元素，并希望得到以下结果:
cities = ["Kathmandu", "Pokhara", "Dharan", "Butwal"]
有没有像compact这样不需要循环的方法?
当前回答
cities.reject! { |c| c.blank? }
为什么要用空白?在空的吗?blank可以识别nil，空字符串和空白。例如:
cities = ["Kathmandu", "Pokhara", " ", nil, "", "Dharan", "Butwal"].reject { |c| c.blank? }
仍然会返回:
["Kathmandu", "Pokhara", "Dharan", "Butwal"]
叫空?On " "将返回false，您可能希望它为true。
注:空白?只能通过Rails访问，Ruby只支持空?
其他回答
以下是对我有效的方法:
[1, "", 2, "hello", nil].reject(&:blank?)
输出:
[1, 2, "hello"]
当我想整理一个这样的数组时，我使用:
["Kathmandu", "Pokhara", "", "Dharan", "Butwal"] - ["", nil]
这将删除所有空白或nil元素。
试试这个:
puts ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"] - [""]
已经有很多答案了，但如果你在Rails世界里，这里有另一种方法:
cities = ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"].select &:present?
最明确的
cities.delete_if(&:blank?)
这将删除nil值和空字符串("")值。
例如:
cities = ["Kathmandu", "Pokhara", "", "Dharan", "Butwal", nil]
cities.delete_if(&:blank?)
# => ["Kathmandu", "Pokhara", "Dharan", "Butwal"]
