为了完成这个答案，它可以这样工作……

UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];
switch (types) {
   case UIRemoteNotificationTypeAlert:
   case UIRemoteNotificationTypeBadge:
       // For enabled code
       break;
   case UIRemoteNotificationTypeSound:
   case UIRemoteNotificationTypeNone:
   default:
       // For disabled code
       break;
}

编辑:这是不对的。因为这些是位智慧的东西，它不会与开关工作，所以我结束使用这个:

UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];
UIRemoteNotificationType typesset = (UIRemoteNotificationTypeAlert | UIRemoteNotificationTypeBadge);
if((types & typesset) == typesset)
{
    CeldaSwitch.chkSwitch.on = true;
}
else
{
    CeldaSwitch.chkSwitch.on = false;
}

斯威夫特 3+

    if #available(iOS 10.0, *) {
        UNUserNotificationCenter.current().getNotificationSettings(completionHandler: { (settings: UNNotificationSettings) in
            // settings.authorizationStatus == .authorized
        })
    } else {
        return UIApplication.shared.currentUserNotificationSettings?.types.contains(UIUserNotificationType.alert) ?? false
    }

RxSwift可观察的iOS10+版本:

import UserNotifications
extension UNUserNotificationCenter {
    static var isAuthorized: Observable<Bool> {
        return Observable.create { observer in
            DispatchQueue.main.async {
                current().getNotificationSettings(completionHandler: { (settings: UNNotificationSettings) in
                    if settings.authorizationStatus == .authorized {
                        observer.onNext(true)
                        observer.onCompleted()
                    } else {
                        current().requestAuthorization(options: [.badge, .alert, .sound]) { (granted, error) in
                            observer.onNext(granted)
                            observer.onCompleted()
                        }
                    }
                })
            }
            return Disposables.create()
        }
    }
}

这个Swifty解决方案对我来说效果很好(iOS8+)，

方法:

func isNotificationEnabled(completion:@escaping (_ enabled:Bool)->()){
    if #available(iOS 10.0, *) {
        UNUserNotificationCenter.current().getNotificationSettings(completionHandler: { (settings: UNNotificationSettings) in
            let status =  (settings.authorizationStatus == .authorized)
            completion(status)
        })
    } else {
        if let status = UIApplication.shared.currentUserNotificationSettings?.types{
            let status = status.rawValue != UIUserNotificationType(rawValue: 0).rawValue
            completion(status)
        }else{
            completion(false)
        }
    }
}

用法:

isNotificationEnabled { (isEnabled) in
            if isEnabled{
                print("Push notification enabled")
            }else{
                print("Push notification not enabled")
            }
        }

Ref

下面是如何在Xamarin.ios中做到这一点。

public class NotificationUtils
{
    public static bool AreNotificationsEnabled ()
    {
        var settings = UIApplication.SharedApplication.CurrentUserNotificationSettings;
        var types = settings.Types;
        return types != UIUserNotificationType.None;
    }
}

如果你支持iOS 10+，只使用UNUserNotificationCenter方法。

尽管Zac的答案在iOS 7之前是完全正确的，但自从iOS 8到来后，它就发生了变化。因为enabledRemoteNotificationTypes从iOS 8开始就已经弃用了。对于iOS 8和更高版本，你需要使用isregisteredforremotenotifizations。

—>使用enabledRemoteNotificationTypes >使用isregisteredforremotenotifizations。

quantumpotato的问题:

类型是由

UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];

可以使用

if (types & UIRemoteNotificationTypeAlert)

而不是

if (types == UIRemoteNotificationTypeNone) 

将允许你只检查通知是否启用(不用担心声音，徽章，通知中心等)。第一行代码(types & UIRemoteNotificationTypeAlert)如果“Alert Style”设置为“横幅”或“警报”将返回YES，如果“Alert Style”设置为“None”则返回NO，与其他设置无关。