我正在寻找一种方法来确定用户是否有,通过设置,启用或禁用他们的推送通知我的应用程序。
当前回答
下面是如何在Xamarin.ios中做到这一点。
public class NotificationUtils
{
public static bool AreNotificationsEnabled ()
{
var settings = UIApplication.SharedApplication.CurrentUserNotificationSettings;
var types = settings.Types;
return types != UIUserNotificationType.None;
}
}
如果你支持iOS 10+,只使用UNUserNotificationCenter方法。
其他回答
在最新版本的iOS中,这种方法已被弃用。支持iOS 7和iOS 8使用:
UIApplication *application = [UIApplication sharedApplication];
BOOL enabled;
// Try to use the newer isRegisteredForRemoteNotifications otherwise use the enabledRemoteNotificationTypes.
if ([application respondsToSelector:@selector(isRegisteredForRemoteNotifications)])
{
enabled = [application isRegisteredForRemoteNotifications];
}
else
{
UIRemoteNotificationType types = [application enabledRemoteNotificationTypes];
enabled = types & UIRemoteNotificationTypeAlert;
}
下面是如何在Xamarin.ios中做到这一点。
public class NotificationUtils
{
public static bool AreNotificationsEnabled ()
{
var settings = UIApplication.SharedApplication.CurrentUserNotificationSettings;
var types = settings.Types;
return types != UIUserNotificationType.None;
}
}
如果你支持iOS 10+,只使用UNUserNotificationCenter方法。
swift4.0, iOS11的更新代码
import UserNotifications
UNUserNotificationCenter.current().getNotificationSettings { (settings) in
print("Notification settings: \(settings)")
guard settings.authorizationStatus == .authorized else { return }
//Not authorised
UIApplication.shared.registerForRemoteNotifications()
}
swift3.0, iOS10的代码
let isRegisteredForRemoteNotifications = UIApplication.shared.isRegisteredForRemoteNotifications
if isRegisteredForRemoteNotifications {
// User is registered for notification
} else {
// Show alert user is not registered for notification
}
从iOS9开始,swift 2.0的UIRemoteNotificationType已弃用,请使用以下代码
let notificationType = UIApplication.shared.currentUserNotificationSettings!.types
if notificationType == UIUserNotificationType.none {
// Push notifications are disabled in setting by user.
}else{
// Push notifications are enabled in setting by user.
}
只需检查是否启用了推送通知
if notificationType == UIUserNotificationType.badge {
// the application may badge its icon upon a notification being received
}
if notificationType == UIUserNotificationType.sound {
// the application may play a sound upon a notification being received
}
if notificationType == UIUserNotificationType.alert {
// the application may display an alert upon a notification being received
}
为了完成这个答案,它可以这样工作……
UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];
switch (types) {
case UIRemoteNotificationTypeAlert:
case UIRemoteNotificationTypeBadge:
// For enabled code
break;
case UIRemoteNotificationTypeSound:
case UIRemoteNotificationTypeNone:
default:
// For disabled code
break;
}
编辑:这是不对的。因为这些是位智慧的东西,它不会与开关工作,所以我结束使用这个:
UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];
UIRemoteNotificationType typesset = (UIRemoteNotificationTypeAlert | UIRemoteNotificationTypeBadge);
if((types & typesset) == typesset)
{
CeldaSwitch.chkSwitch.on = true;
}
else
{
CeldaSwitch.chkSwitch.on = false;
}
在尝试同时支持iOS8和更低版本时,我并没有像Kevin建议的那样使用isregisteredforremotenotifations。相反,我使用了currentUserNotificationSettings,它在我的测试中工作得很好。
+ (BOOL)notificationServicesEnabled {
BOOL isEnabled = NO;
if ([[UIApplication sharedApplication] respondsToSelector:@selector(currentUserNotificationSettings)]){
UIUserNotificationSettings *notificationSettings = [[UIApplication sharedApplication] currentUserNotificationSettings];
if (!notificationSettings || (notificationSettings.types == UIUserNotificationTypeNone)) {
isEnabled = NO;
} else {
isEnabled = YES;
}
} else {
UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];
if (types & UIRemoteNotificationTypeAlert) {
isEnabled = YES;
} else{
isEnabled = NO;
}
}
return isEnabled;
}
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