我正在做一些SQL选择查询,并希望将我的UTC日期时间列转换为本地时间,以便在我的查询结果中显示为本地时间。注意,我不希望通过代码进行这种转换,而是当我对我的数据库进行手动和随机SQL查询时。


当前回答

这可以在没有函数的情况下完成。下面的代码将把UTC时间转换为考虑夏令时的山地时间。相应地调整所有的-6和-7数字到您的时区(即对于EST,您将分别调整为-4和-5)

--Adjust a UTC value, in the example the UTC field is identified as UTC.Field, to account for daylight savings time when converting out of UTC to Mountain time.
CASE
    --When it's between March and November, it is summer time which is -6 from UTC
    WHEN MONTH ( UTC.Field ) > 3 AND MONTH ( UTC.Field ) < 11 
        THEN DATEADD ( HOUR , -6 , UTC.Field )
    --When its March and the day is greater than the 14, you know it's summer (-6)
    WHEN MONTH ( UTC.Field ) = 3
        AND DATEPART ( DAY , UTC.Field ) >= 14 
        THEN
            --However, if UTC is before 9am on that Sunday, then it's before 2am Mountain which means it's still Winter daylight time.
            CASE 
                WHEN DATEPART ( WEEKDAY , UTC.Field ) = 1 
                    AND UTC.Field < '9:00'
                    --Before 2am mountain time so it's winter, -7 hours for Winter daylight time
                    THEN DATEADD ( HOUR , -7 , UTC.Field )
                --Otherwise -6 because it'll be after 2am making it Summer daylight time
                ELSE DATEADD ( HOUR , -6 , UTC.Field )
            END
    WHEN MONTH ( UTC.Field ) = 3
        AND ( DATEPART ( WEEKDAY , UTC.Field ) + 7 ) <= DATEPART ( day , UTC.Field ) 
        THEN 
            --According to the date, it's moved onto Summer daylight, but we need to account for the hours leading up to 2am if it's Sunday
            CASE 
                WHEN DATEPART ( WEEKDAY , UTC.Field ) = 1 
                    AND UTC.Field < '9:00'
                    --Before 9am UTC is before 2am Mountain so it's winter Daylight, -7 hours
                    THEN DATEADD ( HOUR , -7 , UTC.Field )
                --Otherwise, it's summer daylight, -6 hours
                ELSE DATEADD ( HOUR , -6 , UTC.Field )
            END
    --When it's November and the weekday is greater than the calendar date, it's still Summer so -6 from the time
    WHEN MONTH ( UTC.Field ) = 11
        AND DATEPART ( WEEKDAY , UTC.Field ) > DATEPART ( DAY , UTC.Field ) 
        THEN DATEADD ( HOUR , -6 , UTC.Field )
    WHEN MONTH ( UTC.Field ) = 11
        AND DATEPART ( WEEKDAY , UTC.Field ) <= DATEPART ( DAY , UTC.Field ) 
            --If the weekday is less than or equal to the calendar day it's Winter daylight but we need to account for the hours leading up to 2am.
            CASE 
                WHEN DATEPART ( WEEKDAY , UTC.Field ) = 1 
                    AND UTC.Field < '8:00'
                    --If it's before 8am UTC and it's Sunday in the logic outlined, then it's still Summer daylight, -6 hours
                    THEN DATEADD ( HOUR , -6 , UTC.Field )
                --Otherwise, adjust for Winter daylight at -7
                ELSE DATEADD ( HOUR , -7 , UTC.Field )
            END
    --If the date doesn't fall into any of the above logic, it's Winter daylight, -7
    ELSE
        DATEADD ( HOUR , -7 , UTC.Field )
END

其他回答

我有代码执行UTC到本地和本地到UTC时间,允许使用这样的代码进行转换

DECLARE @usersTimezone VARCHAR(32)='Europe/London'
DECLARE @utcDT DATETIME=GetUTCDate()
DECLARE @userDT DATETIME=[dbo].[funcUTCtoLocal](@utcDT, @usersTimezone)

and

DECLARE @usersTimezone VARCHAR(32)='Europe/London'
DECLARE @userDT DATETIME=GetDate()
DECLARE @utcDT DATETIME=[dbo].[funcLocaltoUTC](@userDT, @usersTimezone)

这些函数可以支持NodaTime提供的IANA/TZDB中的全部或一部分时区-请参阅https://nodatime.org/TimeZones上的完整列表

请注意,我的用例意味着我只需要一个“当前”窗口,允许在大约+/- 5年的范围内转换时间。这意味着,如果您需要很宽的时间段,我使用的方法可能不适合您,因为它在给定日期范围内为每个时区间隔生成代码的方式不同。

该项目位于GitHub: https://github.com/elliveny/SQLServerTimeConversion

这将生成如下示例所示的SQL函数代码

这样就可以获得与夏令时同步的服务器时间

declare @dt datetime
set @dt = getutcdate() -- GMT equivalent

sysdatetimeoffset会考虑夏令时

select [InputTime] = @dt
       , [LocalTime2] = dateadd(mi, datediff(mi, sysdatetimeoffset(),getdate()), @dt) 

对于Azure SQL和@@Version >= SQL Server 2016用户,下面是一个使用AT TIME ZONE的简单函数。

CREATE FUNCTION [dbo].[Global_Convert_UTCTimeTo_LocalTime]
(
   @LocalTimeZone        VARCHAR(50),
   @UTCDateTime          DATETIME
)
RETURNS DATETIME
AS
BEGIN
   DECLARE @ConvertedDateTime DATETIME;

   SELECT @ConvertedDateTime = @UTCDateTime AT TIME ZONE 'UTC' AT TIME ZONE @LocalTimeZone
   RETURN @ConvertedDateTime

END
GO

对于@LocalTimeZone可以采用的值类型,请转到此链接或转到KEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Windows NT\CurrentVersion\Time Zones

下面是一个将夏令时考虑在内的更简单的例子

CREATE FUNCTION [dbo].[UtcToLocal] 
(
    @p_utcDatetime DATETIME 
)
RETURNS DATETIME
AS
BEGIN
    RETURN DATEADD(MINUTE, DATEDIFF(MINUTE, GETUTCDATE(), @p_utcDatetime), GETDATE())
END

这可以在没有函数的情况下完成。下面的代码将把UTC时间转换为考虑夏令时的山地时间。相应地调整所有的-6和-7数字到您的时区(即对于EST,您将分别调整为-4和-5)

--Adjust a UTC value, in the example the UTC field is identified as UTC.Field, to account for daylight savings time when converting out of UTC to Mountain time.
CASE
    --When it's between March and November, it is summer time which is -6 from UTC
    WHEN MONTH ( UTC.Field ) > 3 AND MONTH ( UTC.Field ) < 11 
        THEN DATEADD ( HOUR , -6 , UTC.Field )
    --When its March and the day is greater than the 14, you know it's summer (-6)
    WHEN MONTH ( UTC.Field ) = 3
        AND DATEPART ( DAY , UTC.Field ) >= 14 
        THEN
            --However, if UTC is before 9am on that Sunday, then it's before 2am Mountain which means it's still Winter daylight time.
            CASE 
                WHEN DATEPART ( WEEKDAY , UTC.Field ) = 1 
                    AND UTC.Field < '9:00'
                    --Before 2am mountain time so it's winter, -7 hours for Winter daylight time
                    THEN DATEADD ( HOUR , -7 , UTC.Field )
                --Otherwise -6 because it'll be after 2am making it Summer daylight time
                ELSE DATEADD ( HOUR , -6 , UTC.Field )
            END
    WHEN MONTH ( UTC.Field ) = 3
        AND ( DATEPART ( WEEKDAY , UTC.Field ) + 7 ) <= DATEPART ( day , UTC.Field ) 
        THEN 
            --According to the date, it's moved onto Summer daylight, but we need to account for the hours leading up to 2am if it's Sunday
            CASE 
                WHEN DATEPART ( WEEKDAY , UTC.Field ) = 1 
                    AND UTC.Field < '9:00'
                    --Before 9am UTC is before 2am Mountain so it's winter Daylight, -7 hours
                    THEN DATEADD ( HOUR , -7 , UTC.Field )
                --Otherwise, it's summer daylight, -6 hours
                ELSE DATEADD ( HOUR , -6 , UTC.Field )
            END
    --When it's November and the weekday is greater than the calendar date, it's still Summer so -6 from the time
    WHEN MONTH ( UTC.Field ) = 11
        AND DATEPART ( WEEKDAY , UTC.Field ) > DATEPART ( DAY , UTC.Field ) 
        THEN DATEADD ( HOUR , -6 , UTC.Field )
    WHEN MONTH ( UTC.Field ) = 11
        AND DATEPART ( WEEKDAY , UTC.Field ) <= DATEPART ( DAY , UTC.Field ) 
            --If the weekday is less than or equal to the calendar day it's Winter daylight but we need to account for the hours leading up to 2am.
            CASE 
                WHEN DATEPART ( WEEKDAY , UTC.Field ) = 1 
                    AND UTC.Field < '8:00'
                    --If it's before 8am UTC and it's Sunday in the logic outlined, then it's still Summer daylight, -6 hours
                    THEN DATEADD ( HOUR , -6 , UTC.Field )
                --Otherwise, adjust for Winter daylight at -7
                ELSE DATEADD ( HOUR , -7 , UTC.Field )
            END
    --If the date doesn't fall into any of the above logic, it's Winter daylight, -7
    ELSE
        DATEADD ( HOUR , -7 , UTC.Field )
END