摘自http://java.com/js/deployJava.js:

    // return true if 'installed' (considered as a JRE version string) is
    // greater than or equal to 'required' (again, a JRE version string).
    compareVersions: function (installed, required) {

        var a = installed.split('.');
        var b = required.split('.');

        for (var i = 0; i < a.length; ++i) {
            a[i] = Number(a[i]);
        }
        for (var i = 0; i < b.length; ++i) {
            b[i] = Number(b[i]);
        }
        if (a.length == 2) {
            a[2] = 0;
        }

        if (a[0] > b[0]) return true;
        if (a[0] < b[0]) return false;

        if (a[1] > b[1]) return true;
        if (a[1] < b[1]) return false;

        if (a[2] > b[2]) return true;
        if (a[2] < b[2]) return false;

        return true;
    }

如果不允许使用字母或符号，那么代码行数就很少。如果您控制了版本控制方案，并且不是第三方提供的，那么这种方法是有效的。

// we presume all versions are of this format "1.4" or "1.10.2.3", without letters // returns: 1 (bigger), 0 (same), -1 (smaller) function versionCompare (v1, v2) { const v1Parts = v1.split('.') const v2Parts = v2.split('.') const length = Math.max(v1Parts.length, v2Parts.length) for (let i = 0; i < length; i++) { const value = (parseInt(v1Parts[i]) || 0) - (parseInt(v2Parts[i]) || 0) if (value < 0) return -1 if (value > 0) return 1 } return 0 } console.log(versionCompare('1.2.0', '1.2.4') === -1) console.log(versionCompare('1.2', '1.2.0') === 0) console.log(versionCompare('1.2', '1') === 1) console.log(versionCompare('1.2.10', '1.2.1') === 1) console.log(versionCompare('1.2.134230', '1.2.2') === 1) console.log(versionCompare('1.2.134230', '1.3.0.1.2.3.1') === -1)

我也遇到过类似的问题，而且我已经为它创建了一个解决方案。你可以试一试。

如果等于则返回0，如果版本号大于则返回1，如果版本号小于则返回-1

function compareVersion(currentVersion, minVersion) { let current = currentVersion.replace(/\./g," .").split(' ').map(x=>parseFloat(x,10)) let min = minVersion.replace(/\./g," .").split(' ').map(x=>parseFloat(x,10)) for(let i = 0; i < Math.max(current.length, min.length); i++) { if((current[i] || 0) < (min[i] || 0)) { return -1 } else if ((current[i] || 0) > (min[i] || 0)) { return 1 } } return 0 } console.log(compareVersion("81.0.1212.121","80.4.1121.121")); console.log(compareVersion("81.0.1212.121","80.4.9921.121")); console.log(compareVersion("80.0.1212.121","80.4.9921.121")); console.log(compareVersion("4.4.0","4.4.1")); console.log(compareVersion("5.24","5.2")); console.log(compareVersion("4.1","4.1.2")); console.log(compareVersion("4.1.2","4.1")); console.log(compareVersion("4.4.4.4","4.4.4.4.4")); console.log(compareVersion("4.4.4.4.4.4","4.4.4.4.4")); console.log(compareVersion("0","1")); console.log(compareVersion("1","1")); console.log(compareVersion("1","1.0.00000.0000")); console.log(compareVersion("","1")); console.log(compareVersion("10.0.1","10.1"));

2017答:

v1 = '20.0.12'; 
v2 = '3.123.12';

compareVersions(v1,v2) 
// return positive: v1 > v2, zero:v1 == v2, negative: v1 < v2 
function compareVersions(v1, v2) {
        v1= v1.split('.')
        v2= v2.split('.')
        var len = Math.max(v1.length,v2.length)
        /*default is true*/
        for( let i=0; i < len; i++)
            v1 = Number(v1[i] || 0);
            v2 = Number(v2[i] || 0);
            if (v1 !== v2) return v1 - v2 ;
            i++;
        }
        return 0;
    }

最简单的现代浏览器代码:

 function compareVersion2(ver1, ver2) {
      ver1 = ver1.split('.').map( s => s.padStart(10) ).join('.');
      ver2 = ver2.split('.').map( s => s.padStart(10) ).join('.');
      return ver1 <= ver2;
 }

这里的想法是比较数字，但以字符串的形式。为了使比较工作，两个字符串必须在相同的长度。所以:

"123" > "99"变成"123" > "099" 填充短数字“修复”比较

这里我用0填充每个部分，长度为10。然后使用简单的字符串比较来得到答案

例子:

var ver1 = '0.2.10', ver2=`0.10.2`
//become 
ver1 = '0000000000.0000000002.0000000010'
ver2 = '0000000000.0000000010.0000000002'
// then it easy to see that
ver1 <= ver2 // true

replace()函数只替换字符串中的第一个出现项。我们来替换。与,。然后全部删除。然后做，to。再次将其解析为float。

for(i=0; i<versions.length; i++) {
    v = versions[i].replace('.', ',');
    v = v.replace(/\./g, '');
    versions[i] = parseFloat(v.replace(',', '.'));
}

最后，排序:

versions.sort();

// Return 1 if a > b
// Return -1 if a < b
// Return 0 if a == b
function compare(a, b) {
    if (a === b) {
       return 0;
    }

    var a_components = a.split(".");
    var b_components = b.split(".");

    var len = Math.min(a_components.length, b_components.length);

    // loop while the components are equal
    for (var i = 0; i < len; i++) {
        // A bigger than B
        if (parseInt(a_components[i]) > parseInt(b_components[i])) {
            return 1;
        }

        // B bigger than A
        if (parseInt(a_components[i]) < parseInt(b_components[i])) {
            return -1;
        }
    }

    // If one's a prefix of the other, the longer one is greater.
    if (a_components.length > b_components.length) {
        return 1;
    }

    if (a_components.length < b_components.length) {
        return -1;
    }

    // Otherwise they are the same.
    return 0;
}

console.log(compare("1", "2"));
console.log(compare("2", "1"));

console.log(compare("1.0", "1.0"));
console.log(compare("2.0", "1.0"));
console.log(compare("1.0", "2.0"));
console.log(compare("1.0.1", "1.0"));