以下是软件版本号:

"1.0", "1.0.1", "2.0", "2.0.0.1", "2.0.1"

我怎么比较呢?

假设正确的顺序是:

"1.0", "1.0.1", "2.0", "2.0.0.1", "2.0.1"

想法很简单… 读第一个数字,然后,第二个,第三个… 但是我不能将版本号转换为浮点数… 你也可以像这样看到版本号:

"1.0.0.0", "1.0.1.0", "2.0.0.0", "2.0.0.1", "2.0.1.0"

这样可以更清楚地看到背后的想法。 但是,我怎样才能把它转换成计算机程序呢?


当前回答

下面是另一个简短的版本,适用于任何数量的子版本,填充零和偶数字母(1.0.0b3)

const compareVer = ((prep, repl) =>
{
  prep = t => ("" + t)
      //treat non-numerical characters as lower version
      //replacing them with a negative number based on charcode of first character
    .replace(/[^0-9\.]+/g, c => "." + (c.replace(/[\W_]+/, "").toLowerCase().charCodeAt(0) - 65536) + ".")
      //remove trailing "." and "0" if followed by non-numerical characters (1.0.0b);
    .replace(/(?:\.0+)*(\.-[0-9]+)(\.[0-9]+)?\.*$/g, "$1$2")
    .split('.');

  return (a, b, c, i, r) =>
  {
    a = prep(a);
    b = prep(b);
    for (i = 0, r = 0, c = Math.max(a.length, b.length); !r && i++ < c;)
    {
      r = -1 * ((a[i] = ~~a[i]) < (b[i] = ~~b[i])) + (a[i] > b[i]);
    }
    return r;
  }
})();

函数返回:

如果a = b则为0

1如果a > b

-1如果a < b

1.0         = 1.0.0.0.0.0
1.0         < 1.0.1
1.0b1       < 1.0
1.0b        = 1.0b
1.1         > 1.0.1b
1.1alpha    < 1.1beta
1.1rc1      > 1.1beta
1.1rc1      < 1.1rc2
1.1.0a1     < 1.1a2
1.1.0a10    > 1.1.0a1
1.1.0alpha  = 1.1a
1.1.0alpha2 < 1.1b1
1.0001      > 1.00000.1.0.0.0.01

/*use strict*/ const compareVer = ((prep, repl) => { prep = t => ("" + t) //treat non-numerical characters as lower version //replacing them with a negative number based on charcode of first character .replace(/[^0-9\.]+/g, c => "." + (c.replace(/[\W_]+/, "").toLowerCase().charCodeAt(0) - 65536) + ".") //remove trailing "." and "0" if followed by non-numerical characters (1.0.0b); .replace(/(?:\.0+)*(\.-[0-9]+)(\.[0-9]+)?\.*$/g, "$1$2") .split('.'); return (a, b, c, i, r) => { a = prep(a); b = prep(b); for (i = 0, r = 0, c = Math.max(a.length, b.length); !r && i++ < c;) { r = -1 * ((a[i] = ~~a[i]) < (b[i] = ~~b[i])) + (a[i] > b[i]); } return r; } })(); //examples let list = [ ["1.0", "1.0.0.0.0.0"], ["1.0", "1.0.1"], ["1.0b1", "1.0"], ["1.0b", "1.0b"], ["1.1", "1.0.1b"], ["1.1alpha", "1.1beta"], ["1.1rc1", "1.1beta"], ["1.1rc1", "1.1rc2"], ["1.1.0a1", "1.1a2"], ["1.1.0a10", "1.1.0a1"], ["1.1.0alpha", "1.1a"], ["1.1.0alpha2", "1.1b1"], ["1.0001", "1.00000.1.0.0.0.01"] ] for(let i = 0; i < list.length; i++) { console.log( list[i][0] + " " + "<=>"[compareVer(list[i][0], list[i][1]) + 1] + " " + list[i][1] ); }

https://jsfiddle.net/vanowm/p7uvtbor/

其他回答

你可以遍历每个以句点分隔的字符并将其转换为int类型:

var parts = versionString.split('.');

for (var i = 0; i < parts.length; i++) {
  var value = parseInt(parts[i]);
  // do stuffs here.. perhaps build a numeric version variable?
}

我已经创建了这个解决方案,我希望你觉得它有用:

https://runkit.com/ecancino/5f3c6c59593d23001485992e


const quantify = max => (n, i) => n * (+max.slice(0, max.length - i))

const add = (a, b) => a + b

const calc = s => s.
    split('.').
    map(quantify('1000000')).
    reduce(add, 0)

const sortVersions = unsortedVersions => unsortedVersions
    .map(version => ({ version, order: calc(version) }))
    .sort((a, b) => a.order - b.order)
    .reverse()
    .map(o => o.version)

我找到了最简单的方法来比较它们,但我不确定这是否是你想要的。

当我在控制台中运行下面的代码时,它是有意义的,并且使用sort()方法,我可以获得版本字符串的排序数组。它是根据字母顺序排列的。

"1.0" < "1.0.1" //true
var arr = ["1.0.1", "1.0", "3.2.0", "1.3"]
arr.sort();     //["1.0", "1.0.1", "1.3", "3.2.0"]

下面是另一个简短的版本,适用于任何数量的子版本,填充零和偶数字母(1.0.0b3)

const compareVer = ((prep, repl) =>
{
  prep = t => ("" + t)
      //treat non-numerical characters as lower version
      //replacing them with a negative number based on charcode of first character
    .replace(/[^0-9\.]+/g, c => "." + (c.replace(/[\W_]+/, "").toLowerCase().charCodeAt(0) - 65536) + ".")
      //remove trailing "." and "0" if followed by non-numerical characters (1.0.0b);
    .replace(/(?:\.0+)*(\.-[0-9]+)(\.[0-9]+)?\.*$/g, "$1$2")
    .split('.');

  return (a, b, c, i, r) =>
  {
    a = prep(a);
    b = prep(b);
    for (i = 0, r = 0, c = Math.max(a.length, b.length); !r && i++ < c;)
    {
      r = -1 * ((a[i] = ~~a[i]) < (b[i] = ~~b[i])) + (a[i] > b[i]);
    }
    return r;
  }
})();

函数返回:

如果a = b则为0

1如果a > b

-1如果a < b

1.0         = 1.0.0.0.0.0
1.0         < 1.0.1
1.0b1       < 1.0
1.0b        = 1.0b
1.1         > 1.0.1b
1.1alpha    < 1.1beta
1.1rc1      > 1.1beta
1.1rc1      < 1.1rc2
1.1.0a1     < 1.1a2
1.1.0a10    > 1.1.0a1
1.1.0alpha  = 1.1a
1.1.0alpha2 < 1.1b1
1.0001      > 1.00000.1.0.0.0.01

/*use strict*/ const compareVer = ((prep, repl) => { prep = t => ("" + t) //treat non-numerical characters as lower version //replacing them with a negative number based on charcode of first character .replace(/[^0-9\.]+/g, c => "." + (c.replace(/[\W_]+/, "").toLowerCase().charCodeAt(0) - 65536) + ".") //remove trailing "." and "0" if followed by non-numerical characters (1.0.0b); .replace(/(?:\.0+)*(\.-[0-9]+)(\.[0-9]+)?\.*$/g, "$1$2") .split('.'); return (a, b, c, i, r) => { a = prep(a); b = prep(b); for (i = 0, r = 0, c = Math.max(a.length, b.length); !r && i++ < c;) { r = -1 * ((a[i] = ~~a[i]) < (b[i] = ~~b[i])) + (a[i] > b[i]); } return r; } })(); //examples let list = [ ["1.0", "1.0.0.0.0.0"], ["1.0", "1.0.1"], ["1.0b1", "1.0"], ["1.0b", "1.0b"], ["1.1", "1.0.1b"], ["1.1alpha", "1.1beta"], ["1.1rc1", "1.1beta"], ["1.1rc1", "1.1rc2"], ["1.1.0a1", "1.1a2"], ["1.1.0a10", "1.1.0a1"], ["1.1.0alpha", "1.1a"], ["1.1.0alpha2", "1.1b1"], ["1.0001", "1.00000.1.0.0.0.01"] ] for(let i = 0; i < list.length; i++) { console.log( list[i][0] + " " + "<=>"[compareVer(list[i][0], list[i][1]) + 1] + " " + list[i][1] ); }

https://jsfiddle.net/vanowm/p7uvtbor/

semver

npm使用的语义版本解析器。

$ npm install semver
var semver = require('semver');

semver.diff('3.4.5', '4.3.7') //'major'
semver.diff('3.4.5', '3.3.7') //'minor'
semver.gte('3.4.8', '3.4.7') //true
semver.ltr('3.4.8', '3.4.7') //false

semver.valid('1.2.3') // '1.2.3'
semver.valid('a.b.c') // null
semver.clean(' =v1.2.3 ') // '1.2.3'
semver.satisfies('1.2.3', '1.x || >=2.5.0 || 5.0.0 - 7.2.3') // true
semver.gt('1.2.3', '9.8.7') // false
semver.lt('1.2.3', '9.8.7') // true

var versions = [ '1.2.3', '3.4.5', '1.0.2' ]
var max = versions.sort(semver.rcompare)[0]
var min = versions.sort(semver.compare)[0]
var max = semver.maxSatisfying(versions, '*')

语义版本控制链接:https://www.npmjs.com/package/semver#prerelease-identifiers