Waleed Eissa代码的逆函数（十六进制字符串到字节数组）：

    public static byte[] HexToBytes(this string hexString)        
    {
        byte[] b = new byte[hexString.Length / 2];            
        char c;
        for (int i = 0; i < hexString.Length / 2; i++)
        {
            c = hexString[i * 2];
            b[i] = (byte)((c < 0x40 ? c - 0x30 : (c < 0x47 ? c - 0x37 : c - 0x57)) << 4);
            c = hexString[i * 2 + 1];
            b[i] += (byte)(c < 0x40 ? c - 0x30 : (c < 0x47 ? c - 0x37 : c - 0x57));
        }

        return b;
    }

Waleed Eissa功能，支持小写：

    public static string BytesToHex(this byte[] barray, bool toLowerCase = true)
    {
        byte addByte = 0x37;
        if (toLowerCase) addByte = 0x57;
        char[] c = new char[barray.Length * 2];
        byte b;
        for (int i = 0; i < barray.Length; ++i)
        {
            b = ((byte)(barray[i] >> 4));
            c[i * 2] = (char)(b > 9 ? b + addByte : b + 0x30);
            b = ((byte)(barray[i] & 0xF));
            c[i * 2 + 1] = (char)(b > 9 ? b + addByte : b + 0x30);
        }

        return new string(c);
    }

我猜它的速度值16个额外的字节。

    static char[] hexes = new char[]{'0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F'};
    public static string ToHexadecimal (this byte[] Bytes)
    {
        char[] Result = new char[Bytes.Length << 1];
        int Offset = 0;
        for (int i = 0; i != Bytes.Length; i++) {
            Result[Offset++] = hexes[Bytes[i] >> 4];
            Result[Offset++] = hexes[Bytes[i] & 0x0F];
        }
        return new string(Result);
    }

如果您希望比BitConverter更灵活，但不希望使用那些笨重的90年代风格的显式循环，那么您可以这样做：

String.Join(String.Empty, Array.ConvertAll(bytes, x => x.ToString("X2")));

或者，如果您使用的是.NET 4.0：

String.Concat(Array.ConvertAll(bytes, x => x.ToString("X2")));

（后者来自对原帖子的评论。）

    // a safe version of the lookup solution:       

    public static string ByteArrayToHexViaLookup32Safe(byte[] bytes, bool withZeroX)
    {
        if (bytes.Length == 0)
        {
            return withZeroX ? "0x" : "";
        }

        int length = bytes.Length * 2 + (withZeroX ? 2 : 0);
        StateSmall stateToPass = new StateSmall(bytes, withZeroX);
        return string.Create(length, stateToPass, (chars, state) =>
        {
            int offset0x = 0;
            if (state.WithZeroX)
            {
                chars[0] = '0';
                chars[1] = 'x';
                offset0x += 2;
            }

            Span<uint> charsAsInts = MemoryMarshal.Cast<char, uint>(chars.Slice(offset0x));
            int targetLength = state.Bytes.Length;
            for (int i = 0; i < targetLength; i += 1)
            {
                uint val = Lookup32[state.Bytes[i]];
                charsAsInts[i] = val;
            }
        });
    }

    private struct StateSmall
    {
        public StateSmall(byte[] bytes, bool withZeroX)
        {
            Bytes = bytes;
            WithZeroX = withZeroX;
        }

        public byte[] Bytes;
        public bool WithZeroX;
    }

测试：十六进制字符串到字节数组

我注意到，大多数测试都是在将Bytes数组转换为十六进制字符串的函数上执行的。因此，在这篇文章中，我将关注另一方面：将十六进制字符串转换为字节数组的函数。若您只对结果感兴趣，可以跳到“摘要”部分。测试代码文件在文章末尾提供。

标签

我想根据接受的答案（Tomalak）将函数命名为StringToByteArrayV1，或将其快捷到V1。其余函数将以相同的方式命名：V2、V3、V4、…、。。。，等

参与功能索引

Tomalak的StringToByteArrayV1（公认答案）Mykroft的StringToByteArrayV2（使用SoapHexBinary）drphrozen的StringToByteArrayV3（查找表）CoperNick的StringToByteArrayV4（字节操作）Chris F编写的StringToByteArrayV5_1（字节操作）Chris F的StringToByteArrayV5_2（V5_1+根据Amir Rezaei的评论修改）Chris F的StringToByteArrayV5_3（V5_2+根据Ben Voigt的评论对其进行了修改）（您可以在发布后的测试代码中看到它的最终形状）Ben Mosher编写的StringToByteArrayV6（字节操作）Maratius的StringToByteArrayV7（字节操作-安全版本）Maratius的StringToByteArrayV8（字节操作-不安全版本）StringToByteArrayV9（按Geograph）AlejandroAlis编写的StringToByteArrayV10Fredrik Hu编写的StringToByteArrayV11Maarten Bodewes编写的StringToByteArrayV12ClausAndersen编写的StringToByteArrayV13Stas Makutin编写的StringToByteArrayV14JJJ的StringToByteArrayV15JamieSee的StringToByteArrayV16spacepille的StringToByteArrayV17Gregory Morse编写的StringToByteArrayV18Rick编写的StringToByteArrayV19SandRock的StringToByteArrayV20Paul编写的StringToByteArrayV21

正确性测试

我通过传递1字节的所有256个可能值来测试正确性，然后检查输出是否正确。结果：

V18中以“00”开头的字符串有问题（请参阅Roger Stewart对此的评论）。除了通过所有测试。如果十六进制字符串字母是大写的：所有函数都成功传递如果十六进制字符串字母是小写的，则以下函数失败：V5_1、V5_2、v7、V8、V15、V19

注：V5_3解决了这个问题（V5_1和V5_2）

性能测试

我已经使用Stopwatch类进行了性能测试。

长字符串的性能

input length: 10,000,000 bytes
runs: 100
average elapsed time per run:
V1 = 136.4ms
V2 = 104.5ms
V3 = 22.0ms
V4 = 9.9ms
V5_1 = 10.2ms
V5_2 = 9.0ms
V5_3 = 9.3ms
V6 = 18.3ms
V7 = 9.8ms
V8 = 8.8ms
V9 = 10.2ms
V10 = 19.0ms
V11 = 12.2ms
V12 = 27.4ms
V13 = 21.8ms
V14 = 12.0ms
V15 = 14.9ms
V16 = 15.3ms
V17 = 9.5ms
V18 got excluded from this test, because it was very slow when using very long string
V19 = 222.8ms
V20 = 66.0ms
V21 = 15.4ms

V1 average ticks per run: 1363529.4
V2 is more fast than V1 by: 1.3 times (ticks ratio)
V3 is more fast than V1 by: 6.2 times (ticks ratio)
V4 is more fast than V1 by: 13.8 times (ticks ratio)
V5_1 is more fast than V1 by: 13.3 times (ticks ratio)
V5_2 is more fast than V1 by: 15.2 times (ticks ratio)
V5_3 is more fast than V1 by: 14.8 times (ticks ratio)
V6 is more fast than V1 by: 7.4 times (ticks ratio)
V7 is more fast than V1 by: 13.9 times (ticks ratio)
V8 is more fast than V1 by: 15.4 times (ticks ratio)
V9 is more fast than V1 by: 13.4 times (ticks ratio)
V10 is more fast than V1 by: 7.2 times (ticks ratio)
V11 is more fast than V1 by: 11.1 times (ticks ratio)
V12 is more fast than V1 by: 5.0 times (ticks ratio)
V13 is more fast than V1 by: 6.3 times (ticks ratio)
V14 is more fast than V1 by: 11.4 times (ticks ratio)
V15 is more fast than V1 by: 9.2 times (ticks ratio)
V16 is more fast than V1 by: 8.9 times (ticks ratio)
V17 is more fast than V1 by: 14.4 times (ticks ratio)
V19 is more SLOW than V1 by: 1.6 times (ticks ratio)
V20 is more fast than V1 by: 2.1 times (ticks ratio)
V21 is more fast than V1 by: 8.9 times (ticks ratio)

V18的长串性能

V18 took long time at the previous test, 
so let's decrease length for it:  
input length: 1,000,000 bytes
runs: 100
average elapsed time per run: V1 = 14.1ms , V18 = 146.7ms
V1 average ticks per run: 140630.3
V18 is more SLOW than V1 by: 10.4 times (ticks ratio)

短字符串的性能

input length: 100 byte
runs: 1,000,000
V1 average ticks per run: 14.6
V2 is more fast than V1 by: 1.4 times (ticks ratio)
V3 is more fast than V1 by: 5.9 times (ticks ratio)
V4 is more fast than V1 by: 15.7 times (ticks ratio)
V5_1 is more fast than V1 by: 15.1 times (ticks ratio)
V5_2 is more fast than V1 by: 18.4 times (ticks ratio)
V5_3 is more fast than V1 by: 16.3 times (ticks ratio)
V6 is more fast than V1 by: 5.3 times (ticks ratio)
V7 is more fast than V1 by: 15.7 times (ticks ratio)
V8 is more fast than V1 by: 18.0 times (ticks ratio)
V9 is more fast than V1 by: 15.5 times (ticks ratio)
V10 is more fast than V1 by: 7.8 times (ticks ratio)
V11 is more fast than V1 by: 12.4 times (ticks ratio)
V12 is more fast than V1 by: 5.3 times (ticks ratio)
V13 is more fast than V1 by: 5.2 times (ticks ratio)
V14 is more fast than V1 by: 13.4 times (ticks ratio)
V15 is more fast than V1 by: 9.9 times (ticks ratio)
V16 is more fast than V1 by: 9.2 times (ticks ratio)
V17 is more fast than V1 by: 16.2 times (ticks ratio)
V18 is more fast than V1 by: 1.1 times (ticks ratio)
V19 is more SLOW than V1 by: 1.6 times (ticks ratio)
V20 is more fast than V1 by: 1.9 times (ticks ratio)
V21 is more fast than V1 by: 11.4 times (ticks ratio)

测试代码

在使用以下代码之前，最好先阅读本文下面的免责声明部分https://github.com/Ghosticollis/performance-tests/blob/main/MTestPerformance.cs

总结

由于性能良好，我建议使用以下函数之一，并支持大写和小写：

CoperNick的StringToByteArrayV4StringToByteArrayV9（按Geograph）spacepille的StringToByteArrayV17StringToByteArrayV5_3基本上由Chris F开发（它基于V5_1，但我根据Amir Rezaei和Ben Voigt的评论对其进行了增强）。

以下是V5_3的最终形状：

static byte[] HexStringToByteArrayV5_3(string hexString) {
    int hexStringLength = hexString.Length;
    byte[] b = new byte[hexStringLength / 2];
    for (int i = 0; i < hexStringLength; i += 2) {
        int topChar = hexString[i];
        topChar = (topChar > 0x40 ? (topChar & ~0x20) - 0x37 : topChar - 0x30) << 4;
        int bottomChar = hexString[i + 1];
        bottomChar = bottomChar > 0x40 ? (bottomChar & ~0x20) - 0x37 : bottomChar - 0x30;
        b[i / 2] = (byte)(topChar + bottomChar);
    }
    return b;
}

免责声明

警告：我没有适当的测试知识。这些原始测试的主要目的是快速概述所有发布的函数的优点。如果您需要准确的结果，请使用适当的测试工具。

最后，我想说，我是新来的，在斯塔科弗洛活跃，如果我的职位空缺，我很抱歉。如果您能发表评论，我们将不胜感激。

支持最短路径和.net核心：

    public static string BytesToString(byte[] ba) =>
        ba.Aggregate(new StringBuilder(32), (sb, b) => sb.Append(b.ToString("X2"))).ToString();