如何将字节数组转换为十六进制字符串,反之亦然?
当前回答
这里不想赘述很多答案,但我发现了一个十六进制字符串解析器的相当优化(比公认的好4.5倍)、简单的实现。首先,我的测试输出(第一批是我的实现):
Give me that string:
04c63f7842740c77e545bb0b2ade90b384f119f6ab57b680b7aa575a2f40939f
Time to parse 100,000 times: 50.4192 ms
Result as base64: BMY/eEJ0DHflRbsLKt6Qs4TxGfarV7aAt6pXWi9Ak58=
BitConverter'd: 04-C6-3F-78-42-74-0C-77-E5-45-BB-0B-2A-DE-90-B3-84-F1-19-F6-AB-5
7-B6-80-B7-AA-57-5A-2F-40-93-9F
Accepted answer: (StringToByteArray)
Time to parse 100000 times: 233.1264ms
Result as base64: BMY/eEJ0DHflRbsLKt6Qs4TxGfarV7aAt6pXWi9Ak58=
BitConverter'd: 04-C6-3F-78-42-74-0C-77-E5-45-BB-0B-2A-DE-90-B3-84-F1-19-F6-AB-5
7-B6-80-B7-AA-57-5A-2F-40-93-9F
With Mono's implementation:
Time to parse 100000 times: 777.2544ms
Result as base64: BMY/eEJ0DHflRbsLKt6Qs4TxGfarV7aAt6pXWi9Ak58=
BitConverter'd: 04-C6-3F-78-42-74-0C-77-E5-45-BB-0B-2A-DE-90-B3-84-F1-19-F6-AB-5
7-B6-80-B7-AA-57-5A-2F-40-93-9F
With SoapHexBinary:
Time to parse 100000 times: 845.1456ms
Result as base64: BMY/eEJ0DHflRbsLKt6Qs4TxGfarV7aAt6pXWi9Ak58=
BitConverter'd: 04-C6-3F-78-42-74-0C-77-E5-45-BB-0B-2A-DE-90-B3-84-F1-19-F6-AB-5
7-B6-80-B7-AA-57-5A-2F-40-93-9F
base64和“BitConverter'd”行用于测试正确性。请注意,它们是相等的。
实施:
public static byte[] ToByteArrayFromHex(string hexString)
{
if (hexString.Length % 2 != 0) throw new ArgumentException("String must have an even length");
var array = new byte[hexString.Length / 2];
for (int i = 0; i < hexString.Length; i += 2)
{
array[i/2] = ByteFromTwoChars(hexString[i], hexString[i + 1]);
}
return array;
}
private static byte ByteFromTwoChars(char p, char p_2)
{
byte ret;
if (p <= '9' && p >= '0')
{
ret = (byte) ((p - '0') << 4);
}
else if (p <= 'f' && p >= 'a')
{
ret = (byte) ((p - 'a' + 10) << 4);
}
else if (p <= 'F' && p >= 'A')
{
ret = (byte) ((p - 'A' + 10) << 4);
} else throw new ArgumentException("Char is not a hex digit: " + p,"p");
if (p_2 <= '9' && p_2 >= '0')
{
ret |= (byte) ((p_2 - '0'));
}
else if (p_2 <= 'f' && p_2 >= 'a')
{
ret |= (byte) ((p_2 - 'a' + 10));
}
else if (p_2 <= 'F' && p_2 >= 'A')
{
ret |= (byte) ((p_2 - 'A' + 10));
} else throw new ArgumentException("Char is not a hex digit: " + p_2, "p_2");
return ret;
}
我尝试了一些不安全的东西,并将(显然是冗余的)字符移动到另一个方法来蚕食if序列,但这是最快的。
(我承认这回答了一半的问题。我觉得字符串->字节[]转换不足,而字节[]->字符串角度似乎被很好地覆盖了。因此,这个答案。)
其他回答
我将参加这个比特拨弄比赛,因为我有一个同样使用比特拨弄来解码十六进制的答案。请注意,使用字符数组可能会更快,因为调用StringBuilder方法也需要时间。
public static String ToHex (byte[] data)
{
int dataLength = data.Length;
// pre-create the stringbuilder using the length of the data * 2, precisely enough
StringBuilder sb = new StringBuilder (dataLength * 2);
for (int i = 0; i < dataLength; i++) {
int b = data [i];
// check using calculation over bits to see if first tuple is a letter
// isLetter is zero if it is a digit, 1 if it is a letter
int isLetter = (b >> 7) & ((b >> 6) | (b >> 5)) & 1;
// calculate the code using a multiplication to make up the difference between
// a digit character and an alphanumerical character
int code = '0' + ((b >> 4) & 0xF) + isLetter * ('A' - '9' - 1);
// now append the result, after casting the code point to a character
sb.Append ((Char)code);
// do the same with the lower (less significant) tuple
isLetter = (b >> 3) & ((b >> 2) | (b >> 1)) & 1;
code = '0' + (b & 0xF) + isLetter * ('A' - '9' - 1);
sb.Append ((Char)code);
}
return sb.ToString ();
}
public static byte[] FromHex (String hex)
{
// pre-create the array
int resultLength = hex.Length / 2;
byte[] result = new byte[resultLength];
// set validity = 0 (0 = valid, anything else is not valid)
int validity = 0;
int c, isLetter, value, validDigitStruct, validDigit, validLetterStruct, validLetter;
for (int i = 0, hexOffset = 0; i < resultLength; i++, hexOffset += 2) {
c = hex [hexOffset];
// check using calculation over bits to see if first char is a letter
// isLetter is zero if it is a digit, 1 if it is a letter (upper & lowercase)
isLetter = (c >> 6) & 1;
// calculate the tuple value using a multiplication to make up the difference between
// a digit character and an alphanumerical character
// minus 1 for the fact that the letters are not zero based
value = ((c & 0xF) + isLetter * (-1 + 10)) << 4;
// check validity of all the other bits
validity |= c >> 7; // changed to >>, maybe not OK, use UInt?
validDigitStruct = (c & 0x30) ^ 0x30;
validDigit = ((c & 0x8) >> 3) * (c & 0x6);
validity |= (isLetter ^ 1) * (validDigitStruct | validDigit);
validLetterStruct = c & 0x18;
validLetter = (((c - 1) & 0x4) >> 2) * ((c - 1) & 0x2);
validity |= isLetter * (validLetterStruct | validLetter);
// do the same with the lower (less significant) tuple
c = hex [hexOffset + 1];
isLetter = (c >> 6) & 1;
value ^= (c & 0xF) + isLetter * (-1 + 10);
result [i] = (byte)value;
// check validity of all the other bits
validity |= c >> 7; // changed to >>, maybe not OK, use UInt?
validDigitStruct = (c & 0x30) ^ 0x30;
validDigit = ((c & 0x8) >> 3) * (c & 0x6);
validity |= (isLetter ^ 1) * (validDigitStruct | validDigit);
validLetterStruct = c & 0x18;
validLetter = (((c - 1) & 0x4) >> 2) * ((c - 1) & 0x2);
validity |= isLetter * (validLetterStruct | validLetter);
}
if (validity != 0) {
throw new ArgumentException ("Hexadecimal encoding incorrect for input " + hex);
}
return result;
}
从Java代码转换而来。
用@CodesInChaus补充答案(反向方法)
public static byte[] HexToByteUsingByteManipulation(string s)
{
byte[] bytes = new byte[s.Length / 2];
for (int i = 0; i < bytes.Length; i++)
{
int hi = s[i*2] - 65;
hi = hi + 10 + ((hi >> 31) & 7);
int lo = s[i*2 + 1] - 65;
lo = lo + 10 + ((lo >> 31) & 7) & 0x0f;
bytes[i] = (byte) (lo | hi << 4);
}
return bytes;
}
说明:
&0x0f还支持小写字母
hi=hi+10+((hi>>31)&7);与以下内容相同:
hi=ch-65+10+((ch-65)>>31)&7);
对于“0”9’与hi=ch-65+10+7相同;其为hi=ch-48(这是因为0xffffff&7)。
对于“A”F’为hi=ch-65+10;(这是因为0x00000000&7)。
对于“a”我们必须使用大数字,所以我们必须通过使用&0x0f使某些位为0,从默认版本中减去32。
65是“A”的代码
48是“0”的代码
7是ASCII表中“9”和“A”之间的字母数(…456789:;<=>?@ABCD…)。
为了方便以后复制和粘贴,将几个答案合并到一个类中:
/// <summary>
/// Extension methods to quickly convert byte array to string and back.
/// </summary>
public static class HexConverter
{
/// <summary>
/// Map values to hex digits
/// </summary>
private static readonly char[] HexDigits =
{
'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F'
};
/// <summary>
/// Map 56 characters between ['0', 'F'] to their hex equivalents, and set invalid characters
/// such that they will overflow byte to fail conversion.
/// </summary>
private static readonly ushort[] HexValues =
{
0x0000, 0x0001, 0x0002, 0x0003, 0x0004, 0x0005, 0x0006, 0x0007, 0x0008, 0x0009, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100,
0x000A, 0x000B, 0x000C, 0x000D, 0x000E, 0x000F, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100,
0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x000A, 0x000B,
0x000C, 0x000D, 0x000E, 0x000F
};
/// <summary>
/// Empty byte array
/// </summary>
private static readonly byte[] Empty = new byte[0];
/// <summary>
/// Convert a byte array to a hexadecimal string.
/// </summary>
/// <param name="bytes">
/// The input byte array.
/// </param>
/// <returns>
/// A string of hexadecimal digits.
/// </returns>
public static string ToHexString(this byte[] bytes)
{
var c = new char[bytes.Length * 2];
for (int i = 0, j = 0; i < bytes.Length; i++)
{
c[j++] = HexDigits[bytes[i] >> 4];
c[j++] = HexDigits[bytes[i] & 0x0F];
}
return new string(c);
}
/// <summary>
/// Parse a string of hexadecimal digits into a byte array.
/// </summary>
/// <param name="hexadecimalString">
/// The hexadecimal string.
/// </param>
/// <returns>
/// The parsed <see cref="byte[]"/> array.
/// </returns>
/// <exception cref="ArgumentException">
/// The input string either contained invalid characters, or was of an odd length.
/// </exception>
public static byte[] ToByteArray(string hexadecimalString)
{
if (!TryParse(hexadecimalString, out var value))
{
throw new ArgumentException("Invalid hexadecimal string", nameof(hexadecimalString));
}
return value;
}
/// <summary>
/// Parse a hexadecimal string to bytes
/// </summary>
/// <param name="hexadecimalString">
/// The hexadecimal string, which must be an even number of characters.
/// </param>
/// <param name="value">
/// The parsed value if successful.
/// </param>
/// <returns>
/// True if successful.
/// </returns>
public static bool TryParse(string hexadecimalString, out byte[] value)
{
if (hexadecimalString.Length == 0)
{
value = Empty;
return true;
}
if (hexadecimalString.Length % 2 != 0)
{
value = Empty;
return false;
}
try
{
value = new byte[hexadecimalString.Length / 2];
for (int i = 0, j = 0; j < hexadecimalString.Length; i++)
{
value[i] = (byte)((HexValues[hexadecimalString[j++] - '0'] << 4)
| HexValues[hexadecimalString[j++] - '0']);
}
return true;
}
catch (OverflowException)
{
value = Empty;
return false;
}
}
}
我今天遇到了同样的问题,我遇到了以下代码:
private static string ByteArrayToHex(byte[] barray)
{
char[] c = new char[barray.Length * 2];
byte b;
for (int i = 0; i < barray.Length; ++i)
{
b = ((byte)(barray[i] >> 4));
c[i * 2] = (char)(b > 9 ? b + 0x37 : b + 0x30);
b = ((byte)(barray[i] & 0xF));
c[i * 2 + 1] = (char)(b > 9 ? b + 0x37 : b + 0x30);
}
return new string(c);
}
来源:论坛帖子byte[]数组到十六进制字符串(见PZahra的帖子)。我稍微修改了一下代码,删除了0x前缀。
我对代码进行了一些性能测试,它几乎比使用BitConverter.ToString()快八倍(根据patridge的帖子,速度最快)。
// a safe version of the lookup solution:
public static string ByteArrayToHexViaLookup32Safe(byte[] bytes, bool withZeroX)
{
if (bytes.Length == 0)
{
return withZeroX ? "0x" : "";
}
int length = bytes.Length * 2 + (withZeroX ? 2 : 0);
StateSmall stateToPass = new StateSmall(bytes, withZeroX);
return string.Create(length, stateToPass, (chars, state) =>
{
int offset0x = 0;
if (state.WithZeroX)
{
chars[0] = '0';
chars[1] = 'x';
offset0x += 2;
}
Span<uint> charsAsInts = MemoryMarshal.Cast<char, uint>(chars.Slice(offset0x));
int targetLength = state.Bytes.Length;
for (int i = 0; i < targetLength; i += 1)
{
uint val = Lookup32[state.Bytes[i]];
charsAsInts[i] = val;
}
});
}
private struct StateSmall
{
public StateSmall(byte[] bytes, bool withZeroX)
{
Bytes = bytes;
WithZeroX = withZeroX;
}
public byte[] Bytes;
public bool WithZeroX;
}
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