如何将字节数组转换为十六进制字符串,反之亦然?
当前回答
扩展方法(免责声明:完全未经测试的代码,BTW…):
public static class ByteExtensions
{
public static string ToHexString(this byte[] ba)
{
StringBuilder hex = new StringBuilder(ba.Length * 2);
foreach (byte b in ba)
{
hex.AppendFormat("{0:x2}", b);
}
return hex.ToString();
}
}
使用Tomalak的三种解决方案之一(最后一种是字符串上的扩展方法)。
其他回答
我将参加这个比特拨弄比赛,因为我有一个同样使用比特拨弄来解码十六进制的答案。请注意,使用字符数组可能会更快,因为调用StringBuilder方法也需要时间。
public static String ToHex (byte[] data)
{
int dataLength = data.Length;
// pre-create the stringbuilder using the length of the data * 2, precisely enough
StringBuilder sb = new StringBuilder (dataLength * 2);
for (int i = 0; i < dataLength; i++) {
int b = data [i];
// check using calculation over bits to see if first tuple is a letter
// isLetter is zero if it is a digit, 1 if it is a letter
int isLetter = (b >> 7) & ((b >> 6) | (b >> 5)) & 1;
// calculate the code using a multiplication to make up the difference between
// a digit character and an alphanumerical character
int code = '0' + ((b >> 4) & 0xF) + isLetter * ('A' - '9' - 1);
// now append the result, after casting the code point to a character
sb.Append ((Char)code);
// do the same with the lower (less significant) tuple
isLetter = (b >> 3) & ((b >> 2) | (b >> 1)) & 1;
code = '0' + (b & 0xF) + isLetter * ('A' - '9' - 1);
sb.Append ((Char)code);
}
return sb.ToString ();
}
public static byte[] FromHex (String hex)
{
// pre-create the array
int resultLength = hex.Length / 2;
byte[] result = new byte[resultLength];
// set validity = 0 (0 = valid, anything else is not valid)
int validity = 0;
int c, isLetter, value, validDigitStruct, validDigit, validLetterStruct, validLetter;
for (int i = 0, hexOffset = 0; i < resultLength; i++, hexOffset += 2) {
c = hex [hexOffset];
// check using calculation over bits to see if first char is a letter
// isLetter is zero if it is a digit, 1 if it is a letter (upper & lowercase)
isLetter = (c >> 6) & 1;
// calculate the tuple value using a multiplication to make up the difference between
// a digit character and an alphanumerical character
// minus 1 for the fact that the letters are not zero based
value = ((c & 0xF) + isLetter * (-1 + 10)) << 4;
// check validity of all the other bits
validity |= c >> 7; // changed to >>, maybe not OK, use UInt?
validDigitStruct = (c & 0x30) ^ 0x30;
validDigit = ((c & 0x8) >> 3) * (c & 0x6);
validity |= (isLetter ^ 1) * (validDigitStruct | validDigit);
validLetterStruct = c & 0x18;
validLetter = (((c - 1) & 0x4) >> 2) * ((c - 1) & 0x2);
validity |= isLetter * (validLetterStruct | validLetter);
// do the same with the lower (less significant) tuple
c = hex [hexOffset + 1];
isLetter = (c >> 6) & 1;
value ^= (c & 0xF) + isLetter * (-1 + 10);
result [i] = (byte)value;
// check validity of all the other bits
validity |= c >> 7; // changed to >>, maybe not OK, use UInt?
validDigitStruct = (c & 0x30) ^ 0x30;
validDigit = ((c & 0x8) >> 3) * (c & 0x6);
validity |= (isLetter ^ 1) * (validDigitStruct | validDigit);
validLetterStruct = c & 0x18;
validLetter = (((c - 1) & 0x4) >> 2) * ((c - 1) & 0x2);
validity |= isLetter * (validLetterStruct | validLetter);
}
if (validity != 0) {
throw new ArgumentException ("Hexadecimal encoding incorrect for input " + hex);
}
return result;
}
从Java代码转换而来。
为什么要让它变得复杂?这在Visual Studio 2008中很简单:
C#:
string hex = BitConverter.ToString(YourByteArray).Replace("-", "");
VB:
Dim hex As String = BitConverter.ToString(YourByteArray).Replace("-", "")
Dotnet 5更新
要从byte[](字节数组)转换为十六进制字符串,请使用:
System.Convert.ToHexString
var myBytes = new byte[100];
var myString = System.Convert.ToHexString(myBytes);
要将十六进制字符串转换为字节[],请使用:
System.Convert.FromHexString
var myString = "E10B116E8530A340BCC7B3EAC208487B";
var myBytes = System.Convert.FromHexString(myString);
如果您希望比BitConverter更灵活,但不希望使用那些笨重的90年代风格的显式循环,那么您可以这样做:
String.Join(String.Empty, Array.ConvertAll(bytes, x => x.ToString("X2")));
或者,如果您使用的是.NET 4.0:
String.Concat(Array.ConvertAll(bytes, x => x.ToString("X2")));
(后者来自对原帖子的评论。)
如果性能很重要,这里有一个优化的解决方案:
static readonly char[] _hexDigits = "0123456789abcdef".ToCharArray();
public static string ToHexString(this byte[] bytes)
{
char[] digits = new char[bytes.Length * 2];
for (int i = 0; i < bytes.Length; i++)
{
int d1, d2;
d1 = Math.DivRem(bytes[i], 16, out d2);
digits[2 * i] = _hexDigits[d1];
digits[2 * i + 1] = _hexDigits[d2];
}
return new string(digits);
}
它比BitConverter.ToString快2.5倍,比BitConverter.ToString+删除“-”字符快7倍。
推荐文章
- 实体框架核心:在上一个操作完成之前,在此上下文中开始的第二个操作
- 如何为构造函数定制Visual Studio的私有字段生成快捷方式?
- 如何使用JSON确保字符串是有效的JSON。网
- 使用C返回一个数组
- AppSettings从.config文件中获取值
- 通过HttpClient向REST API发布一个空体
- 如何检查IEnumerable是否为空或空?
- 自动化invokerrequired代码模式
- 在c#代码中设置WPF文本框的背景颜色
- 在c#中,什么是单子?
- c#和Java中的泛型有什么不同?和模板在c++ ?
- 向对象数组添加属性
- c#线程安全快速(est)计数器
- 如何将此foreach代码转换为Parallel.ForEach?
- 如何分裂()一个分隔字符串到一个列表<字符串>