如何将字节数组转换为十六进制字符串,反之亦然?
当前回答
我将参加这个比特拨弄比赛,因为我有一个同样使用比特拨弄来解码十六进制的答案。请注意,使用字符数组可能会更快,因为调用StringBuilder方法也需要时间。
public static String ToHex (byte[] data)
{
int dataLength = data.Length;
// pre-create the stringbuilder using the length of the data * 2, precisely enough
StringBuilder sb = new StringBuilder (dataLength * 2);
for (int i = 0; i < dataLength; i++) {
int b = data [i];
// check using calculation over bits to see if first tuple is a letter
// isLetter is zero if it is a digit, 1 if it is a letter
int isLetter = (b >> 7) & ((b >> 6) | (b >> 5)) & 1;
// calculate the code using a multiplication to make up the difference between
// a digit character and an alphanumerical character
int code = '0' + ((b >> 4) & 0xF) + isLetter * ('A' - '9' - 1);
// now append the result, after casting the code point to a character
sb.Append ((Char)code);
// do the same with the lower (less significant) tuple
isLetter = (b >> 3) & ((b >> 2) | (b >> 1)) & 1;
code = '0' + (b & 0xF) + isLetter * ('A' - '9' - 1);
sb.Append ((Char)code);
}
return sb.ToString ();
}
public static byte[] FromHex (String hex)
{
// pre-create the array
int resultLength = hex.Length / 2;
byte[] result = new byte[resultLength];
// set validity = 0 (0 = valid, anything else is not valid)
int validity = 0;
int c, isLetter, value, validDigitStruct, validDigit, validLetterStruct, validLetter;
for (int i = 0, hexOffset = 0; i < resultLength; i++, hexOffset += 2) {
c = hex [hexOffset];
// check using calculation over bits to see if first char is a letter
// isLetter is zero if it is a digit, 1 if it is a letter (upper & lowercase)
isLetter = (c >> 6) & 1;
// calculate the tuple value using a multiplication to make up the difference between
// a digit character and an alphanumerical character
// minus 1 for the fact that the letters are not zero based
value = ((c & 0xF) + isLetter * (-1 + 10)) << 4;
// check validity of all the other bits
validity |= c >> 7; // changed to >>, maybe not OK, use UInt?
validDigitStruct = (c & 0x30) ^ 0x30;
validDigit = ((c & 0x8) >> 3) * (c & 0x6);
validity |= (isLetter ^ 1) * (validDigitStruct | validDigit);
validLetterStruct = c & 0x18;
validLetter = (((c - 1) & 0x4) >> 2) * ((c - 1) & 0x2);
validity |= isLetter * (validLetterStruct | validLetter);
// do the same with the lower (less significant) tuple
c = hex [hexOffset + 1];
isLetter = (c >> 6) & 1;
value ^= (c & 0xF) + isLetter * (-1 + 10);
result [i] = (byte)value;
// check validity of all the other bits
validity |= c >> 7; // changed to >>, maybe not OK, use UInt?
validDigitStruct = (c & 0x30) ^ 0x30;
validDigit = ((c & 0x8) >> 3) * (c & 0x6);
validity |= (isLetter ^ 1) * (validDigitStruct | validDigit);
validLetterStruct = c & 0x18;
validLetter = (((c - 1) & 0x4) >> 2) * ((c - 1) & 0x2);
validity |= isLetter * (validLetterStruct | validLetter);
}
if (validity != 0) {
throw new ArgumentException ("Hexadecimal encoding incorrect for input " + hex);
}
return result;
}
从Java代码转换而来。
其他回答
这是一篇很棒的帖子。我喜欢瓦利德的解决方案。我还没有通过帕特里奇的测试,但似乎很快。我还需要反向过程,将十六进制字符串转换为字节数组,因此我将其作为Waleed解决方案的反向来编写。不确定它是否比托马拉克的原始解决方案更快。同样,我也没有通过帕特里奇的测试运行相反的过程。
private byte[] HexStringToByteArray(string hexString)
{
int hexStringLength = hexString.Length;
byte[] b = new byte[hexStringLength / 2];
for (int i = 0; i < hexStringLength; i += 2)
{
int topChar = (hexString[i] > 0x40 ? hexString[i] - 0x37 : hexString[i] - 0x30) << 4;
int bottomChar = hexString[i + 1] > 0x40 ? hexString[i + 1] - 0x37 : hexString[i + 1] - 0x30;
b[i / 2] = Convert.ToByte(topChar + bottomChar);
}
return b;
}
这是我的纯二进制解决方案,不需要库查找,也支持大写/小写:
public static String encode(byte[] bytes, boolean uppercase) {
char[] result = new char[2 * bytes.length];
for (int i = 0; i < bytes.length; i++) {
byte word = bytes[i];
byte left = (byte) ((0XF0 & word) >>> 4);
byte right = (byte) ((byte) 0X0F & word);
int resultIndex = i * 2;
result[resultIndex] = encode(left, uppercase);
result[resultIndex + 1] = encode(right, uppercase);
}
return new String(result);
}
public static char encode(byte value, boolean uppercase) {
int characterCase = uppercase ? 0 : 32;
if (value > 15 || value < 0) {
return '0';
}
if (value > 9) {
return (char) (value + 0x37 | characterCase);
}
return (char) (value + 0x30);
}
static string ByteArrayToHexViaLookupPerByte2(byte[] bytes)
{
var result3 = new uint[bytes.Length];
for (int i = 0; i < bytes.Length; i++)
result3[i] = _Lookup32[bytes[i]];
var handle = GCHandle.Alloc(result3, GCHandleType.Pinned);
try
{
var result = Marshal.PtrToStringUni(handle.AddrOfPinnedObject(), bytes.Length * 2);
return result;
}
finally
{
handle.Free();
}
}
在我的测试中,这个函数总是不安全实现之后的第二个条目。
不幸的是,测试台不太可靠。。。如果你多次运行它,列表会被打乱,以至于谁知道在不安全之后哪个才是最快的!它没有考虑预热、jit编译时间和GC性能影响。我很想重写它以获得更多信息,但我真的没有时间。
我想出了一个不同的代码,它可以容忍额外的字符(空格、破折号…)。它的灵感主要来自这里一些可以接受的快速答案。它允许解析以下“文件”
00-aa-84-fb
12 32 FF CD
12 00
12_32_FF_CD
1200d5e68a
/// <summary>Reads a hex string into bytes</summary>
public static IEnumerable<byte> HexadecimalStringToBytes(string hex) {
if (hex == null)
throw new ArgumentNullException(nameof(hex));
char c, c1 = default(char);
bool hasc1 = false;
unchecked {
for (int i = 0; i < hex.Length; i++) {
c = hex[i];
bool isValid = 'A' <= c && c <= 'f' || 'a' <= c && c <= 'f' || '0' <= c && c <= '9';
if (!hasc1) {
if (isValid) {
hasc1 = true;
}
} else {
hasc1 = false;
if (isValid) {
yield return (byte)((GetHexVal(c1) << 4) + GetHexVal(c));
}
}
c1 = c;
}
}
}
/// <summary>Reads a hex string into a byte array</summary>
public static byte[] HexadecimalStringToByteArray(string hex)
{
if (hex == null)
throw new ArgumentNullException(nameof(hex));
var bytes = new List<byte>(hex.Length / 2);
foreach (var item in HexadecimalStringToBytes(hex)) {
bytes.Add(item);
}
return bytes.ToArray();
}
private static byte GetHexVal(char val)
{
return (byte)(val - (val < 0x3A ? 0x30 : val < 0x5B ? 0x37 : 0x57));
// ^^^^^^^^^^^^^^^^^ ^^^^^^^^^^^^^^^^^ ^^^^
// digits 0-9 upper char A-Z a-z
}
复制时请参考完整代码。包括单元测试。
有些人可能会说它对额外的字符太宽容了。因此,不要依赖此代码来执行验证(或更改)。
您可以使用BitConverter.ToString方法:
byte[] bytes = {0, 1, 2, 4, 8, 16, 32, 64, 128, 256}
Console.WriteLine( BitConverter.ToString(bytes));
输出:
00-01-02-04-08-10-20-40-80-FF
更多信息:BitConverter.ToString方法(Byte[])
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