我想写一个这样的查询:
SELECT o.OrderId, MAX(o.NegotiatedPrice, o.SuggestedPrice)
FROM Order o
但这不是MAX函数的工作原理,对吧?它是一个聚合函数,因此它需要一个参数,然后返回所有行的MAX。
有人知道我的方法吗?
我想写一个这样的查询:
SELECT o.OrderId, MAX(o.NegotiatedPrice, o.SuggestedPrice)
FROM Order o
但这不是MAX函数的工作原理,对吧?它是一个聚合函数,因此它需要一个参数,然后返回所有行的MAX。
有人知道我的方法吗?
当前回答
如果你使用的是SQL Server 2008(或更高版本),那么这是更好的解决方案:
SELECT o.OrderId,
(SELECT MAX(Price)
FROM (VALUES (o.NegotiatedPrice),(o.SuggestedPrice)) AS AllPrices(Price))
FROM Order o
所有的信用和投票都应该去Sven对一个相关问题的答案,“多列的SQL MAX ?” 我说这是“最佳答案”,因为:
It doesn't require complicating your code with UNION's, PIVOT's, UNPIVOT's, UDF's, and crazy-long CASE statments. It isn't plagued with the problem of handling nulls, it handles them just fine. It's easy to swap out the "MAX" with "MIN", "AVG", or "SUM". You can use any aggregate function to find the aggregate over many different columns. You're not limited to the names I used (i.e. "AllPrices" and "Price"). You can pick your own names to make it easier to read and understand for the next guy. You can find multiple aggregates using SQL Server 2008's derived_tables like so: SELECT MAX(a), MAX(b) FROM (VALUES (1, 2), (3, 4), (5, 6), (7, 8), (9, 10) ) AS MyTable(a, b)
其他回答
SELECT o.OrderID
CASE WHEN o.NegotiatedPrice > o.SuggestedPrice THEN
o.NegotiatedPrice
ELSE
o.SuggestedPrice
END AS Price
如果你使用的是SQL Server 2008(或更高版本),那么这是更好的解决方案:
SELECT o.OrderId,
(SELECT MAX(Price)
FROM (VALUES (o.NegotiatedPrice),(o.SuggestedPrice)) AS AllPrices(Price))
FROM Order o
所有的信用和投票都应该去Sven对一个相关问题的答案,“多列的SQL MAX ?” 我说这是“最佳答案”,因为:
It doesn't require complicating your code with UNION's, PIVOT's, UNPIVOT's, UDF's, and crazy-long CASE statments. It isn't plagued with the problem of handling nulls, it handles them just fine. It's easy to swap out the "MAX" with "MIN", "AVG", or "SUM". You can use any aggregate function to find the aggregate over many different columns. You're not limited to the names I used (i.e. "AllPrices" and "Price"). You can pick your own names to make it easier to read and understand for the next guy. You can find multiple aggregates using SQL Server 2008's derived_tables like so: SELECT MAX(a), MAX(b) FROM (VALUES (1, 2), (3, 4), (5, 6), (7, 8), (9, 10) ) AS MyTable(a, b)
其他答案都很好,但如果你不得不担心有NULL值,你可能会想要这个变体:
SELECT o.OrderId,
CASE WHEN ISNULL(o.NegotiatedPrice, o.SuggestedPrice) > ISNULL(o.SuggestedPrice, o.NegotiatedPrice)
THEN ISNULL(o.NegotiatedPrice, o.SuggestedPrice)
ELSE ISNULL(o.SuggestedPrice, o.NegotiatedPrice)
END
FROM Order o
我会使用kcrumley提供的解决方案 只需稍微修改它以处理null
create function dbo.HigherArgumentOrNull(@val1 int, @val2 int)
returns int
as
begin
if @val1 >= @val2
return @val1
if @val1 < @val2
return @val2
return NULL
end
编辑 在Mark的评论后修改。正如他在3值逻辑x > NULL或x < NULL应该总是返回NULL。换句话说,未知的结果。
SQL Server 2012引入IIF:
SELECT
o.OrderId,
IIF( ISNULL( o.NegotiatedPrice, 0 ) > ISNULL( o.SuggestedPrice, 0 ),
o.NegotiatedPrice,
o.SuggestedPrice
)
FROM
Order o
建议在使用IIF时处理NULL,因为boolean表达式两侧的NULL将导致IIF返回false_value(而不是NULL)。