是否有可能在JavaScript中检测“空闲”时间?

我的主要用例可能是预取或预加载内容。

我将空闲时间定义为用户不活动或没有任何CPU使用的时间段


当前回答

下面是一个使用jQuery处理鼠标移动和按键事件的简单脚本。 如果时间过期,页面将重新加载。

<script type="text/javascript">
    var idleTime = 0;
    $(document).ready(function () {
        // Increment the idle time counter every minute.
        var idleInterval = setInterval(timerIncrement, 60000); // 1 minute

        // Zero the idle timer on mouse movement.
        $(this).mousemove(function (e) {
            idleTime = 0;
        });
        $(this).keypress(function (e) {
            idleTime = 0;
        });
    });

    function timerIncrement() {
        idleTime = idleTime + 1;
        if (idleTime > 19) { // 20 minutes
            window.location.reload();
        }
    }
</script>

其他回答

您要求优雅,我创建了一个简单的类来支持惰性检查(具有空闲状态),除了命令方式(带有回调)之外。此外,当违反空闲时间时,该类支持“backToActive”。

class Idle {
    constructor(timeout = 10, idleCallback = null, backToActiveCallback = null, autoStart = true, backToActiveOnXHR = false) {
        this.timeout = timeout
        this.idleCallback = idleCallback
        this.backToActiveCallback = backToActiveCallback
        this.autoStart = autoStart // only F5
        this.backToActiveOnXHR = backToActiveOnXHR
        this.idle = false
        this.timer = null
        this.events = ['scroll', 'mousedown', 'mousemove', 'keypress', 'scroll', 'touchstart']
        this.init()
    }

    init() {
        if(this.backToActiveOnXHR) {
            this.events.push('load')
        }
        this.events.forEach(name => {
            window.addEventListener(name, this.backToActive, true)
        })
        if(this.autoStart) {
            this.backToActive()
        }
    }

    goIdle = () => {
        this.idle = true
        if(!!this.idleCallback) {
            this.idleCallback(this.timeout)
        }
    }

    backToActive = () => {
        if(this.idle) {
            this.backToActiveCallback()
        }
        this.idle = false
        clearTimeout(this.timer)
        this.timer = setTimeout(this.goIdle, this.timeout * 1000)
    }
}

用法:

let idleCallback = timeout => { console.log(`Went idle after ${timeout} seconds`) }
let backToActiveCallback = () => { console.log('Back to active') }
let idle = new Idle(30, idleCallback, backToActiveCallback)

devtools的结果:

// Went idle after 30 seconds <--- goes idle when no activity is detected
// Back to active <--- when the user is detected again

支持懒惰的好处:

setInterval(() => {
    common.fetchApi('/api/v1/list', { status: idle.idle ? 'away' : 'online' }).then(/* show a list of elements */)
}, 1000 * 5)

你为什么要一张惰性支票?有时我们使用周期性的XHR(带setInterval),即当用户观看航班、乘车、电影、订单等列表时。对于每个XHR,我们可以添加关于他/她的活动状态(在线/离开)的信息,这样我们就可以了解系统中的活跃用户。

我的课程是基于Equiman和Frank Conijn的回答。

以下是我找到的最佳解决方案:

当用户空闲时发生火灾事件

下面是JavaScript代码:

idleTimer = null;
idleState = false;
idleWait = 2000;

(function ($) {

    $(document).ready(function () {

        $('*').bind('mousemove keydown scroll', function () {

            clearTimeout(idleTimer);

            if (idleState == true) {

                // Reactivated event
                $("body").append("<p>Welcome Back.</p>");
            }

            idleState = false;

            idleTimer = setTimeout(function () {

                // Idle Event
                $("body").append("<p>You've been idle for " + idleWait/1000 + " seconds.</p>");

                idleState = true; }, idleWait);
        });

        $("body").trigger("mousemove");

    });
}) (jQuery)

纯JavaScript,通过addEventListener正确设置重置时间和绑定:

(function() {

  var t,
    timeout = 5000;

  function resetTimer() {
    console.log("reset: " + new Date().toLocaleString());
    if (t) {
      window.clearTimeout(t);
    }
    t = window.setTimeout(logout, timeout);
  }

  function logout() {
    console.log("done: " + new Date().toLocaleString());
  }
  resetTimer();

  //And bind the events to call `resetTimer()`
  ["click", "mousemove", "keypress"].forEach(function(name) {
    console.log(name);
    document.addEventListener(name, resetTimer);
  });

}());

我的回答受到了维贾伊的启发,但我认为这是一个更简短、更普遍的解决方案,我想把它分享给可能有帮助的人。

(function () { 
    var minutes = true; // change to false if you'd rather use seconds
    var interval = minutes ? 60000 : 1000; 
    var IDLE_TIMEOUT = 3; // 3 minutes in this example
    var idleCounter = 0;

    document.onmousemove = document.onkeypress = function () {
        idleCounter = 0;
    };

    window.setInterval(function () {
        if (++idleCounter >= IDLE_TIMEOUT) {
            window.location.reload(); // or whatever you want to do
        }
    }, interval);
}());

按照目前的情况,这段代码将立即执行,并在3分钟内没有鼠标移动或按键后重新加载当前页面。

它利用普通的JavaScript和立即调用的函数表达式以一种干净且自包含的方式处理空闲超时。

Debounce其实是个好主意!下面是一个用于无jquery项目的版本:

const derivedLogout = createDerivedLogout(30);
derivedLogout(); // It could happen that the user is too idle)
window.addEventListener('click', derivedLogout, false);
window.addEventListener('mousemove', derivedLogout, false);
window.addEventListener('keyup', derivedLogout, false);

function createDerivedLogout (sessionTimeoutInMinutes) {
    return _.debounce( () => {
        window.location = this.logoutUrl;
    }, sessionTimeoutInMinutes * 60 * 1000 )
}