由于眼睛的问题,我不得不将控制台背景色改为白色,但字体是灰色的,它使消息无法阅读。我怎样才能改变呢?


当前回答

paint-console

简单的可着色原木。支持检查对象和单行更新 这个包只是重新油漆控制台。

安装

npm install paint-console

使用

require('paint-console');

console.info('console.info();');
console.warn('console.warn();');
console.error('console.error();');
console.log('console.log();');

demo

其他回答

Sindre Sorhus设计的这个图书馆是目前最好的:

粉笔

高性能 不扩展String.prototype 富有表现力的API 嵌套样式的能力 干净和专注 自动检测颜色支持 积极维护 5500+模块使用

下面你可以找到运行node.js应用程序时文本的颜色引用:

console.log('\x1b[36m%s\x1b[0m', 'I am cyan');  //cyan
console.log('\x1b[33m%s\x1b[0m', stringToMakeYellow);  //yellow

注意%s是字符串(第二个参数)被注入的位置。\x1b[0m重置终端颜色,因此在此之后它不再继续是所选的颜色。

颜色参考

Reset = "\x1b[0m"
Bright = "\x1b[1m"
Dim = "\x1b[2m"
Underscore = "\x1b[4m"
Blink = "\x1b[5m"
Reverse = "\x1b[7m"
Hidden = "\x1b[8m"

FgBlack = "\x1b[30m"
FgRed = "\x1b[31m"
FgGreen = "\x1b[32m"
FgYellow = "\x1b[33m"
FgBlue = "\x1b[34m"
FgMagenta = "\x1b[35m"
FgCyan = "\x1b[36m"
FgWhite = "\x1b[37m"
FgGray = "\x1b[90m"

BgBlack = "\x1b[40m"
BgRed = "\x1b[41m"
BgGreen = "\x1b[42m"
BgYellow = "\x1b[43m"
BgBlue = "\x1b[44m"
BgMagenta = "\x1b[45m"
BgCyan = "\x1b[46m"
BgWhite = "\x1b[47m"
BgGray = "\x1b[100m"

编辑:

例如,\x1b[31m是一个转义序列,它将被您的终端拦截,并指示它切换到红色。事实上,\x1b是不可打印控制字符转义的代码。仅处理颜色和样式的转义序列也被称为ANSI转义代码,并且是标准化的,因此它们(应该)适用于任何平台。

维基百科对不同终端显示颜色的方式做了很好的比较 https://en.wikipedia.org/wiki/ANSI_escape_code#Colors

对于一个不影响String对象的内置方法的流行替代颜色,我推荐使用cli-color。

包括颜色和可链接样式,如粗体、斜体和下划线。

有关此类别中各个模块的比较,请参见这里。

最小的别名:

{
  const f = (color) => (...args) => {
    for (const x of [color, ...args, "\33[0m"]) console.log(x);
  };

  Object.assign(console, {
    black: f("\33[30m"),
    red: f("\33[31m"),
    green: f("\33[32m"),
    yellow: f("\33[33m"),
    blue: f("\33[34m"),
    magenta: f("\33[35m"),
    cyan: f("\33[36m"),
    white: f("\33[37m"),
  });
}

// Usage
console.blue("Blue world");
var colorSet = {
    Reset: "\x1b[0m",
    Red: "\x1b[31m",
    Green: "\x1b[32m",
    Yellow: "\x1b[33m",
    Blue: "\x1b[34m",
    Magenta: "\x1b[35m"
};

var funcNames = ["info", "log", "warn", "error"];
var colors = [colorSet.Green, colorSet.Blue, colorSet.Yellow, colorSet.Red];

for (var i = 0; i < funcNames.length; i++) {
    let funcName = funcNames[i];
    let color = colors[i];
    let oldFunc = console[funcName];
    console[funcName] = function () {
        var args = Array.prototype.slice.call(arguments);
        if (args.length) {
            args = [color + args[0]].concat(args.slice(1), colorSet.Reset);
        }
        oldFunc.apply(null, args);
    };
}

// Test:
console.info("Info is green.");
console.log("Log is blue.");
console.warn("Warn is orange.");
console.error("Error is red.");
console.info("--------------------");
console.info("Formatting works as well. The number = %d", 123);