这是对teoman shipahi的回答的重新讨论，使用了一个稍微不那么模糊的名称，并遵循了在尝试调用代码之前定义代码的设计原则。(虽然node允许您做其他事情，但本末倒置并不是一个好的实践。)

function rename_or_copy_and_delete (oldPath, newPath, callback) {

    function copy_and_delete () {
        var readStream = fs.createReadStream(oldPath);
        var writeStream = fs.createWriteStream(newPath);

        readStream.on('error', callback);
        writeStream.on('error', callback);
        readStream.on('close', 
              function () {
                fs.unlink(oldPath, callback);
              }
        );

        readStream.pipe(writeStream);
    }

    fs.rename(oldPath, newPath, 
        function (err) {
          if (err) {
              if (err.code === 'EXDEV') {
                  copy_and_delete();
              } else {
                  callback(err);
              }
              return;// << both cases (err/copy_and_delete)
          }
          callback();
        }
    );
}

在下面URL的帮助下，您可以复制或移动您的文件CURRENT Source到Destination Source

https://coursesweb.net/nodejs/move-copy-file

/*********Moves the $file to $dir2 Start *********/ var moveFile = (file, dir2)=>{ //include the fs, path modules var fs = require('fs'); var path = require('path'); //gets file name and adds it to dir2 var f = path.basename(file); var dest = path.resolve(dir2, f); fs.rename(file, dest, (err)=>{ if(err) throw err; else console.log('Successfully moved'); }); }; //move file1.htm from 'test/' to 'test/dir_1/' moveFile('./test/file1.htm', './test/dir_1/'); /*********Moves the $file to $dir2 END *********/ /*********copy the $file to $dir2 Start *********/ var copyFile = (file, dir2)=>{ //include the fs, path modules var fs = require('fs'); var path = require('path'); //gets file name and adds it to dir2 var f = path.basename(file); var source = fs.createReadStream(file); var dest = fs.createWriteStream(path.resolve(dir2, f)); source.pipe(dest); source.on('end', function() { console.log('Succesfully copied'); }); source.on('error', function(err) { console.log(err); }); }; //example, copy file1.htm from 'test/dir_1/' to 'test/' copyFile('./test/dir_1/file1.htm', './test/'); /*********copy the $file to $dir2 END *********/

我将把所有涉及的函数(即重命名，复制，断开链接)彼此分离，以获得灵活性，并承诺一切，当然:

const renameFile = (path, newPath) => 
  new Promise((res, rej) => {
    fs.rename(path, newPath, (err, data) =>
      err
        ? rej(err)
        : res(data));
  });

const copyFile = (path, newPath, flags) =>
  new Promise((res, rej) => {
    const readStream = fs.createReadStream(path),
      writeStream = fs.createWriteStream(newPath, {flags});

    readStream.on("error", rej);
    writeStream.on("error", rej);
    writeStream.on("finish", res);
    readStream.pipe(writeStream);
  });

const unlinkFile = path => 
  new Promise((res, rej) => {
    fs.unlink(path, (err, data) =>
      err
        ? rej(err)
        : res(data));
  });

const moveFile = (path, newPath, flags) =>
  renameFile(path, newPath)
    .catch(e => {
      if (e.code !== "EXDEV")
        throw new e;

      else
        return copyFile(path, newPath, flags)
          .then(() => unlinkFile(path));
    });

moveFile只是一个方便的函数，我们可以分别应用这些函数，例如，当我们需要更细粒度的异常处理时。

就像上面的回答中所说的那样，我的2分:copy()方法不应该在没有轻微调整的情况下原样用于复制文件:

function copy(callback) {
    var readStream = fs.createReadStream(oldPath);
    var writeStream = fs.createWriteStream(newPath);

    readStream.on('error', callback);
    writeStream.on('error', callback);

    // Do not callback() upon "close" event on the readStream
    // readStream.on('close', function () {
    // Do instead upon "close" on the writeStream
    writeStream.on('close', function () {
        callback();
    });

    readStream.pipe(writeStream);
}

复制函数封装在Promise中:

function copy(oldPath, newPath) {
  return new Promise((resolve, reject) => {
    const readStream = fs.createReadStream(oldPath);
    const writeStream = fs.createWriteStream(newPath);

    readStream.on('error', err => reject(err));
    writeStream.on('error', err => reject(err));

    writeStream.on('close', function() {
      resolve();
    });

    readStream.pipe(writeStream);
  })

但是，请记住，如果目标文件夹不存在，文件系统可能会崩溃。

使用mv节点模块，它将首先尝试执行fs。重命名，然后退回到复制，然后取消链接。

根据seppo0010的注释，我使用了重命名函数来完成此操作。

http://nodejs.org/docs/latest/api/fs.html#fs_fs_rename_oldpath_newpath_callback

fs。重命名(oldPath, newPath, callback) 新增于:v0.0.2 oldPath <String> | <Buffer> newPath <String> | <Buffer> . newPath <String> 回调函数> < 异步重命名(2)。除了可能的异常，没有参数 赋给完成回调函数。