我想写一个循环15个字符串的脚本(可能是数组?)这可能吗?

类似于:

for databaseName in listOfNames
then
  # Do something
end

当前回答

单线循环,

 declare -a listOfNames=('db_a' 'db_b' 'db_c')
 for databaseName in ${listOfNames[@]}; do echo $databaseName; done;

你会得到这样的输出,

db_a
db_b
db_c

其他回答

我循环浏览一系列项目以进行git pull更新:

#!/bin/sh
projects="
web
ios
android
"
for project in $projects do
    cd  $HOME/develop/$project && git pull
end

当然,这是可能的。

for databaseName in a b c d e f; do
  # do something like: echo $databaseName
done 

有关详细信息,请参阅、while和until的Bash循环。

我在GitHub更新中使用了这种方法,我发现它很简单。

## declare an array variable
arr_variable=("kofi" "kwame" "Ama")

## now loop through the above array
for i in "${arr_variable[@]}"
do
   echo "$i"


done
   

您可以使用带有三个表达式(C样式)的计数器遍历bash数组值,以读取循环语法的所有值和索引:

declare -a kofi=("kofi" "kwame" "Ama")
 
# get the length of the array
length=${#kofi[@]}

for (( j=0; j<${length}; j++ ));
do
  print (f "Current index %d with value %s\n" $j "${kofi[$j]}")
done

这与user2533809的答案类似,但每个文件都将作为单独的命令执行。

#!/bin/bash
names="RA
RB
R C
RD"

while read -r line; do
    echo line: "$line"
done <<< "$names"
listOfNames="db_one db_two db_three"
for databaseName in $listOfNames
do
  echo $databaseName
done

或者只是

for databaseName in db_one db_two db_three
do
  echo $databaseName
done