SELECT DISTINCT field1, field2, field3, ......
FROM table;
我试图完成以下SQL语句,但我希望它返回所有列。 这可能吗?
就像这样:
SELECT DISTINCT field1, *
FROM table;
SELECT DISTINCT field1, field2, field3, ......
FROM table;
我试图完成以下SQL语句,但我希望它返回所有列。 这可能吗?
就像这样:
SELECT DISTINCT field1, *
FROM table;
当前回答
将GROUP BY添加到要检查重复的字段 您的查询可能看起来像
SELECT field1, field2, field3, ...... FROM table GROUP BY field1
将检查Field1以排除重复记录
或者你可能会问
SELECT * FROM table GROUP BY field1
字段1的重复记录被排除在SELECT中
其他回答
这是一个简单的解决方法:
WITH cte AS /* Declaring a new table named 'cte' to be a clone of your table */
(SELECT *, ROW_NUMBER() OVER (PARTITION BY id ORDER BY val1 DESC) AS rn
FROM MyTable /* Selecting only unique values based on the "id" field */
)
SELECT * /* Here you can specify several columns to retrieve */
FROM cte
WHERE rn = 1
select min(table.id), table.column1
from table
group by table.column1
SELECT *
FROM tblname
GROUP BY duplicate_values
ORDER BY ex.VISITED_ON DESC
LIMIT 0 , 30
在ORDER BY我刚刚把例子放在这里,你也可以在这里添加ID字段
SELECT c2.field1 ,
field2
FROM (SELECT DISTINCT
field1
FROM dbo.TABLE AS C
) AS c1
JOIN dbo.TABLE AS c2 ON c1.field1 = c2.field1
SELECT * from table where field in (SELECT distinct field from table)