如果你想使用npm包，扳手是很好的选择。

var wrench = require("wrench");

var files = wrench.readdirSyncRecursive("directory");

wrench.readdirRecursive("directory", function (error, files) {
    // live your dreams
});

编辑(2018): 作者在2015年弃用了这个包:

扳手.js已弃用，并且在相当长的一段时间内没有更新。我强烈建议使用fs-extra来执行任何额外的文件系统操作。

There are basically two ways of accomplishing this. In an async environment you'll notice that there are two kinds of loops: serial and parallel. A serial loop waits for one iteration to complete before it moves onto the next iteration - this guarantees that every iteration of the loop completes in order. In a parallel loop, all the iterations are started at the same time, and one may complete before another, however, it is much faster than a serial loop. So in this case, it's probably better to use a parallel loop because it doesn't matter what order the walk completes in, just as long as it completes and returns the results (unless you want them in order).

一个平行循环看起来是这样的:

var fs = require('fs');
var path = require('path');
var walk = function(dir, done) {
  var results = [];
  fs.readdir(dir, function(err, list) {
    if (err) return done(err);
    var pending = list.length;
    if (!pending) return done(null, results);
    list.forEach(function(file) {
      file = path.resolve(dir, file);
      fs.stat(file, function(err, stat) {
        if (stat && stat.isDirectory()) {
          walk(file, function(err, res) {
            results = results.concat(res);
            if (!--pending) done(null, results);
          });
        } else {
          results.push(file);
          if (!--pending) done(null, results);
        }
      });
    });
  });
};

一个串行循环看起来像这样:

var fs = require('fs');
var path = require('path');
var walk = function(dir, done) {
  var results = [];
  fs.readdir(dir, function(err, list) {
    if (err) return done(err);
    var i = 0;
    (function next() {
      var file = list[i++];
      if (!file) return done(null, results);
      file = path.resolve(dir, file);
      fs.stat(file, function(err, stat) {
        if (stat && stat.isDirectory()) {
          walk(file, function(err, res) {
            results = results.concat(res);
            next();
          });
        } else {
          results.push(file);
          next();
        }
      });
    })();
  });
};

并且在你的主目录中测试它(警告:如果你的主目录中有很多东西，结果列表将会非常大):

walk(process.env.HOME, function(err, results) {
  if (err) throw err;
  console.log(results);
});

编辑:改进的示例。

a .看一下文件模块。它有一个叫walk的函数:

文件。步行(开始,回调) 导航文件树，为每个目录调用回调，传入 (null, dirPath, dirs, files)。

这可能是为你准备的!是的，它是异步的。但是，如果需要的话，我认为您必须自己聚合完整的路径。

B.另一种选择，甚至是我的最爱之一:使用unix find来查找。为什么要再做一件已经编程好的事情呢?也许不是你真正需要的，但仍然值得一试:

var execFile = require('child_process').execFile;
execFile('find', [ 'somepath/' ], function(err, stdout, stderr) {
  var file_list = stdout.split('\n');
  /* now you've got a list with full path file names */
});

Find有一个很好的内置缓存机制，使得后续搜索非常快，只要只有少数文件夹被更改。

香草ES6 +异步/等待+小和可读

我没有在这篇文章中找到我想要的答案;在不同的答案中有一些相似的元素，但我只想要一些简单易读的东西。

为了防止它在未来帮助到任何人(比如几个月后的我自己)，这就是我最终使用的:

const { readdir } = require('fs/promises');
const { join } = require('path');

const readdirRecursive = async dir => {
  const files = await readdir( dir, { withFileTypes: true } );

  const paths = files.map( async file => {
    const path = join( dir, file.name );

    if ( file.isDirectory() ) return await readdirRecursive( path );

    return path;
  } );

  return ( await Promise.all( paths ) ).flat( Infinity );
}

module.exports = {
  readdirRecursive,
}

还有一种方法。我把它放在这里。也许将来它会对某人有用。

const fs = require("fs");
const { promisify } = require("util");
const p = require("path");
const readdir = promisify(fs.readdir);

async function getFiles(path) {
  try {
    const entries = await readdir(path, { withFileTypes: true });

    const files = entries
      .filter((file) => !file.isDirectory())
      .map((file) => ({
        path: `${path}/${file.name}`,
        ext: p.extname(`${path}/${file.name}`),
        pathDir: path,
      }));

    const folders = entries.filter((folder) => folder.isDirectory());

    for (const folder of folders) {
      files.push(...(await getFiles(`${path}/${folder.name}`)));
    }
    return files;
  } catch (error) {
    return error;
  }
}

用法:

getFiles(rootFolderPath)
 .then()
 .catch()

另一个答案，但这次使用的是TypeScript:

/** * Recursively walk a directory asynchronously and obtain all file names (with full path). * * @param dir Folder name you want to recursively process * @param done Callback function, returns all files with full path. * @param filter Optional filter to specify which files to include, * e.g. for json files: (f: string) => /.json$/.test(f) */ const walk = ( dir: string, done: (err: Error | null, results ? : string[]) => void, filter ? : (f: string) => boolean ) => { let results: string[] = []; fs.readdir(dir, (err: Error, list: string[]) => { if (err) { return done(err); } let pending = list.length; if (!pending) { return done(null, results); } list.forEach((file: string) => { file = path.resolve(dir, file); fs.stat(file, (err2, stat) => { if (stat && stat.isDirectory()) { walk(file, (err3, res) => { if (res) { results = results.concat(res); } if (!--pending) { done(null, results); } }, filter); } else { if (typeof filter === 'undefined' || (filter && filter(file))) { results.push(file); } if (!--pending) { done(null, results); } } }); }); }); };