我有一个纯JavaScript承诺(内置实现或poly-fill):

var promise = new promise(函数(解析,拒绝){/*…* /});

从规范来看,Promise可以是:

" settle "和" resolved " “解决”和“拒绝” “等待”

我有一个用例,我希望同步审问承诺并确定:

承诺达成了吗? 如果是,承诺解决了吗?

我知道我可以使用#then()来安排在Promise改变状态后异步执行的工作。我不是在问你该怎么做。

这个问题是关于Promise状态的同步询问。我怎样才能做到这一点呢?


当前回答

如果你正在使用ES7实验版,你可以使用async轻松地包装你想要收听的承诺。

async function getClient() {
  let client, resolved = false;
  try {
    client = await new Promise((resolve, reject) => {
      let client = new Client();

      let timer = setTimeout(() => {
         reject(new Error(`timeout`, 1000));
         client.close();
      });

      client.on('ready', () => {
        if(!resolved) {
          clearTimeout(timer);
          resolve(client);
        }
      });

      client.on('error', (error) => {
        if(!resolved) {
          clearTimeout(timer);
          reject(error);
        }
      });

      client.on('close', (hadError) => {
        if(!resolved && !hadError) {
          clearTimeout(timer);
          reject(new Error("close"));
        }
      });
    });

    resolved = true;
  } catch(error) {
    resolved = true;
    throw error;
  }
  return client;
}

其他回答

在节点中,写入未记录的内部进程。

> process.binding('util').getPromiseDetails(Promise.resolve({data: [1,2,3]}));
[ 1, { data: [ 1, 2, 3 ] } ]

> process.binding('util').getPromiseDetails(Promise.reject(new Error('no')));
[ 2, Error: no ]

> process.binding('util').getPromiseDetails(new Promise((resolve) => {}));
[ 0, <1 empty item> ]

Promise-status-async可以做到。它是异步的,但它不使用然后等待承诺被解决。

const {promiseStatus} = require('promise-status-async');
// ...
if (await promiseStatus(promise) === 'pending') {
    const idle = new Promise(function(resolve) {
        // can do some IDLE job meanwhile
    });
    return idle;
}

这里是一个更充实的QueryablePromise的es6版本,允许在第一次解析后进行链接和捕获,并立即解析或拒绝以保持api与本机Promise一致。

const PROMISE = Symbol('PROMISE') const tap = fn => x => (fn(x), x) const trace = label => tap(x => console.log(label, x)) class QueryablePromise { resolved = false rejected = false fulfilled = false catchFns = [] constructor(fn) { this[PROMISE] = new Promise(fn) .then(tap(() => { this.fulfilled = true this.resolved = true })) .catch(x => { this.fulfilled = true this.rejected = true return Promise.reject(x) }) } then(fn) { this[PROMISE].then(fn) return this } catch(fn) { this[PROMISE].catch(fn) return this } static resolve(x) { return new QueryablePromise((res) => res(x)) } static reject(x) { return new QueryablePromise((_, rej) => rej(x)) } } const resolvedPromise = new QueryablePromise((res) => { setTimeout(res, 200, 'resolvedPromise') }) const rejectedPromise = new QueryablePromise((_, rej) => { setTimeout(rej, 200, 'rejectedPromise') }) // ensure our promises have not been fulfilled console.log('test 1 before: is resolved', resolvedPromise.resolved) console.log('test 2 before: is rejected', rejectedPromise.rejected) setTimeout(() => { // check to see the resolved status of our promise console.log('test 1 after: is resolved', resolvedPromise.resolved) console.log('test 2 after: is rejected', rejectedPromise.rejected) }, 300) // make sure we can immediately resolve a QueryablePromise const immediatelyResolvedPromise = QueryablePromise.resolve('immediatelyResolvedPromise') // ensure we can chain then .then(trace('test 3 resolved')) .then(trace('test 3 resolved 2')) .catch(trace('test 3 rejected')) // make sure we can immediately reject a QueryablePromise const immediatelyRejectedPromise = QueryablePromise.reject('immediatelyRejectedPromise') .then(trace('test 4 resolved')) .catch(trace('test 4 rejected')) <script src="https://codepen.io/synthet1c/pen/KyQQmL.js"></script>

警告:process.binding(“跑龙套”)。节点16上的getPromiseDetails未定义!

基准:

候选人:

/**
 * https://stackoverflow.com/a/47009572/5318303
 */
const isPromisePending1 = (() => { // noinspection JSUnresolvedFunction
    const util = process.binding('util')  // noinspection JSUnresolvedFunction
    return promise => !util.getPromiseDetails(promise)[0]
})()

/**
 * https://stackoverflow.com/a/35852666/5318303
 */
const isPromisePending2 = (promise) => util.inspect(promise) === 'Promise { <pending> }'

/**
 * https://stackoverflow.com/a/35820220/5318303
 */
const isPromisePending3 = (promise) => {
    const t = {}
    return Promise.race([promise, t])
            .then(v => v === t, () => false)
}

测试的承诺:

const a = Promise.resolve()
const b = Promise.reject()
const c = new Promise(() => {})
const x = (async () => 1)()

运行基准:

const n = 1000000

console.time('isPromisePending1')
for (let i = 0; i < n; i++) {
    isPromisePending1(a)
    isPromisePending1(b)
    isPromisePending1(c)
    isPromisePending1(x)
}
console.timeEnd('isPromisePending1')

console.time('isPromisePending2')
for (let i = 0; i < n; i++) {
    isPromisePending2(a)
    isPromisePending2(b)
    isPromisePending2(c)
    isPromisePending2(x)
}
console.timeEnd('isPromisePending2')

console.time('isPromisePending3')
for (let i = 0; i < n; i++) {
    await isPromisePending3(a)
    await isPromisePending3(b)
    await isPromisePending3(c)
    await isPromisePending3(x)
}
console.timeEnd('isPromisePending3')

结果:

isPromisePending1: 440.694ms
isPromisePending2: 3.354s
isPromisePending3: 4.761s

显然isPromisePending1()太快了(8~10倍)!但它在节点16上不可用!(见上述警告)。

2019:

据我所知,做到这一点的简单方法是thenable,超薄包装承诺或任何异步作业。

const sleep = (t) => new Promise(res => setTimeout(res,t));
const sleeping = sleep(30);

function track(promise){
    let state = 'pending';
    promise = promise.finally( _=> state ='fulfilled');
    return {
        get state(){return state},
        then: promise.then.bind(promise), /*thentable*/
        finally:promise.finally.bind(promise),
        catch:promise.catch.bind(promise),
    }
}


promise = track(sleeping);
console.log(promise.state) // pending

promise.then(function(){
    console.log(promise.state); // fulfilled
})