我如何转换字符串既像'helloThere'或'helloThere'到'HelloThere'在JavaScript?
当前回答
HTTPRequest_ToServer-AndWaiting --> HTTP Request To Server And Waiting
function toSpaceCase(str) { return str .replace(/[-_]/g, ' ') /* * insert a space between lower & upper * HttpRequest => Http Request */ .replace(/([a-z])([A-Z])/g, '$1 $2') /* * space before last upper in a sequence followed by lower * XMLHttp => XML Http */ .replace(/\b([A-Z]+)([A-Z])([a-z])/, '$1 $2$3') // uppercase the first character .replace(/^./, str => str.toUpperCase()) .replace(/\s+/g, ' ') .trim(); } const input = 'HTTPRequest_ToServer-AndWaiting'; const result = toSpaceCase(input); console.log(input,'-->', result)
其他回答
我没有尝试每个人的答案,但我修补过的几个解决方案并不能满足我所有的要求。
我想出了一个办法…
export const jsObjToCSSString = (o={}) =>
Object.keys(o)
.map(key => ({ key, value: o[key] }))
.map(({key, value}) =>
({
key: key.replace( /([A-Z])/g, "-$1").toLowerCase(),
value
})
)
.reduce(
(css, {key, value}) =>
`${css} ${key}: ${value}; `.trim(),
'')
添加了另一个ES6解决方案,我更喜欢上面的一些想法。
https://codepen.io/902Labs/pen/mxdxRv?editors=0010#0
const camelize = (str) => str
.split(' ')
.map(([first, ...theRest]) => (
`${first.toUpperCase()}${theRest.join('').toLowerCase()}`)
)
.join(' ');
你可以使用这样的函数:
function fixStr(str) {
var out = str.replace(/^\s*/, ""); // strip leading spaces
out = out.replace(/^[a-z]|[^\s][A-Z]/g, function(str, offset) {
if (offset == 0) {
return(str.toUpperCase());
} else {
return(str.substr(0,1) + " " + str.substr(1).toUpperCase());
}
});
return(out);
}
"hello World" ==> "Hello World"
"HelloWorld" ==> "Hello World"
"FunInTheSun" ==? "Fun In The Sun"
带有一堆测试字符串的代码:http://jsfiddle.net/jfriend00/FWLuV/。
保留前导空格的替代版本:http://jsfiddle.net/jfriend00/Uy2ac/。
此解决方案也适用于不在[A-Z]范围内的其他Unicode字符。例如:Ä, Ö, Å。
let camelCaseToTitleCase = (s) => (
s.split("").reduce(
(acc, letter, i) => (
i === 0 || console.log(acc, letter, i)
? [...acc, letter.toUpperCase()]
: letter === letter.toUpperCase()
? [...acc, " ", letter]
: [...acc, letter]
), []
).join("")
)
const myString = "ArchipelagoOfÅland"
camelCaseToTitleCase(myString)
我认为这可以用reg exp /([a-z]|[a-z] +)([a-z])/g和替换“$1 $2”来完成。
我爱美国的毒品