我在Bash中有一个字符串：
string="My string"
如何测试它是否包含另一个字符串？
if [ $string ?? 'foo' ]; then
echo "It's there!"
fi
哪里是我不认识的接线员。我使用echo和grep吗？
if echo "$string" | grep 'foo'; then
echo "It's there!"
fi
这看起来有点笨拙。
当前回答
您可以使用逻辑&&以更紧凑
#!/bin/bash
# NO MATCH EXAMPLE
string="test"
[[ "$string" == *"foo"* ]] && {
echo "YES"
}
# MATCH EXAMPLE
string="tefoost"
[[ "$string" == *"foo"* ]] && {
echo "YES"
}
其他回答
我不确定是否使用if语句，但您可以使用case语句获得类似的效果：
case "$string" in
*foo*)
# Do stuff
;;
esac
这个怎么样：
text=" <tag>bmnmn</tag> "
if [[ "$text" =~ "<tag>" ]]; then
echo "matched"
else
echo "not matched"
fi
一个是：
[ $(expr $mystring : ".*${search}.*") -ne 0 ] && echo 'yes' || echo 'no'
我使用这个函数（一个不包括但很明显的依赖项）。它通过了以下测试。如果函数返回值>0，则找到字符串。你也可以很容易地返回1或0。
function str_instr {
# Return position of ```str``` within ```string```.
# >>> str_instr "str" "string"
# str: String to search for.
# string: String to search.
typeset str string x
# Behavior here is not the same in bash vs ksh unless we escape special characters.
str="$(str_escape_special_characters "${1}")"
string="${2}"
x="${string%%$str*}"
if [[ "${x}" != "${string}" ]]; then
echo "${#x} + 1" | bc -l
else
echo 0
fi
}
function test_str_instr {
str_instr "(" "'foo@host (dev,web)'" | assert_eq 11
str_instr ")" "'foo@host (dev,web)'" | assert_eq 19
str_instr "[" "'foo@host [dev,web]'" | assert_eq 11
str_instr "]" "'foo@host [dev,web]'" | assert_eq 19
str_instr "a" "abc" | assert_eq 1
str_instr "z" "abc" | assert_eq 0
str_instr "Eggs" "Green Eggs And Ham" | assert_eq 7
str_instr "a" "" | assert_eq 0
str_instr "" "" | assert_eq 0
str_instr " " "Green Eggs" | assert_eq 6
str_instr " " " Green " | assert_eq 1
}
如果您喜欢正则表达式方法：
string='My string';
if [[ $string =~ "My" ]]; then
echo "It's there!"
fi
