如何检测用户用JavaScript在网页上向某个方向滑动手指?
我想知道是否有一种解决方案可以同时适用于iPhone和Android手机上的网站。
如何检测用户用JavaScript在网页上向某个方向滑动手指?
我想知道是否有一种解决方案可以同时适用于iPhone和Android手机上的网站。
当前回答
你可以监听touchstart和touchend事件,并根据事件数据计算方向和力(Codepen):
让start = null; 文档。addEventListener('touchstart', e => { const touch = e. changedtouchs[0]; Start = [touch.]clientX touch.clientY); }); 文档。addEventListener('touchend', e => { const touch = e. changedtouchs[0]; Const end = [touch.]clientX touch.clientY); document.body.innerText = " ${结束[0]-[0]开始},${结束[1]-[1]开始}'; }); 点击这里
或者你可以围绕同样的概念构建一个更符合人体工程学的API (Codepen):
const removeListener = addSwipeRightListener(document, (force, e) => {
console.info('Swiped right with force: ' + force);
});
// removeListener()
// swipe.js const { addSwipeLeftListener, addSwipeRightListener, addSwipeUpListener, addSwipeDownListener, } = (function() { // <element, {listeners: [...], handleTouchstart, handleTouchend}> const elements = new WeakMap(); function readTouch(e) { const touch = e.changedTouches[0]; if (touch == undefined) { return null; } return [touch.clientX, touch.clientY]; } function addListener(element, cb) { let elementValues = elements.get(element); if (elementValues === undefined) { const listeners = new Set(); const handleTouchstart = e => { elementValues.start = readTouch(e); }; const handleTouchend = e => { const start = elementValues.start; if (start === null) { return; } const end = readTouch(e); for (const listener of listeners) { listener([end[0] - start[0], end[1] - start[1]], e); } }; element.addEventListener('touchstart', handleTouchstart); element.addEventListener('touchend', handleTouchend); elementValues = { start: null, listeners, handleTouchstart, handleTouchend, }; elements.set(element, elementValues); } elementValues.listeners.add(cb); return () => deleteListener(element, cb); } function deleteListener(element, cb) { const elementValues = elements.get(element); const listeners = elementValues.listeners; listeners.delete(cb); if (listeners.size === 0) { elements.delete(element); element.removeEventListener('touchstart', elementValues.handleTouchstart); element.removeEventListener('touchend', elementValues.handleTouchend); } } function addSwipeLeftListener(element, cb) { return addListener(element, (force, e) => { const [x, y] = force; if (x < 0 && -x > Math.abs(y)) { cb(x, e); } }); } function addSwipeRightListener(element, cb) { return addListener(element, (force, e) => { const [x, y] = force; if (x > 0 && x > Math.abs(y)) { cb(x, e); } }); } function addSwipeUpListener(element, cb) { return addListener(element, (force, e) => { const [x, y] = force; if (y < 0 && -y > Math.abs(x)) { cb(x, e); } }); } function addSwipeDownListener(element, cb) { return addListener(element, (force, e) => { const [x, y] = force; if (y > 0 && y > Math.abs(x)) { cb(x, e); } }); } return { addSwipeLeftListener, addSwipeRightListener, addSwipeUpListener, addSwipeDownListener, } })(); // app.js function print(direction, force) { document.querySelector('#direction').innerText = direction; document.querySelector('#data').innerText = force; } addSwipeLeftListener(document, (force, e) => { print('left', force); }); addSwipeRightListener(document, (force, e) => { print('right', force); }); addSwipeUpListener(document, (force, e) => { print('up', force); }); addSwipeDownListener(document, (force, e) => { print('down', force); }); <h1>Swipe <span id="direction"></span></h1> Force (px): <span id="data"></span>
其他回答
如果有人试图在Android上使用jQuery Mobile,并且有JQM滑动检测的问题
(我在Xperia Z1, Galaxy S3, Nexus 4和一些Wiko手机上也有一些)这可能很有用:
//Fix swipe gesture on android
if(android){ //Your own device detection here
$.event.special.swipe.verticalDistanceThreshold = 500
$.event.special.swipe.horizontalDistanceThreshold = 10
}
在android上的滑动不会被检测到,除非它是一个非常长、精确和快速的滑动。
这两条线可以正常工作
使用两个:
jQuery移动控件:在大多数情况下都可以工作,特别是当你在开发使用其他jQuery插件的应用程序时,最好使用jQuery移动控件。请访问:https://www.w3schools.com/jquerymobile/jquerymobile_events_touch.asp
锤子时间!一个最好的,轻量级和快速的基于javascript的库。请访问:https://hammerjs.github.io/
一些mod的顶部回答(不能评论…)来处理短滑动
document.addEventListener('touchstart', handleTouchStart, false);
document.addEventListener('touchmove', handleTouchMove, false);
var xDown = null;
var yDown = null;
function handleTouchStart(evt) {
xDown = evt.touches[0].clientX;
yDown = evt.touches[0].clientY;
};
function handleTouchMove(evt) {
if ( ! xDown || ! yDown ) {
return;
}
var xUp = evt.touches[0].clientX;
var yUp = evt.touches[0].clientY;
var xDiff = xDown - xUp;
var yDiff = yDown - yUp;
if(Math.abs( xDiff )+Math.abs( yDiff )>150){ //to deal with to short swipes
if ( Math.abs( xDiff ) > Math.abs( yDiff ) ) {/*most significant*/
if ( xDiff > 0 ) {/* left swipe */
alert('left!');
} else {/* right swipe */
alert('right!');
}
} else {
if ( yDiff > 0 ) {/* up swipe */
alert('Up!');
} else { /* down swipe */
alert('Down!');
}
}
/* reset values */
xDown = null;
yDown = null;
}
};
我也合并了一些答案,主要是第一个和第二个与类,下面是我的版本:
export default class Swipe {
constructor(options) {
this.xDown = null;
this.yDown = null;
this.options = options;
this.handleTouchStart = this.handleTouchStart.bind(this);
this.handleTouchMove = this.handleTouchMove.bind(this);
document.addEventListener('touchstart', this.handleTouchStart, false);
document.addEventListener('touchmove', this.handleTouchMove, false);
}
onLeft() {
this.options.onLeft();
}
onRight() {
this.options.onRight();
}
onUp() {
this.options.onUp();
}
onDown() {
this.options.onDown();
}
static getTouches(evt) {
return evt.touches // browser API
}
handleTouchStart(evt) {
const firstTouch = Swipe.getTouches(evt)[0];
this.xDown = firstTouch.clientX;
this.yDown = firstTouch.clientY;
}
handleTouchMove(evt) {
if ( ! this.xDown || ! this.yDown ) {
return;
}
let xUp = evt.touches[0].clientX;
let yUp = evt.touches[0].clientY;
let xDiff = this.xDown - xUp;
let yDiff = this.yDown - yUp;
if ( Math.abs( xDiff ) > Math.abs( yDiff ) ) {/*most significant*/
if ( xDiff > 0 && this.options.onLeft) {
/* left swipe */
this.onLeft();
} else if (this.options.onRight) {
/* right swipe */
this.onRight();
}
} else {
if ( yDiff > 0 && this.options.onUp) {
/* up swipe */
this.onUp();
} else if (this.options.onDown){
/* down swipe */
this.onDown();
}
}
/* reset values */
this.xDown = null;
this.yDown = null;
}
}
之后可以这样使用:
let swiper = new Swipe({
onLeft() {
console.log('You swiped left.');
}
});
当你只想调用“onLeft”方法时,它有助于避免控制台错误。
在这里的建议之上,我将跟踪手指号码,因为如果你同时用两个手指触摸,它将获得X位置,而不会导致一个奇怪的行为,而且,你可能想要设置一个“距离”最小值,这样用户在通过你的网站或应用程序触摸时就不会错误地触发滑动。
//Swipe
let touchstartX = 0
let touchendX = 0
let fingerCount = 0
const checkDirection = () => {
const distance = 50 //Minimum distance for the swipe to work
//left
if (touchendX < touchstartX && (touchstartX - touchendX) > distance ){
//Do something cool
}
//right
if (touchendX > touchstartX && (touchendX - touchstartX) > distance){
//Do something cooler
}
document.addEventListener('touchstart', e => {
fingerCount = e.touches.length
touchstartX = e.changedTouches[0].clientX
})
document.addEventListener('touchend', e => {
touchendX = e.changedTouches[0].clientX
if(fingerCount === 1){
checkDirection()
}
})