我已经创建了下一个字典:
var postJSON = [ids[0]:answersArray[0], ids[1]:answersArray[1], ids[2]:answersArray[2]] as Dictionary
得到:
[2: B, 1: A, 3: C]
那么,如何将其转换为JSON呢?
我已经创建了下一个字典:
var postJSON = [ids[0]:answersArray[0], ids[1]:answersArray[1], ids[2]:answersArray[2]] as Dictionary
得到:
[2: B, 1: A, 3: C]
那么,如何将其转换为JSON呢?
当前回答
do{
let dataDict = [ "level" :
[
["column" : 0,"down" : 0,"left" : 0,"right" : 0,"row" : 0,"up" : 0],
["column" : 1,"down" : 0,"left" : 0,"right" : 0,"row" : 0,"up" : 0],
["column" : 2,"down" : 0,"left" : 0,"right" : 0,"row" : 0,"up" : 0],
["column" : 0,"down" : 0,"left" : 0,"right" : 0,"row" : 1,"up" : 0],
["column" : 1,"down" : 0,"left" : 0,"right" : 0,"row" : 1,"up" : 0],
["column" : 2,"down" : 0,"left" : 0,"right" : 0,"row" : 1,"up" : 0]
]
]
var jsonData = try JSONSerialization.data(withJSONObject: dataDict, options: JSONSerialization.WritingOptions.prettyPrinted)
let jsonStringData = NSString(data: jsonData as Data, encoding: NSUTF8StringEncoding)! as String
print(jsonStringData)
}catch{
print(error.localizedDescription)
}
其他回答
我对你的问题的回答如下
let dict = ["0": "ArrayObjectOne", "1": "ArrayObjecttwo", "2": "ArrayObjectThree"]
var error : NSError?
let jsonData = try! NSJSONSerialization.dataWithJSONObject(dict, options: NSJSONWritingOptions.PrettyPrinted)
let jsonString = NSString(data: jsonData, encoding: String.Encoding.utf8.rawValue)! as String
print(jsonString)
答案是
{
"0" : "ArrayObjectOne",
"1" : "ArrayObjecttwo",
"2" : "ArrayObjectThree"
}
在Swift 5.4中
extension Dictionary {
var jsonData: Data? {
return try? JSONSerialization.data(withJSONObject: self, options: [.prettyPrinted])
}
func toJSONString() -> String? {
if let jsonData = jsonData {
let jsonString = String(data: jsonData, encoding: .utf8)
return jsonString
}
return nil
}
}
把它作为变量的想法是,这样你就可以像这样重用它:
extension Dictionary {
func decode<T:Codable>() throws -> T {
return try JSONDecoder().decode(T.self, from: jsonData ?? Data())
}
}
使用lldb
(lldb) p JSONSerialization.data(withJSONObject: notification.request.content.userInfo, options: [])
(Data) $R16 = 375 bytes
(lldb) p String(data: $R16!, encoding: .utf8)!
(String) $R18 = "{\"aps\": \"some_text\"}"
//or
p String(data: JSONSerialization.data(withJSONObject: notification.request.content.userInfo, options: [])!, encoding: .utf8)!
(String) $R4 = "{\"aps\": \"some_text\"}"
斯威夫特5:
let dic = ["2": "B", "1": "A", "3": "C"]
let encoder = JSONEncoder()
if let jsonData = try? encoder.encode(dic) {
if let jsonString = String(data: jsonData, encoding: .utf8) {
print(jsonString)
}
}
注意键和值必须实现Codable。字符串、整型和双精度(以及更多)已经是可编码的。参见编码和解码自定义类型。
还要注意,Any不符合Codable。这可能仍然是一个很好的方法来调整你的数据成为可编码的,这样你就可以使用Swift类型(特别是在你也要解码任何编码的json的情况下),这样你就可以更声明你的编码的结果。
这是一个简单的扩展来做到这一点:
https://gist.github.com/stevenojo/0cb8afcba721838b8dcb115b846727c3
extension Dictionary {
func jsonString() -> NSString? {
let jsonData = try? JSONSerialization.data(withJSONObject: self, options: [])
guard jsonData != nil else {return nil}
let jsonString = String(data: jsonData!, encoding: .utf8)
guard jsonString != nil else {return nil}
return jsonString! as NSString
}
}