预期的输入:
getDatesFromRange( '2010-10-01', '2010-10-05' );
预期的输出:
Array( '2010-10-01', '2010-10-02', '2010-10-03', '2010-10-04', '2010-10-05' )
预期的输入:
getDatesFromRange( '2010-10-01', '2010-10-05' );
预期的输出:
Array( '2010-10-01', '2010-10-02', '2010-10-03', '2010-10-04', '2010-10-05' )
当前回答
为了让穆斯塔法的回答更完整,这绝对是最简单和最有效的方法:
function getDatesFromRange($start_date, $end_date, $date_format = 'Y-m-d')
{
$dates_array = array();
for ($x = strtotime($start_date); $x <= strtotime($end_date); $x += 86400) {
array_push($dates_array, date($date_format, $x));
}
return $dates_array;
}
// see the dates in the array
print_r( getDatesFromRange('2017-02-09', '2017-02-19') );
如果在调用函数时添加第三个参数,您甚至可以更改默认的输出日期格式,否则它将使用默认格式,即设置为'Y-m-d'。
我希望它能帮助你:)
其他回答
使用DateTime对象的PHP 5.2解决方案。但是startDate必须在endDate之前。
function createRange($startDate, $endDate) {
$tmpDate = new DateTime($startDate);
$tmpEndDate = new DateTime($endDate);
$outArray = array();
do {
$outArray[] = $tmpDate->format('Y-m-d');
} while ($tmpDate->modify('+1 day') <= $tmpEndDate);
return $outArray;
}
使用:
$dates = createRange('2010-10-01', '2010-10-05');
$日期包含:
Array( '2010-10-01', '2010-10-02', '2010-10-03', '2010-10-04', '2010-10-05' )
function GetDays($sStartDate, $sEndDate){
// Firstly, format the provided dates.
// This function works best with YYYY-MM-DD
// but other date formats will work thanks
// to strtotime().
$sStartDate = gmdate("Y-m-d", strtotime($sStartDate));
$sEndDate = gmdate("Y-m-d", strtotime($sEndDate));
// Start the variable off with the start date
$aDays[] = $sStartDate;
// Set a 'temp' variable, sCurrentDate, with
// the start date - before beginning the loop
$sCurrentDate = $sStartDate;
// While the current date is less than the end date
while($sCurrentDate < $sEndDate){
// Add a day to the current date
$sCurrentDate = gmdate("Y-m-d", strtotime("+1 day", strtotime($sCurrentDate)));
// Add this new day to the aDays array
$aDays[] = $sCurrentDate;
}
// Once the loop has finished, return the
// array of days.
return $aDays;
}
使用像
GetDays('2007-01-01', '2007-01-31');
下面是一个函数,它将从两个方向返回日期范围,适用于PHP >=5.2.2:
function createRange($start, $end, $format = 'Y-m-d') {
$start = new DateTime($start);
$end = new DateTime($end);
$invert = $start > $end;
$dates = array();
$dates[] = $start->format($format);
while ($start != $end) {
$start->modify(($invert ? '-' : '+') . '1 day');
$dates[] = $start->format($format);
}
return $dates;
}
使用的例子:
print_r(createRange('2010-10-01', '2010-10-05'));
/*Array
(
[0] => 2010-10-01
[1] => 2010-10-02
[2] => 2010-10-03
[3] => 2010-10-04
[4] => 2010-10-05
)*/
print_r(createRange('2010-10-05', '2010-10-01', 'j M Y'));
/*Array
(
[0] => 5 Oct 2010
[1] => 4 Oct 2010
[2] => 3 Oct 2010
[3] => 2 Oct 2010
[4] => 1 Oct 2010
)*/
demo
function createDateRangeArray($start, $end) {
// Modified by JJ Geewax
$range = array();
if (is_string($start) === true) $start = strtotime($start);
if (is_string($end) === true ) $end = strtotime($end);
if ($start > $end) return createDateRangeArray($end, $start);
do {
$range[] = date('Y-m-d', $start);
$start = strtotime("+ 1 day", $start);
}
while($start < $end);
return $range;
}
来源:http://boonedocks.net/mike/archives/137-Creating-a-Date-Range-Array-with-PHP.html
function getWeekdayDatesFrom($format, $start_date_epoch, $end_date_epoch, $range) {
$dates_arr = array();
if( ! $range) {
$range = round(abs($start_date_epoch-$end_date_epoch)/86400) + 1;
} else {
$range = $range + 1; //end date inclusive
}
$current_date_epoch = $start_date_epoch;
for($i = 1; $i <= $range; $i+1) {
$d = date('N', $current_date_epoch);
if($d <= 5) { // not sat or sun
$dates_arr[] = "'".date($format, $current_date_epoch)."'";
}
$next_day_epoch = strtotime('+'.$i.'day', $start_date_epoch);
$i++;
$current_date_epoch = $next_day_epoch;
}
return $dates_arr;
}