这是非常灵活的。

/**
 * Creating date collection between two dates
 *
 * <code>
 * <?php
 * # Example 1
 * date_range("2014-01-01", "2014-01-20", "+1 day", "m/d/Y");
 *
 * # Example 2. you can use even time
 * date_range("01:00:00", "23:00:00", "+1 hour", "H:i:s");
 * </code>
 *
 * @author Ali OYGUR <alioygur@gmail.com>
 * @param string since any date, time or datetime format
 * @param string until any date, time or datetime format
 * @param string step
 * @param string date of output format
 * @return array
 */
function date_range($first, $last, $step = '+1 day', $output_format = 'd/m/Y' ) {

    $dates = array();
    $current = strtotime($first);
    $last = strtotime($last);

    while( $current <= $last ) {

        $dates[] = date($output_format, $current);
        $current = strtotime($step, $current);
    }

    return $dates;
}

使用DateTime对象的PHP 5.2解决方案。但是startDate必须在endDate之前。

function createRange($startDate, $endDate) {
    $tmpDate = new DateTime($startDate);
    $tmpEndDate = new DateTime($endDate);

    $outArray = array();
    do {
        $outArray[] = $tmpDate->format('Y-m-d');
    } while ($tmpDate->modify('+1 day') <= $tmpEndDate);

    return $outArray;
}

使用:

$dates = createRange('2010-10-01', '2010-10-05');

$日期包含:

Array( '2010-10-01', '2010-10-02', '2010-10-03', '2010-10-04', '2010-10-05' )       

<?
print_r(getDatesFromRange( '2010-10-01', '2010-10-05' ));

function getDatesFromRange($startDate, $endDate)
{
    $return = array($startDate);
    $start = $startDate;
    $i=1;
    if (strtotime($startDate) < strtotime($endDate))
    {
       while (strtotime($start) < strtotime($endDate))
        {
            $start = date('Y-m-d', strtotime($startDate.'+'.$i.' days'));
            $return[] = $start;
            $i++;
        }
    }

    return $return;
}

我认为这是最简短的答案

按照您的喜好编辑代码

for ($x=strtotime('2015-12-01');$x<=strtotime('2015-12-30');$x+=86400)
echo date('Y-m-d',$x);

这是非常灵活的。

/**
 * Creating date collection between two dates
 *
 * <code>
 * <?php
 * # Example 1
 * date_range("2014-01-01", "2014-01-20", "+1 day", "m/d/Y");
 *
 * # Example 2. you can use even time
 * date_range("01:00:00", "23:00:00", "+1 hour", "H:i:s");
 * </code>
 *
 * @author Ali OYGUR <alioygur@gmail.com>
 * @param string since any date, time or datetime format
 * @param string until any date, time or datetime format
 * @param string step
 * @param string date of output format
 * @return array
 */
function date_range($first, $last, $step = '+1 day', $output_format = 'd/m/Y' ) {

    $dates = array();
    $current = strtotime($first);
    $last = strtotime($last);

    while( $current <= $last ) {

        $dates[] = date($output_format, $current);
        $current = strtotime($step, $current);
    }

    return $dates;
}

// will return dates array
function returnBetweenDates( $startDate, $endDate ){
    $startStamp = strtotime(  $startDate );
    $endStamp   = strtotime(  $endDate );

    if( $endStamp > $startStamp ){
        while( $endStamp >= $startStamp ){

            $dateArr[] = date( 'Y-m-d', $startStamp );

            $startStamp = strtotime( ' +1 day ', $startStamp );

        }
        return $dateArr;    
    }else{
        return $startDate;
    }

}

returnBetweenDates( '2014-09-16', '2014-09-26' );

// print_r( returnBetweenDates( '2014-09-16', '2014-09-26' ) );

它将返回如下所示的数组:

Array
(
    [0] => 2014-09-16
    [1] => 2014-09-17
    [2] => 2014-09-18
    [3] => 2014-09-19
    [4] => 2014-09-20
    [5] => 2014-09-21
    [6] => 2014-09-22
    [7] => 2014-09-23
    [8] => 2014-09-24
    [9] => 2014-09-25
    [10] => 2014-09-26
)