我的程序在后台线程中执行一些网络活动。在开始之前,它会弹出一个进度对话框。该对话框在处理程序上被解除。这一切都很好,除了当对话框打开时屏幕方向发生变化(背景线程正在运行)。此时,应用程序要么崩溃,要么死锁,要么进入一个奇怪的阶段,在所有线程被杀死之前,应用程序根本无法工作。

我如何处理屏幕方向的变化优雅?

下面的示例代码大致匹配我的实际程序:

public class MyAct extends Activity implements Runnable {
    public ProgressDialog mProgress;

    // UI has a button that when pressed calls send

    public void send() {
         mProgress = ProgressDialog.show(this, "Please wait", 
                      "Please wait", 
                      true, true);
        Thread thread = new Thread(this);
        thread.start();
    }

    public void run() {
        Thread.sleep(10000);
        Message msg = new Message();
        mHandler.sendMessage(msg);
    }

    private final Handler mHandler = new Handler() {
        @Override
        public void handleMessage(Message msg) {
            mProgress.dismiss();
        }
    };
}

栈:

E/WindowManager(  244): Activity MyAct has leaked window com.android.internal.policy.impl.PhoneWindow$DecorView@433b7150 that was originally added here
E/WindowManager(  244): android.view.WindowLeaked: Activity MyAct has leaked window com.android.internal.policy.impl.PhoneWindow$DecorView@433b7150 that was originally added here
E/WindowManager(  244):     at android.view.ViewRoot.<init>(ViewRoot.java:178)
E/WindowManager(  244):     at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:147)
E/WindowManager(  244):     at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:90)
E/WindowManager(  244):     at android.view.Window$LocalWindowManager.addView(Window.java:393)
E/WindowManager(  244):     at android.app.Dialog.show(Dialog.java:212)
E/WindowManager(  244):     at android.app.ProgressDialog.show(ProgressDialog.java:103)
E/WindowManager(  244):     at android.app.ProgressDialog.show(ProgressDialog.java:91)
E/WindowManager(  244):     at MyAct.send(MyAct.java:294)
E/WindowManager(  244):     at MyAct$4.onClick(MyAct.java:174)
E/WindowManager(  244):     at android.view.View.performClick(View.java:2129)
E/WindowManager(  244):     at android.view.View.onTouchEvent(View.java:3543)
E/WindowManager(  244):     at android.widget.TextView.onTouchEvent(TextView.java:4664)
E/WindowManager(  244):     at android.view.View.dispatchTouchEvent(View.java:3198)

我已经尝试在onSaveInstanceState中取消进度对话框,但这只是防止了立即崩溃。背景线程仍在运行,UI处于部分绘制状态。需要在它重新开始工作之前杀死整个应用程序。


当前回答

最初的问题是代码无法在屏幕方向改变时存活下来。显然,这是“解决”的程序处理屏幕方向变化本身,而不是让UI框架做它(通过调用onDestroy)。

I would submit that if the underlying problem is that the program will not survive onDestroy(), then the accepted solution is just a workaround that leaves the program with serious other problems and vulnerabilities. Remember that the Android framework specifically states that your activity is at risk for being destroyed almost at any time due to circumstances outside your control. Therefore, your activity must be able to survive onDestroy() and subsequent onCreate() for any reason, not just a screen orientation change.

如果你要接受自己处理屏幕方向变化来解决OP的问题,你需要验证onDestroy()的其他原因不会导致相同的错误。你能做到吗?如果不是,我会质疑这个“公认的”答案是否真的是一个很好的答案。

其他回答

当你切换方向时,Android会创建一个新的View。你可能会崩溃,因为你的后台线程试图改变旧线程的状态。(它也可能有麻烦,因为你的后台线程不在UI线程上)

我建议将mHandler设为volatile,并在方向改变时更新它。

看起来太“快速和肮脏”了,所以请指出缺点,但我发现有用的是……

在我的AsyncTask的onPostExecute方法中,我简单地包装了`。try/catch块中的进度对话框(带有空捕获)的Dismiss ',然后简单地忽略所引发的异常。似乎是错误的,但似乎没有不良影响(至少对于我随后所做的事情,这是启动另一个活动,将我的长时间运行查询的结果传递为一个额外)

当你改变方向时,Android会终止那个活动并创建新的活动。 我建议使用Rx java的retrofit。自动处理崩溃。

在改造调用时使用这些方法。

.subscribeOn (Schedulers.io ()) .observeOn (AndroidSchedulers.mainThread ())

我是这样做的:

    package com.palewar;
    import android.app.Activity;
    import android.app.ProgressDialog;
    import android.os.Bundle;
    import android.os.Handler;
    import android.os.Message;

    public class ThreadActivity extends Activity {


        static ProgressDialog dialog;
        private Thread downloadThread;
        final static Handler handler = new Handler() {

            @Override
            public void handleMessage(Message msg) {

                super.handleMessage(msg);

                dialog.dismiss();

            }

        };

        protected void onDestroy() {
    super.onDestroy();
            if (dialog != null && dialog.isShowing()) {
                dialog.dismiss();
                dialog = null;
            }

        }

        /** Called when the activity is first created. */
        @Override
        public void onCreate(Bundle savedInstanceState) {
            super.onCreate(savedInstanceState);
            setContentView(R.layout.main);

            downloadThread = (Thread) getLastNonConfigurationInstance();
            if (downloadThread != null && downloadThread.isAlive()) {
                dialog = ProgressDialog.show(ThreadActivity.this, "",
                        "Signing in...", false);
            }

            dialog = ProgressDialog.show(ThreadActivity.this, "",
                    "Signing in ...", false);

            downloadThread = new MyThread();
            downloadThread.start();
            // processThread();
        }

        // Save the thread
        @Override
        public Object onRetainNonConfigurationInstance() {
            return downloadThread;
        }


        static public class MyThread extends Thread {
            @Override
            public void run() {

                try {
                    // Simulate a slow network
                    try {
                        new Thread().sleep(5000);
                    } catch (InterruptedException e) {
                        e.printStackTrace();
                    }
                    handler.sendEmptyMessage(0);

                } finally {

                }
            }
        }

    }

你也可以试着让我知道它对你是否有效

如果你维护两个布局,所有的UI线程都应该终止。

如果你使用AsynTask,那么你可以很容易地在当前活动的onDestroy()方法中调用.cancel()方法。

@Override
protected void onDestroy (){
    removeDialog(DIALOG_LOGIN_ID); // remove loading dialog
    if (loginTask != null){
        if (loginTask.getStatus() != AsyncTask.Status.FINISHED)
            loginTask.cancel(true); //cancel AsyncTask
    }
    super.onDestroy();
}

对于AsyncTask,请在“取消任务”部分阅读更多信息。

更新: 增加了检查状态的条件,因为只有当它处于运行状态时才能取消。 还要注意,AsyncTask只能执行一次。