我的程序在后台线程中执行一些网络活动。在开始之前,它会弹出一个进度对话框。该对话框在处理程序上被解除。这一切都很好,除了当对话框打开时屏幕方向发生变化(背景线程正在运行)。此时,应用程序要么崩溃,要么死锁,要么进入一个奇怪的阶段,在所有线程被杀死之前,应用程序根本无法工作。

我如何处理屏幕方向的变化优雅?

下面的示例代码大致匹配我的实际程序:

public class MyAct extends Activity implements Runnable {
    public ProgressDialog mProgress;

    // UI has a button that when pressed calls send

    public void send() {
         mProgress = ProgressDialog.show(this, "Please wait", 
                      "Please wait", 
                      true, true);
        Thread thread = new Thread(this);
        thread.start();
    }

    public void run() {
        Thread.sleep(10000);
        Message msg = new Message();
        mHandler.sendMessage(msg);
    }

    private final Handler mHandler = new Handler() {
        @Override
        public void handleMessage(Message msg) {
            mProgress.dismiss();
        }
    };
}

栈:

E/WindowManager(  244): Activity MyAct has leaked window com.android.internal.policy.impl.PhoneWindow$DecorView@433b7150 that was originally added here
E/WindowManager(  244): android.view.WindowLeaked: Activity MyAct has leaked window com.android.internal.policy.impl.PhoneWindow$DecorView@433b7150 that was originally added here
E/WindowManager(  244):     at android.view.ViewRoot.<init>(ViewRoot.java:178)
E/WindowManager(  244):     at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:147)
E/WindowManager(  244):     at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:90)
E/WindowManager(  244):     at android.view.Window$LocalWindowManager.addView(Window.java:393)
E/WindowManager(  244):     at android.app.Dialog.show(Dialog.java:212)
E/WindowManager(  244):     at android.app.ProgressDialog.show(ProgressDialog.java:103)
E/WindowManager(  244):     at android.app.ProgressDialog.show(ProgressDialog.java:91)
E/WindowManager(  244):     at MyAct.send(MyAct.java:294)
E/WindowManager(  244):     at MyAct$4.onClick(MyAct.java:174)
E/WindowManager(  244):     at android.view.View.performClick(View.java:2129)
E/WindowManager(  244):     at android.view.View.onTouchEvent(View.java:3543)
E/WindowManager(  244):     at android.widget.TextView.onTouchEvent(TextView.java:4664)
E/WindowManager(  244):     at android.view.View.dispatchTouchEvent(View.java:3198)

我已经尝试在onSaveInstanceState中取消进度对话框,但这只是防止了立即崩溃。背景线程仍在运行,UI处于部分绘制状态。需要在它重新开始工作之前杀死整个应用程序。


当前回答

我发现了一个我还没有在其他地方见过的解决方案。你可以使用一个自定义应用程序对象,它知道你是否有后台任务在进行,而不是试图在活动中做这件事,在方向改变时被销毁和重新创建。我在这里写过博客。

其他回答

对于这些问题,我想出了一个坚如磐石的解决方案,它符合“Android方式”。我使用IntentService模式进行所有长时间运行的操作。

也就是说,我的活动广播意图,IntentService负责工作,将数据保存在DB中,然后广播粘性意图。粘性部分很重要,即使Activity在用户启动工作后暂停,并且错过了来自IntentService的实时广播,我们仍然可以响应并从调用Activity中获取数据。progressdialog可以很好地使用onSaveInstanceState()与此模式一起工作。

Basically, you need to save a flag that you have a progress dialog running in the saved instance bundle. Do not save the progress dialog object because this will leak the entire Activity. To have a persistent handle to the progress dialog, I store it as a weak reference in the application object. On orientation change or anything else that causes the Activity to pause (phone call, user hits home etc.) and then resume, I dismiss the old dialog and recreate a new dialog in the newly created Activity.

对于无限进度对话框来说,这很容易。对于进度条样式,您必须将最后一个已知的进度放在bundle中,并将您在活动中本地使用的任何信息用于跟踪进度。在恢复进度时,您将使用此信息以与之前相同的状态重新生成进度条,然后根据当前状态进行更新。

总之,将长时间运行的任务放到IntentService中,再加上明智地使用onSaveInstanceState(),可以让你有效地跟踪对话框,并在活动生命周期事件中恢复对话框。活动代码的相关部分如下。您还需要BroadcastReceiver中的逻辑来适当地处理Sticky意图,但这超出了本文的范围。

public void doSignIn(View view) {
    waiting=true;
    AppClass app=(AppClass) getApplication();
    String logingon=getString(R.string.signon);
    app.Dialog=new WeakReference<ProgressDialog>(ProgressDialog.show(AddAccount.this, "", logingon, true));
    ...
}

@Override
protected void onSaveInstanceState(Bundle saveState) {
    super.onSaveInstanceState(saveState);
    saveState.putBoolean("waiting",waiting);
}

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    if(savedInstanceState!=null) {
        restoreProgress(savedInstanceState);    
    }
    ...
}

private void restoreProgress(Bundle savedInstanceState) {
    waiting=savedInstanceState.getBoolean("waiting");
    if (waiting) {
        AppClass app=(AppClass) getApplication();
        ProgressDialog refresher=(ProgressDialog) app.Dialog.get();
        refresher.dismiss();
        String logingon=getString(R.string.signon);
        app.Dialog=new WeakReference<ProgressDialog>(ProgressDialog.show(AddAccount.this, "", logingon, true));
    }
}

看起来太“快速和肮脏”了,所以请指出缺点,但我发现有用的是……

在我的AsyncTask的onPostExecute方法中,我简单地包装了`。try/catch块中的进度对话框(带有空捕获)的Dismiss ',然后简单地忽略所引发的异常。似乎是错误的,但似乎没有不良影响(至少对于我随后所做的事情,这是启动另一个活动,将我的长时间运行查询的结果传递为一个额外)

我是这样做的:

    package com.palewar;
    import android.app.Activity;
    import android.app.ProgressDialog;
    import android.os.Bundle;
    import android.os.Handler;
    import android.os.Message;

    public class ThreadActivity extends Activity {


        static ProgressDialog dialog;
        private Thread downloadThread;
        final static Handler handler = new Handler() {

            @Override
            public void handleMessage(Message msg) {

                super.handleMessage(msg);

                dialog.dismiss();

            }

        };

        protected void onDestroy() {
    super.onDestroy();
            if (dialog != null && dialog.isShowing()) {
                dialog.dismiss();
                dialog = null;
            }

        }

        /** Called when the activity is first created. */
        @Override
        public void onCreate(Bundle savedInstanceState) {
            super.onCreate(savedInstanceState);
            setContentView(R.layout.main);

            downloadThread = (Thread) getLastNonConfigurationInstance();
            if (downloadThread != null && downloadThread.isAlive()) {
                dialog = ProgressDialog.show(ThreadActivity.this, "",
                        "Signing in...", false);
            }

            dialog = ProgressDialog.show(ThreadActivity.this, "",
                    "Signing in ...", false);

            downloadThread = new MyThread();
            downloadThread.start();
            // processThread();
        }

        // Save the thread
        @Override
        public Object onRetainNonConfigurationInstance() {
            return downloadThread;
        }


        static public class MyThread extends Thread {
            @Override
            public void run() {

                try {
                    // Simulate a slow network
                    try {
                        new Thread().sleep(5000);
                    } catch (InterruptedException e) {
                        e.printStackTrace();
                    }
                    handler.sendEmptyMessage(0);

                } finally {

                }
            }
        }

    }

你也可以试着让我知道它对你是否有效

我也遇到过同样的情况。我所做的就是在整个应用程序中只获取一个进度对话框的实例。

首先,我创建了一个DialogSingleton类来只获得一个实例(Singleton模式)

public class DialogSingleton
{
    private static Dialog dialog;

    private static final Object mLock = new Object();
    private static DialogSingleton instance;

    private DialogSingleton()
    {

    }

    public static DialogSingleton GetInstance()
    {
        synchronized (mLock)
        {
            if(instance == null)
            {
                instance = new DialogSingleton();
            }

            return instance;
        }
    }

    public void DialogShow(Context context, String title)
    {
        if(!((Activity)context).isFinishing())
        {
            dialog = new ProgressDialog(context, 2);

            dialog.setCanceledOnTouchOutside(false);

            dialog.setTitle(title);

            dialog.show();
        }
    }

    public void DialogDismiss(Context context)
    {
        if(!((Activity)context).isFinishing() && dialog.isShowing())
        {
            dialog.dismiss();
        }
    }
}

正如我在这个类中所展示的,我将进度对话框作为属性。每次我需要显示一个进度对话框时,我都会获得唯一的实例并创建一个新的ProgressDialog。

DialogSingleton.GetInstance().DialogShow(this, "My title here!");

当我完成后台任务时,我再次调用惟一实例并关闭它的对话框。

DialogSingleton.GetInstance().DialogDismiss(this);

我将后台任务状态保存在共享首选项中。当我旋转屏幕时,我问我是否有这个活动的任务运行:(onCreate)

if(Boolean.parseBoolean(preference.GetValue(IS_TASK_NAME_EXECUTED_KEY, "boolean").toString()))
{
    DialogSingleton.GetInstance().DialogShow(this, "Checking credentials!");
} // preference object gets the info from shared preferences (my own implementation to get and put data to shared preferences) and IS_TASK_NAME_EXECUTED_KEY is the key to save this flag (flag to know if this activity has a background task already running).

当我开始运行后台任务时:

preference.AddValue(IS_TASK_NAME_EXECUTED_KEY, true, "boolean");

DialogSingleton.GetInstance().DialogShow(this, "My title here!");

当我完成运行后台任务:

preference.AddValue(IS_TASK_NAME_EXECUTED_KEY, false, "boolean");

DialogSingleton.GetInstance().DialogDismiss(ActivityName.this);

我希望这能有所帮助。

将长任务移动到单独的类中。将其实现为主题-观察者模式。每当创建活动时,注册并在关闭时注销任务类。任务类可以使用AsyncTask。