我想要一个5个字符的字符串,由从集合[a-zA-Z0-9]中随机选取的字符组成。

用JavaScript实现这一点的最佳方法是什么?


当前回答

您可以使用Web Crypto的API:

console.log(self.crypto.getRandomValues(新Uint32Array(1))[0])

(此处为原始答案)

其他回答

最重要的是,所有的答案都是完美的。但我要补充的是,生成任何随机字符串值都非常好而且快速

函数randomStringGenerator(stringLength){var randomString=“”;//选择变量的空值const allCharacters=“`~!@#$%^&*()_+-={}[]:;\'<>?,./|\\ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijlmnopqrstuvwxyz0123456789'”;//所有字母数字字母列表while(stringLength--){randomString+=allCharacters.substr(Math.floor((Math.random()*allCharacters.length)+1),1);//使用Math.random()从所有字符变量中选择任意值}return randomString;//返回生成的字母数字字符串}console.log(randomStringGenerator(10))//通过输入所需的随机字符串来调用函数

or

console.log(Date.now())//它每次都会产生随机的十三个数字字符值。console.log(Date.now().toString().length)//打印生成字符串的长度

这是Coffeescapet版本的一行代码

genRandomString = (length,set) -> [0...length].map( -> set.charAt Math.floor(Math.random() * set.length)).join('')

用法:

genRandomString 5, 'ABCDEFTGHIJKLMNOPQRSTUVWXYZ'

输出:

'FHOOV' # random string of length 5 in possible set A~Z
function generate(length) {
  var letters = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z","A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z","0","1","2","3","4","5","6","7","8","9"];
  var IDtext = "";
  var i = 0;
  while (i < length) {
    var letterIndex = Math.floor(Math.random() * letters.length);
    var letter = letters[letterIndex];
    IDtext = IDtext + letter;
    i++;
  }
  console.log(IDtext)
}

假设您使用underscorejs,就可以在两行中优雅地生成随机字符串:

var possible = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789';
var random = _.sample(possible, 5).join('');

我知道每个人都已经做好了,但我想以最轻量级的方式(轻代码,而不是CPU)尝试一下:

函数rand(长度,电流){电流=电流?当前:“”;返回长度?rand(--length,“0123456789ABCDEFGHIJKLMNOPQRSTUVWXTZabcdefghiklmnopqrstuvxyz”.charAt(Math.floor(Math.random()*60))+电流):电流;}console.log(rand(5));

这需要一点时间来理解,但我认为它确实显示了javascript的语法是多么棒。