如何将JavaScript对象转换为字符串?
例子:
var o = {a:1, b:2}
console.log(o)
console.log('Item: ' + o)
输出:
对象{a=1, b=2} //非常好的可读输出:) Item: [object object] //不知道里面有什么:(
如何将JavaScript对象转换为字符串?
例子:
var o = {a:1, b:2}
console.log(o)
console.log('Item: ' + o)
输出:
对象{a=1, b=2} //非常好的可读输出:) Item: [object object] //不知道里面有什么:(
当前回答
var o = {a:1, b:2};
o.toString=function(){
return 'a='+this.a+', b='+this.b;
};
console.log(o);
console.log('Item: ' + o);
因为Javascript v1.0可以在任何地方工作(甚至是IE) 这是一种本地方法,允许在调试和生产过程中对对象进行定制 https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/Object/toString
有用的例子
var Ship=function(n,x,y){
this.name = n;
this.x = x;
this.y = y;
};
Ship.prototype.toString=function(){
return '"'+this.name+'" located at: x:'+this.x+' y:'+this.y;
};
alert([new Ship('Star Destroyer', 50.001, 53.201),
new Ship('Millennium Falcon', 123.987, 287.543),
new Ship('TIE fighter', 83.060, 102.523)].join('\n'));//now they can battle!
//"Star Destroyer" located at: x:50.001 y:53.201
//"Millennium Falcon" located at: x:123.987 y:287.543
//"TIE fighter" located at: x:83.06 y:102.523
还有,作为奖励
function ISO8601Date(){
return this.getFullYear()+'-'+(this.getMonth()+1)+'-'+this.getDate();
}
var d=new Date();
d.toString=ISO8601Date;//demonstrates altering native object behaviour
alert(d);
//IE6 Fri Jul 29 04:21:26 UTC+1200 2016
//FF&GC Fri Jul 29 2016 04:21:26 GMT+1200 (New Zealand Standard Time)
//d.toString=ISO8601Date; 2016-7-29
其他回答
Stringify-object是yeoman团队制作的一个很好的NPM库:https://www.npmjs.com/package/stringify-object
npm install stringify-object
然后:
const stringifyObject = require('stringify-object');
stringifyObject(myCircularObject);
显然,只有当循环对象使用JSON.stringify()会失败时,它才有趣;
我正在寻找这个,并写了一个深度递归缩进:
function objToString(obj, ndeep) {
if(obj == null){ return String(obj); }
switch(typeof obj){
case "string": return '"'+obj+'"';
case "function": return obj.name || obj.toString();
case "object":
var indent = Array(ndeep||1).join('\t'), isArray = Array.isArray(obj);
return '{['[+isArray] + Object.keys(obj).map(function(key){
return '\n\t' + indent + key + ': ' + objToString(obj[key], (ndeep||1)+1);
}).join(',') + '\n' + indent + '}]'[+isArray];
default: return obj.toString();
}
}
使用方法:objToString({a: 1, b: {c: "test"}})
如果对象是一个jQuery对象,那么你应该使用:
obj.html()
而不是:
JSON.stringify(obj)
例子:
Var tr = $('tr') console.log('This does not work:') console.log (JSON.stringify (tr)) console.log('But this does:') console.log (tr.html ()) < script src = " https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js " > < /脚本> <表> < tr > < td > < / td > < td > b < / td > 表> < /
对于非嵌套对象:
Object.entries(o).map(x=>x.join(":")).join("\r\n")
如果你想要的只是一个字符串输出,那么这应该工作: