如何将JavaScript对象转换为字符串?
例子:
var o = {a:1, b:2}
console.log(o)
console.log('Item: ' + o)
输出:
对象{a=1, b=2} //非常好的可读输出:) Item: [object object] //不知道里面有什么:(
如何将JavaScript对象转换为字符串?
例子:
var o = {a:1, b:2}
console.log(o)
console.log('Item: ' + o)
输出:
对象{a=1, b=2} //非常好的可读输出:) Item: [object object] //不知道里面有什么:(
当前回答
1.
JSON.stringify(o);
Item: {"a":"1", "b":"2"}
2.
var o = {a:1, b:2};
var b=[]; Object.keys(o).forEach(function(k){b.push(k+":"+o[k]);});
b="{"+b.join(', ')+"}";
console.log('Item: ' + b);
项目:{a:1, b:2}
其他回答
如果你只关心字符串、对象和数组:
function objectToString (obj) {
var str = '';
var i=0;
for (var key in obj) {
if (obj.hasOwnProperty(key)) {
if(typeof obj[key] == 'object')
{
if(obj[key] instanceof Array)
{
str+= key + ' : [ ';
for(var j=0;j<obj[key].length;j++)
{
if(typeof obj[key][j]=='object') {
str += '{' + objectToString(obj[key][j]) + (j > 0 ? ',' : '') + '}';
}
else
{
str += '\'' + obj[key][j] + '\'' + (j > 0 ? ',' : ''); //non objects would be represented as strings
}
}
str+= ']' + (i > 0 ? ',' : '')
}
else
{
str += key + ' : { ' + objectToString(obj[key]) + '} ' + (i > 0 ? ',' : '');
}
}
else {
str +=key + ':\'' + obj[key] + '\'' + (i > 0 ? ',' : '');
}
i++;
}
}
return str;
}
/*
This function is as JSON.Stringify (but if you has not in your js-engine you can use this)
Params:
obj - your object
inc_ident - can be " " or "\t".
show_types - show types of object or not
ident - need for recoursion but you can not set this parameter.
*/
function getAsText(obj, inc_ident, show_types, ident) {
var res = "";
if (!ident)
ident = "";
if (typeof(obj) == "string") {
res += "\"" + obj + "\" ";
res += (show_types == true) ? "/* typeobj: " + typeof(obj) + "*/" : "";
} else if (typeof(obj) == "number" || typeof(obj) == "boolean") {
res += obj;
res += (show_types == true) ? "/* typeobj: " + typeof(obj) + "*/" : "";
} else if (obj instanceof Array) {
res += "[ ";
res += show_types ? "/* typeobj: " + typeof(obj) + "*/" : "";
res += "\r\n";
var new_ident = ident + inc_ident;
var arr = [];
for(var key in obj) {
arr.push(new_ident + getAsText(obj[key], inc_ident, show_types, new_ident));
}
res += arr.join(",\r\n") + "\r\n";
res += ident + "]";
} else {
var new_ident = ident + inc_ident;
res += "{ ";
res += (show_types == true) ? "/* typeobj: " + typeof(obj) + "*/" : "";
res += "\r\n";
var arr = [];
for(var key in obj) {
arr.push(new_ident + '"' + key + "\" : " + getAsText(obj[key], inc_ident, show_types, new_ident));
}
res += arr.join(",\r\n") + "\r\n";
res += ident + "}\r\n";
}
return res;
};
示例:
var obj = {
str : "hello",
arr : ["1", "2", "3", 4],
b : true,
vobj : {
str : "hello2"
}
}
var ForReading = 1, ForWriting = 2;
var fso = new ActiveXObject("Scripting.FileSystemObject")
f1 = fso.OpenTextFile("your_object1.txt", ForWriting, true)
f1.Write(getAsText(obj, "\t"));
f1.Close();
f2 = fso.OpenTextFile("your_object2.txt", ForWriting, true)
f2.Write(getAsText(obj, "\t", true));
f2.Close();
your_object1.txt:
{
"str" : "hello" ,
"arr" : [
"1" ,
"2" ,
"3" ,
4
],
"b" : true,
"vobj" : {
"str" : "hello2"
}
}
your_object2.txt:
{ /* typeobj: object*/
"str" : "hello" /* typeobj: string*/,
"arr" : [ /* typeobj: object*/
"1" /* typeobj: string*/,
"2" /* typeobj: string*/,
"3" /* typeobj: string*/,
4/* typeobj: number*/
],
"b" : true/* typeobj: boolean*/,
"vobj" : { /* typeobj: object*/
"str" : "hello2" /* typeobj: string*/
}
}
循环引用
通过使用下面的替换器,我们可以产生更少冗余的JSON -如果源对象包含对某个对象的多次引用,或者包含循环引用-那么我们通过特殊的路径字符串(类似于JSONPath)引用它-我们如下所示
let s = JSON.stringify(obj, refReplacer());
function refReplacer() { let m = new Map(), v= new Map(), init = null; return function(field, value) { let p= m.get(this) + (Array.isArray(this) ? `[${field}]` : '.' + field); let isComplex= value===Object(value) if (isComplex) m.set(value, p); let pp = v.get(value)||''; let path = p.replace(/undefined\.\.?/,''); let val = pp ? `#REF:${pp[0]=='[' ? '$':'$.'}${pp}` : value; !init ? (init=value) : (val===init ? val="#REF:$" : 0); if(!pp && isComplex) v.set(value, path); return val; } } // --------------- // TEST // --------------- // gen obj with duplicate references let a = { a1: 1, a2: 2 }; let b = { b1: 3, b2: "4" }; let obj = { o1: { o2: a }, b, a }; // duplicate reference a.a3 = [1,2,b]; // circular reference b.b3 = a; // circular reference let s = JSON.stringify(obj, refReplacer(), 4); console.log(s);
奖励:这里是这种序列化的逆函数
function parseRefJSON(json) { let objToPath = new Map(); let pathToObj = new Map(); let o = JSON.parse(json); let traverse = (parent, field) => { let obj = parent; let path = '#REF:$'; if (field !== undefined) { obj = parent[field]; path = objToPath.get(parent) + (Array.isArray(parent) ? `[${field}]` : `${field?'.'+field:''}`); } objToPath.set(obj, path); pathToObj.set(path, obj); let ref = pathToObj.get(obj); if (ref) parent[field] = ref; for (let f in obj) if (obj === Object(obj)) traverse(obj, f); } traverse(o); return o; } // ------------ // TEST // ------------ let s = `{ "o1": { "o2": { "a1": 1, "a2": 2, "a3": [ 1, 2, { "b1": 3, "b2": "4", "b3": "#REF:$.o1.o2" } ] } }, "b": "#REF:$.o1.o2.a3[2]", "a": "#REF:$.o1.o2" }`; console.log('Open Chrome console to see nested fields:'); let obj = parseRefJSON(s); console.log(obj);
如果你可以使用lodash,你可以这样做:
> var o = {a:1, b:2};
> '{' + _.map(o, (value, key) => key + ':' + value).join(', ') + '}'
'{a:1, b:2}'
使用lodash map()也可以遍历对象。 这将每个键/值条目映射到它的字符串表示形式:
> _.map(o, (value, key) => key + ':' + value)
[ 'a:1', 'b:2' ]
join()将数组条目放在一起。
如果你可以使用ES6模板字符串,这也是有效的:
> `{${_.map(o, (value, key) => `${key}:${value}`).join(', ')}}`
'{a:1, b:2}'
请注意,这不是递归通过对象:
> var o = {a:1, b:{c:2}}
> _.map(o, (value, key) => `${key}:${value}`)
[ 'a:1', 'b:[object Object]' ]
就像node的util.inspect()一样:
> util.inspect(o)
'{ a: 1, b: { c: 2 } }'
1.
JSON.stringify(o);
Item: {"a":"1", "b":"2"}
2.
var o = {a:1, b:2};
var b=[]; Object.keys(o).forEach(function(k){b.push(k+":"+o[k]);});
b="{"+b.join(', ')+"}";
console.log('Item: ' + b);
项目:{a:1, b:2}