我一直在阅读c++常见问题,对朋友声明很好奇。我个人从未使用过它,但我对探索这门语言很感兴趣。

使用friend的一个好例子是什么?


读了一些常见问题,我喜欢<< >>操作符重载和添加作为这些类的朋友的想法。然而,我不确定这如何不会破坏封装。什么时候这些异常可以保持在OOP的严格范围内?


当前回答

对于操作符<<和操作符>>,没有很好的理由让这些操作符成为朋友。它们确实不应该是成员函数,但它们也不需要是朋友函数。

最好的方法是创建公共打印(ostream&)和读取(istream&)函数。然后,根据这些函数写出操作符<<和操作符>>。这提供了额外的好处,允许您将这些函数设置为虚拟函数,从而提供虚拟序列化。

其他回答

我只使用friend关键字来单元测试受保护的函数。有些人会说不应该测试受保护的功能。然而,在添加新功能时,我发现这个工具非常有用。

然而,我没有直接在类声明中使用关键字in,而是使用一个漂亮的模板-hack来实现这一点:

template<typename T>
class FriendIdentity {
public:
  typedef T me;
};

/**
 * A class to get access to protected stuff in unittests. Don't use
 * directly, use friendMe() instead.
 */
template<class ToFriend, typename ParentClass>
class Friender: public ParentClass
{
public:
  Friender() {}
  virtual ~Friender() {}
private:
// MSVC != GCC
#ifdef _MSC_VER
  friend ToFriend;
#else
  friend class FriendIdentity<ToFriend>::me;
#endif
};

/**
 * Gives access to protected variables/functions in unittests.
 * Usage: <code>friendMe(this, someprotectedobject).someProtectedMethod();</code>
 */
template<typename Tester, typename ParentClass>
Friender<Tester, ParentClass> & 
friendMe(Tester * me, ParentClass & instance)
{
    return (Friender<Tester, ParentClass> &)(instance);
}

这使我能够做到以下几点:

friendMe(this, someClassInstance).someProtectedFunction();

至少适用于GCC和MSVC。

当不同的类(不是从另一个类继承一个类)正在使用另一个类的私有或受保护成员时,可以使用友情。

友元函数的典型用例是 在访问私有或受保护的两个不同的类之间进行 两者的成员。

来自http://www.cplusplus.com/doc/tutorial/inheritance/。

在这个例子中,非成员方法访问类的私有成员。这个方法必须在这个类中声明为类的友元。

// friend functions
#include <iostream>
using namespace std;

class Rectangle {
    int width, height;
  public:
    Rectangle() {}
    Rectangle (int x, int y) : width(x), height(y) {}
    int area() {return width * height;}
    friend Rectangle duplicate (const Rectangle&);
};

Rectangle duplicate (const Rectangle& param)
{
  Rectangle res;
  res.width = param.width*2;
  res.height = param.height*2;
  return res;
}

int main () {
  Rectangle foo;
  Rectangle bar (2,3);
  foo = duplicate (bar);
  cout << foo.area() << '\n';
  return 0;
}

在做TDD的时候,我经常使用c++中的'friend'关键字。

朋友能知道我的一切吗?


更新:我从Bjarne Stroustrup网站上找到了这个关于“朋友”关键字的有价值的答案。

“好友”是一种授予访问权限的显式机制,就像会员资格一样。

c++的创建者说这并没有破坏任何封装原则,我将引用他的话:

“朋友”是否违反封装? 不。但事实并非如此。“好友”是一种授予访问权限的显式机制,就像会员资格一样。你不能(在符合标准的程序中)在不修改类源的情况下授予自己对类的访问权。

很明显…

In C++ "friend" keyword is useful in Operator overloading and Making Bridge. 1.) Friend keyword in operator overloading :Example for operator overloading is: Let say we have a class "Point" that has two float variable"x"(for x-coordinate) and "y"(for y-coordinate). Now we have to overload "<<"(extraction operator) such that if we call "cout << pointobj" then it will print x and y coordinate (where pointobj is an object of class Point). To do this we have two option: 1.Overload "operator <<()" function in "ostream" class. 2.Overload "operator<<()" function in "Point" class. Now First option is not good because if we need to overload again this operator for some different class then we have to again make change in "ostream" class. That's why second is best option. Now compiler can call "operator <<()" function:

   1.Using ostream object cout.As: cout.operator<<(Pointobj) (form ostream class).
2.Call without an object.As: operator<<(cout, Pointobj) (from Point class).

Beacause we have implemented overloading in Point class. So to call this function without an object we have to add"friend" keyword because we can call a friend function without an object. Now function declaration will be As: "friend ostream &operator<<(ostream &cout, Point &pointobj);" 2.) Friend keyword in making bridge : Suppose we have to make a function in which we have to access private member of two or more classes ( generally termed as "bridge" ) . How to do this: To access private member of a class it should be member of that class. Now to access private member of other class every class should declare that function as a friend function. For example : Suppose there are two class A and B. A function "funcBridge()" want to access private member of both classes. Then both class should declare "funcBridge()" as: friend return_type funcBridge(A &a_obj, B & b_obj);I think this would help to understand friend keyword.