1700/1/1之后的日期不需要导入的解决方案

def weekDay(year, month, day):
    offset = [0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334]
    week   = ['Sunday', 
              'Monday', 
              'Tuesday', 
              'Wednesday', 
              'Thursday',  
              'Friday', 
              'Saturday']
    afterFeb = 1
    if month > 2: afterFeb = 0
    aux = year - 1700 - afterFeb
    # dayOfWeek for 1700/1/1 = 5, Friday
    dayOfWeek  = 5
    # partial sum of days betweem current date and 1700/1/1
    dayOfWeek += (aux + afterFeb) * 365                  
    # leap year correction    
    dayOfWeek += aux / 4 - aux / 100 + (aux + 100) / 400     
    # sum monthly and day offsets
    dayOfWeek += offset[month - 1] + (day - 1)               
    dayOfWeek %= 7
    return dayOfWeek, week[dayOfWeek]

print weekDay(2013, 6, 15) == (6, 'Saturday')
print weekDay(1969, 7, 20) == (0, 'Sunday')
print weekDay(1945, 4, 30) == (1, 'Monday')
print weekDay(1900, 1, 1)  == (1, 'Monday')
print weekDay(1789, 7, 14) == (2, 'Tuesday')

如果日期是datetime对象，这是一个解决方案。

import datetime
def dow(date):
    days=["Monday","Tuesday","Wednesday","Thursday","Friday","Saturday","Sunday"]
    dayNumber=date.weekday()
    print days[dayNumber]

使用以下代码：

import pandas as pd
from datetime import datetime
print(pd.DatetimeIndex(df['give_date']).day)

以下是如何将小端字符串日期列表转换为datetime：

import datetime, time
ls = ['31/1/2007', '14/2/2017']
for d in ls:    
    dt = datetime.datetime.strptime(d, "%d/%m/%Y")
    print(dt)
    print(dt.strftime("%A"))

在MATLAB中，高斯方法

day_name={'Sun','Mon','Tue','Wed','Thu','Fri','Sat'}
month_offset=[0 3 3 6 1 4 6 2 5 0 3 5];  % common year

% input date
y1=2022
m1=11
d1=22

% is y1 leap
if mod(y1,4)==0 && mod(y1,100)==0 && mod(y1,400)==0
    month_offset=[0 3 4 0 2 5 0 3 6 1 4 6];  % offset for leap year
end

% Gregorian calendar
weekday_gregor=rem( d1+month_offset(m1) + 5*rem(y1-1,4) +  4*rem(y1-1,100) + 6*rem(y1-1,400),7)

day_name{weekday_gregor+1}

0:星期日1:星期一。。6:星期六

如果您希望生成一个包含日期范围（Date）的列，并生成一个指向第一个日期并指定周日（Week Day）的列（我将使用从2008-01-01到2020-02-01的日期）：

import pandas as pd
dr = pd.date_range(start='2008-01-01', end='2020-02-1')
df = pd.DataFrame()
df['Date'] = dr
df['Week Day'] = pd.to_datetime(dr).weekday

输出如下：

工作日从0到6不等，其中0对应于周一，6对应于周日。