如果给出格式为YYYYMMDD的出生日期,如何以年计算年龄?是否可以使用Date()函数?

我正在寻找一个比我现在使用的更好的解决方案:

Var dob = '19800810'; var年=数字(dob.)substr (0, 4)); var月=数字(dob.)Substr (4, 2)) - 1; var day =数字(dob.)2) substr(6日); var today = new Date(); var age = today.getFullYear() -年份; if (today.getMonth() < month || (today.getMonth() == month && today.getDate() < day)) { 年龄——; } 警报(年龄);


当前回答

从naveen和原始OP的帖子中采用,我最终得到了一个可重用的方法存根,它接受字符串和/或JS Date对象。

我将其命名为gregorianAge(),因为这个计算准确地给出了我们如何使用公历表示年龄。即,如果月和日在出生年份的月和日之前,则不计算结束年。

/** * Calculates human age in years given a birth day. Optionally ageAtDate * can be provided to calculate age at a specific date * * @param string|Date Object birthDate * @param string|Date Object ageAtDate optional * @returns integer Age between birthday and a given date or today */ function gregorianAge(birthDate, ageAtDate) { // convert birthDate to date object if already not if (Object.prototype.toString.call(birthDate) !== '[object Date]') birthDate = new Date(birthDate); // use today's date if ageAtDate is not provided if (typeof ageAtDate == "undefined") ageAtDate = new Date(); // convert ageAtDate to date object if already not else if (Object.prototype.toString.call(ageAtDate) !== '[object Date]') ageAtDate = new Date(ageAtDate); // if conversion to date object fails return null if (ageAtDate == null || birthDate == null) return null; var _m = ageAtDate.getMonth() - birthDate.getMonth(); // answer: ageAt year minus birth year less one (1) if month and day of // ageAt year is before month and day of birth year return (ageAtDate.getFullYear()) - birthDate.getFullYear() - ((_m < 0 || (_m === 0 && ageAtDate.getDate() < birthDate.getDate())) ? 1 : 0) } // Below is for the attached snippet function showAge() { $('#age').text(gregorianAge($('#dob').val())) } $(function() { $(".datepicker").datepicker(); showAge(); }); <link rel="stylesheet" href="//code.jquery.com/ui/1.11.4/themes/smoothness/jquery-ui.css"> <script src="//code.jquery.com/jquery-1.10.2.js"></script> <script src="//code.jquery.com/ui/1.11.4/jquery-ui.js"></script> DOB: <input name="dob" value="12/31/1970" id="dob" class="datepicker" onChange="showAge()" /> AGE: <span id="age"><span>

其他回答

我知道这是一个非常古老的线程,但我想把这个实现放在我写的寻找年龄,我相信这是更准确的。

var getAge = function(year,month,date){
    var today = new Date();
    var dob = new Date();
    dob.setFullYear(year);
    dob.setMonth(month-1);
    dob.setDate(date);
    var timeDiff = today.valueOf() - dob.valueOf();
    var milliInDay = 24*60*60*1000;
    var noOfDays = timeDiff / milliInDay;
    var daysInYear = 365.242;
    return  ( noOfDays / daysInYear ) ;
}

当然,你可以调整它以适应其他获取参数的格式。希望这有助于人们寻找更好的解决方案。

function age()
{
    var birthdate = $j('#birthDate').val(); // in   "mm/dd/yyyy" format
    var senddate = $j('#expireDate').val(); // in   "mm/dd/yyyy" format
    var x = birthdate.split("/");    
    var y = senddate.split("/");
    var bdays = x[1];
    var bmonths = x[0];
    var byear = x[2];
    //alert(bdays);
    var sdays = y[1];
    var smonths = y[0];
    var syear = y[2];
    //alert(sdays);

    if(sdays < bdays)
    {
        sdays = parseInt(sdays) + 30;
        smonths = parseInt(smonths) - 1;
        //alert(sdays);
        var fdays = sdays - bdays;
        //alert(fdays);
    }
    else{
        var fdays = sdays - bdays;
    }

    if(smonths < bmonths)
    {
        smonths = parseInt(smonths) + 12;
        syear = syear - 1;
        var fmonths = smonths - bmonths;
    }
    else
    {
        var fmonths = smonths - bmonths;
    }

    var fyear = syear - byear;
    document.getElementById('patientAge').value = fyear+' years '+fmonths+' months '+fdays+' days';
}

使用javascript从出生日期获取年龄(年,月和日)

函数calcularEdad(年,月和日)

function calcularEdad(fecha) {
        // Si la fecha es correcta, calculamos la edad

        if (typeof fecha != "string" && fecha && esNumero(fecha.getTime())) {
            fecha = formatDate(fecha, "yyyy-MM-dd");
        }

        var values = fecha.split("-");
        var dia = values[2];
        var mes = values[1];
        var ano = values[0];

        // cogemos los valores actuales
        var fecha_hoy = new Date();
        var ahora_ano = fecha_hoy.getYear();
        var ahora_mes = fecha_hoy.getMonth() + 1;
        var ahora_dia = fecha_hoy.getDate();

        // realizamos el calculo
        var edad = (ahora_ano + 1900) - ano;
        if (ahora_mes < mes) {
            edad--;
        }
        if ((mes == ahora_mes) && (ahora_dia < dia)) {
            edad--;
        }
        if (edad > 1900) {
            edad -= 1900;
        }

        // calculamos los meses
        var meses = 0;

        if (ahora_mes > mes && dia > ahora_dia)
            meses = ahora_mes - mes - 1;
        else if (ahora_mes > mes)
            meses = ahora_mes - mes
        if (ahora_mes < mes && dia < ahora_dia)
            meses = 12 - (mes - ahora_mes);
        else if (ahora_mes < mes)
            meses = 12 - (mes - ahora_mes + 1);
        if (ahora_mes == mes && dia > ahora_dia)
            meses = 11;

        // calculamos los dias
        var dias = 0;
        if (ahora_dia > dia)
            dias = ahora_dia - dia;
        if (ahora_dia < dia) {
            ultimoDiaMes = new Date(ahora_ano, ahora_mes - 1, 0);
            dias = ultimoDiaMes.getDate() - (dia - ahora_dia);
        }

        return edad + " años, " + meses + " meses y " + dias + " días";
    }

函数esNumero

function esNumero(strNumber) {
    if (strNumber == null) return false;
    if (strNumber == undefined) return false;
    if (typeof strNumber === "number" && !isNaN(strNumber)) return true;
    if (strNumber == "") return false;
    if (strNumber === "") return false;
    var psInt, psFloat;
    psInt = parseInt(strNumber);
    psFloat = parseFloat(strNumber);
    return !isNaN(strNumber) && !isNaN(psFloat);
}

momentjs:

/* The difference, in years, between NOW and 2012-05-07 */
moment().diff(moment('20120507', 'YYYYMMDD'), 'years')

我有点晚了,但我发现这是计算出生日期的最简单的方法。

希望这能有所帮助。

function init() { writeYears("myage", 0, Age()); } function Age() { var birthday = new Date(1997, 02, 01), //Year, month-1 , day. today = new Date(), one_year = 1000 * 60 * 60 * 24 * 365; return Math.floor((today.getTime() - birthday.getTime()) / one_year); } function writeYears(id, current, maximum) { document.getElementById(id).innerHTML = current; if (current < maximum) { setTimeout(function() { writeYears(id, ++current, maximum); }, Math.sin(current / maximum) * 200); } } init() <span id="myage"></span>