如果给出格式为YYYYMMDD的出生日期，如何以年计算年龄?是否可以使用Date()函数?
我正在寻找一个比我现在使用的更好的解决方案:
Var dob = '19800810'; var年=数字(dob.)substr (0, 4)); var月=数字(dob.)Substr (4, 2)) - 1; var day =数字(dob.)2) substr(6日); var today = new Date(); var age = today.getFullYear() -年份; if (today.getMonth() < month || (today.getMonth() == month && today.getDate() < day)) { 年龄——; ｝ 警报(年龄);
当前回答
我有点晚了，但我发现这是计算出生日期的最简单的方法。
希望这能有所帮助。
function init() { writeYears("myage", 0, Age()); } function Age() { var birthday = new Date(1997, 02, 01), //Year, month-1 , day. today = new Date(), one_year = 1000 * 60 * 60 * 24 * 365; return Math.floor((today.getTime() - birthday.getTime()) / one_year); } function writeYears(id, current, maximum) { document.getElementById(id).innerHTML = current; if (current < maximum) { setTimeout(function() { writeYears(id, ++current, maximum); }, Math.sin(current / maximum) * 200); } } init() <span id="myage"></span>
其他回答
moment.js还有一个可能的解决方案:
var moment = require('moment');
var startDate = new Date();
var endDate = new Date();
endDate.setDate(endDate.getFullYear() + 5); // Add 5 years to second date
console.log(moment.duration(endDate - startDate).years()); // This should returns 5
以下是计算年龄的简单方法:
//dob date dd/mm/yy
var d = 01/01/1990
//today
//date today string format
var today = new Date(); // i.e wed 04 may 2016 15:12:09 GMT
//todays year
var todayYear = today.getFullYear();
// today month
var todayMonth = today.getMonth();
//today date
var todayDate = today.getDate();
//dob
//dob parsed as date format
var dob = new Date(d);
// dob year
var dobYear = dob.getFullYear();
// dob month
var dobMonth = dob.getMonth();
//dob date
var dobDate = dob.getDate();
var yearsDiff = todayYear - dobYear ;
var age;
if ( todayMonth < dobMonth )
{
age = yearsDiff - 1;
}
else if ( todayMonth > dobMonth )
{
age = yearsDiff ;
}
else //if today month = dob month
{ if ( todayDate < dobDate )
{
age = yearsDiff - 1;
}
else
{
age = yearsDiff;
}
}
let dt = dob;
let age = '';
let bY = Number(moment(dt).format('YYYY'));
let bM = Number(moment(dt).format('MM'));
let bD = Number(moment(dt).format('DD'));
let tY = Number(moment().format('YYYY'));
let tM = Number(moment().format('MM'));
let tD = Number(moment().format('DD'));
age += (tY - bY) + ' Y ';
if (tM < bM) {
age += (tM - bM + 12) + ' M ';
tY = tY - 1;
} else {
age += (tM - bM) + ' M '
}
if (tD < bD) {
age += (tD - bD + 30) + ' D ';
tM = tM - 1;
} else {
age += (tD - bD) + ' D '
}
//AGE MONTH DAYS
console.log(age);
我在这里测试的所有答案(大约一半)都认为2000-02-29到2001-02-28是0年，而从2000-02-29到2001-03-01最有可能是1年，即1年零1天。这里有一个getYearDiff函数来修复这个问题。它只适用于d0 < d1:
function getYearDiff(d0, d1) {
d1 = d1 || new Date();
var m = d0.getMonth();
var years = d1.getFullYear() - d0.getFullYear();
d0.setFullYear(d0.getFullYear() + years);
if (d0.getMonth() != m) d0.setDate(0);
return d0 > d1? --years : years;
}
试试这个。
function getAge(dateString) {
var today = new Date();
var birthDate = new Date(dateString);
var age = today.getFullYear() - birthDate.getFullYear();
var m = today.getMonth() - birthDate.getMonth();
if (m < 0 || (m === 0 && today.getDate() < birthDate.getDate())) {
age--;
}
return age;
}
我相信你的代码中唯一看起来粗糙的是substr部分。
小提琴:http://jsfiddle.net/codeandcloud/n33RJ/
