我试图创建一个计算器,但我不能让它工作,因为我不知道如何获得用户输入。

如何在Java中获得用户输入?


当前回答

import java.util.Scanner;

public class userinput {
    public static void main(String[] args) {        
        Scanner input = new Scanner(System.in);

        System.out.print("Name : ");
        String name = input.next();
        System.out.print("Last Name : ");
        String lname = input.next();
        System.out.print("Age : ");
        byte age = input.nextByte();

        System.out.println(" " );
        System.out.println(" " );

        System.out.println("Firt Name: " + name);
        System.out.println("Last Name: " + lname);
        System.out.println("      Age: " + age);
    }
}

其他回答

您可以根据需求使用以下任何选项。

扫描仪类

import java.util.Scanner; 
//...
Scanner scan = new Scanner(System.in);
String s = scan.next();
int i = scan.nextInt();

BufferedReader和InputStreamReader类

import java.io.BufferedReader;
import java.io.InputStreamReader;
//...
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String s = br.readLine();
int i = Integer.parseInt(s);

DataInputStream类

import java.io.DataInputStream;
//...
DataInputStream dis = new DataInputStream(System.in);
int i = dis.readInt();

DataInputStream类中的readLine方法已弃用。要获得String值,您应该使用前面的BufferedReader解决方案


控制台类

import java.io.Console;
//...
Console console = System.console();
String s = console.readLine();
int i = Integer.parseInt(console.readLine());

显然,这种方法在某些ide中不能很好地工作。

然后,Add在main()旁边抛出IOException

DataInputStream input = new DataInputStream(System.in);
System.out.print("Enter your name");
String name = input.readLine();

您可以使用BufferedReader获取用户输入。

BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String accStr;  

System.out.println("Enter your Account number: ");
accStr = br.readLine();

它将在accStr中存储一个String值,因此您必须使用Integer.parseInt将其解析为int。

int accInt = Integer.parseInt(accStr);
Scanner input=new Scanner(System.in);
int integer=input.nextInt();
String string=input.next();
long longInteger=input.nextLong();
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        System.out.println("Welcome to the best program in the world! ");
        while (true) {
            System.out.print("Enter a query: ");
            Scanner scan = new Scanner(System.in);
            String s = scan.nextLine();
            if (s.equals("q")) {
                System.out.println("The program is ending now ....");
                break;
            } else  {
                System.out.println("The program is running...");
            }
        }
    }
}