这是另一种选择

打字稿:

function objectDefined <T>(obj: T): T {
  const acc: Partial<T> = {};
  for (const key in obj) {
    if (obj[key] !== undefined) acc[key] = obj[key];
  }
  return acc as T;
}

Javascript:

function objectDefined(obj) {
  const acc = {};
  for (const key in obj) {
    if (obj[key] !== undefined) acc[key] = obj[key];
  }
  return acc;
}

如果你想要4行纯ES7解决方案:

const clean = e => e instanceof Object ? Object.entries(e).reduce((o, [k, v]) => {
  if (typeof v === 'boolean' || v) o[k] = clean(v);
  return o;
}, e instanceof Array ? [] : {}) : e;

或者如果你喜欢更易读的版本:

function filterEmpty(obj, [key, val]) {
  if (typeof val === 'boolean' || val) {
    obj[key] = clean(val)
  };

  return obj;
}

function clean(entry) {
  if (entry instanceof Object) {
    const type = entry instanceof Array ? [] : {};
    const entries = Object.entries(entry);

    return entries.reduce(filterEmpty, type);
  }

  return entry;
}

这将保留布尔值，也将清理数组。它还通过返回一个清理过的副本来保存原始对象。

删除所有带有null和undefined的属性

让obj = { “id”:1、 “firstName”:空, “姓”:空, “地址”:未定义的, “角色”:“客户”, “照片”:“fb79fd5d - 06 - c9 - 4097 - 8 fdc - 6 - cebf73fab26 / fc8efe82-2af4-4c81-bde7-8d2f9dd7994a.jpg”, “位置”:空, “idNumber”:空, }; let result = Object.entries(obj).reduce((a，[k,v]) => (v == null ?A: (A [k]=v, A))， {}); console.log(结果)

如果有人需要欧文(和埃里克)答案的递归版本，这里是:

/**
 * Delete all null (or undefined) properties from an object.
 * Set 'recurse' to true if you also want to delete properties in nested objects.
 */
function delete_null_properties(test, recurse) {
    for (var i in test) {
        if (test[i] === null) {
            delete test[i];
        } else if (recurse && typeof test[i] === 'object') {
            delete_null_properties(test[i], recurse);
        }
    }
}

Lodash:

_.omitBy({a: 1, b: null}, (v) => !v)

来piggypack本的回答如何解决这个问题使用lodash的_。pickBy，你也可以在姐妹库中解决这个问题:Underscore.js的_.pick。

var obj = {name: 'John', age: null};

var compacted = _.pick(obj, function(value) {
  return value !== null && value !== undefined;
});

参见:JSFiddle示例